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Jan. 31, 2023•0 likes•1 view

Jan. 31, 2023•0 likes•1 view

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Q1 A sample containing 8.840 g of metal pellets was poured into a graduated cylinder initially containing 11.86 mL of water, causing the water level in the cylinder to rise to 18.53 mL. What is the density, in g/mL, of the metal? Q2 A sample containing 6.65 g of metal pellets was poured into a graduated cylinder initially containing 11.16 mL of water. Given the density of the material was 4.9 g/mL, to what level did the water in the cylinder rise? Solution 1) volume of metal = change in water level = 18.53 mL - 11.86 mL = 6.67 mL mass of metal = 8.840 g use: density = mass / volume = 8.840 g / 6.67 mL = 1.325 g/mL Answer: 1.325 g/mL 2) volume of meta = mass / density = 6.65 g / (4.9 g/mL) = 1.36 mL Now use: volume of metal = change in water level volume of metal = final level - initial level 1.36 = final level - 11.16 final level = 12.52 mL Answer: 12.52 mL .

- 1. Q1 A sample containing 8.840 g of metal pellets was poured into a graduated cylinder initially containing 11.86 mL of water, causing the water level in the cylinder to rise to 18.53 mL. What is the density, in g/mL, of the metal? Q2 A sample containing 6.65 g of metal pellets was poured into a graduated cylinder initially containing 11.16 mL of water. Given the density of the material was 4.9 g/mL, to what level did the water in the cylinder rise? Solution 1) volume of metal = change in water level = 18.53 mL - 11.86 mL = 6.67 mL mass of metal = 8.840 g use: density = mass / volume = 8.840 g / 6.67 mL = 1.325 g/mL Answer: 1.325 g/mL 2) volume of meta = mass / density = 6.65 g / (4.9 g/mL)
- 2. = 1.36 mL Now use: volume of metal = change in water level volume of metal = final level - initial level 1.36 = final level - 11.16 final level = 12.52 mL Answer: 12.52 mL