Cuatro Amigos Presentation

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Cuatro Amigos Presentation

  1. 1. Cuatro amigos!By Janice, Pei Yu and KinseyFriday, 24 May, 13
  2. 2. ProblemFriday, 24 May, 13
  3. 3. SOLVEJ=5,10,15A=2M==>M<10(J=5)C=A/3 ==>A=12,18M>J==>J=5:M>5J<C ==>5<CMcannotbeover10.Aisanevennumberabove10.Factssofar:J=5A=12,18C=4,6-------------------------C>5C=66x2=12A=1818÷2=9M=9Friday, 24 May, 13
  4. 4. AnswersJuan’snumberis5Carlos’numberis6Maria’snumberis9Anna’snumberis18Friday, 24 May, 13

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