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図形の問題 解答編(OSC2012 Shimane LT資料)

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図形の問題 解答編(OSC2012 Shimane LT資料)

  1. 1. ∠ABCは何度? A 正方形 CB
  2. 2. ヒント A D 補助線を引いてみましょう CB E
  3. 3. ∠ABC=45° A D △ACD≡△CBEより AC=CB よって△ABCは二等辺三角形 ∠ACB=180°-∠ACD-∠BCE =180°-∠ACD-∠CAD =90° 二等辺三角形の底角は等しいので ∠ABC=∠BAC C ∴ ∠ABC=180°-∠BAC-∠ACD ∠ABC=180°-∠ABC-90° 2∠ABC=90° ∠ABC=45°B E
  4. 4. おしまい(^.^)/~~~

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