Equilibrium Temperature of the Earth
Electromagnetic Spectrum
Spectrum Graph of intensity versus wavelength or frequency Intensity Energy per unit area per unit time Unit of intensity ...
 
Spectrum of sunlight striking the atmosphere and surface of the  Earth
The fraction of light reflected from the surface of the Earth is called the  albedo  of the Earth
Simple Calculation to Determine the Equilibrium Temperature of the Earth <ul><li>The intensity from the sun that reaches t...
The sunlight strikes the earth on just one side as shown. Thus the total power being absorbed, Pabs, on the earth is Iabs ...
The amount of power being radiated away, P rad , is P rad  = I rad  (4  R 2 ), where I rad  is the intensity being emitte...
Dividing through by   R 2  yields I rad  = I abs /4.  The Stefan-Boltzmann law for a blackbody says I rad  =   T 4 , whe...
Substituting yields  T 4  = I abs /4 = 959 W/m 2 /4 = 240 W/m 2 Or T = 255 K = -18 o C
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Equilibrium Temperature Of The Earth

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This powerpoint shows a simple calculation for the equilibrium temperature of the Earth assuming there are no greenhouse gases present.

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Equilibrium Temperature Of The Earth

  1. 1. Equilibrium Temperature of the Earth
  2. 2. Electromagnetic Spectrum
  3. 3. Spectrum Graph of intensity versus wavelength or frequency Intensity Energy per unit area per unit time Unit of intensity is
  4. 5. Spectrum of sunlight striking the atmosphere and surface of the Earth
  5. 6. The fraction of light reflected from the surface of the Earth is called the albedo of the Earth
  6. 7. Simple Calculation to Determine the Equilibrium Temperature of the Earth <ul><li>The intensity from the sun that reaches the outer atmosphere of the earth is called the solar constant. </li></ul><ul><li>The solar constant is equal to 1.37 kW/m 2 . </li></ul><ul><li>The albedo, a, of the earth is usually taken to be 0.3 which means that 30% of the sunlight is reflected. </li></ul><ul><li>Thus the intensity, Iabs, absorbed by the earth is </li></ul><ul><li>Iabs = (1-a)1.37 = 0.7x1.37 = 0.959 kW/m 2. </li></ul>
  7. 8. The sunlight strikes the earth on just one side as shown. Thus the total power being absorbed, Pabs, on the earth is Iabs times the area of a circle whose radius is the radius of the earth, Pabs = Iabs(  R 2 ), where R is the radius of the earth.
  8. 9. The amount of power being radiated away, P rad , is P rad = I rad (4  R 2 ), where I rad is the intensity being emitted in units of kW/m 2 . Since there is thermal equilibrium, P abs = P rad or I abs (  R 2 ) = I rad (4  R 2 ).
  9. 10. Dividing through by  R 2 yields I rad = I abs /4. The Stefan-Boltzmann law for a blackbody says I rad =  T 4 , where T is the temperature of the blackbody and  is the Stefan-Boltzmann constant (  = 5.67x10 -8 W/m 2. K 4 ).
  10. 11. Substituting yields  T 4 = I abs /4 = 959 W/m 2 /4 = 240 W/m 2 Or T = 255 K = -18 o C

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