This document provides information on various topics related to chemical reaction engineering: - It discusses types of reactors, how materials behave within reactors, and how to process and interpret data from chemical reactors. - It explains the concepts of reversible and irreversible reactions, and the three ways a species may lose its chemical identity: decomposition, combination, and isomerization. - Rate of reaction is discussed, including how it can be expressed as the rate of disappearance of reactants or formation of products. - Other topics covered include mass/energy balances, Laplace transforms, psychrometric charts, pump curves, and pipe friction tables.

1. Chemical Reaction
Engineering

2. TypesOfReactorsAndDifferences

3. • This course is concerned with the rate
at which chemical reactions take place,
together with the mechanism and rate
limiting steps that control the reaction
process.
• The sizing of chemical reactors to
achieve production goals is an important
segment.
• How materials behave within reactors,
both chemically and physically, is
significant, as is how the data from
chemical reactors should be recorded,
processed, and interpreted.

4. CSTR
• Types Of Reactions
1. Reversible 2.Irreversible
• Chemical Reaction
• We say that a chemical reaction has
taken place when a detectable number of
molecules of one or more species have
lost their identity and assumed a new
form by a change in the kind or number
of atoms in the compound and/or by a
change in structure or configuration of
these atoms.
• Note: change in configuration means new
things.

5. • There are three basic ways a species may
lose its chemical identity.
1. Decomposition
2. Combination
3. Isomerization
• The rate at which a given chemical
reaction proceeds can be expressed in
several ways. It can be expressed either
as the rate of disappearance of
reactants or the rate of formation of
products.

6. • Rate of reaction for homo
the number of moles of chloral reacting
(disappearing) per unit time per unit
volume (mole/dm^3.s).
• For hetero (liquid/solid)
the number of moles of A reacted per unit
time per unit mass of catalyst (mole/s.g
catalyst).
• The chemical reaction rate is an
intensive quantity and depends on
temperature and concentration.

8. Mass/Energy Balances

10. As define by equation 4.1 will
yield a set of differential
equations with the
fundamental quantities as
dependent variables and time
as an independent variable.
The solution of the differential
equation will determine how
the fundamental quantities or
equivalently the state
variables change with i.e.
determine the dynamic
behavior of the process.
If the state variables do not
change with time we say the
process is a steady state
process. In this case the rate
of accumulation of the
fundamental quantity ‘S’ per
unit of time is zero and the
resulting balances yield
algebraic equations.

13. Solution
On Next
Pages

23. LaplaceTransform
CheatSheet

24. LaplaceTransform
CheatSheet

25. Laplace Transform
Cheat Sheet

27. Designing

28. DESIGNOFREACTORS

29. DESIGNOFREACTORS
?

30. DESIGNOFREACTORS
Answer To The
Question On
Previous Page

45. Know Your Graphs

46. KTypeThermocoupleConversion
Table

47. • If you want to measure a temperature
against mV obtained from the
thermocouple you can use this table.
Lets say you have a reading 3.8. You
look for It in the table and if not
found you interpolate amongst two pts.
Now the temperature you’re reading it
against, take and add in the reference
temperature. For example 30 is your
reference temperature the your final
answer would be 120.
90 + reference
temp.

48. .005kg/kg
.0175kg/kg
.029kg/kg
.0321kg/kg
Wet Bulb
Temperature
Dry Bulb
Temperature
Psychrometric
Chart

49. • This is a psychrometric chart used
to calculate humidity in kg/kg from
a dry and wet bulb temperatures.
Also gives us humid heat and volume
in m.^3/kg.

50. .043
350
.0065
We use these humidity
values to get enthalpy

51. .043
350
.0065
PsychrometricChart m1h1 +m2h2 = mh where (m=m1+m2)
300

52. • In problem 13.5 from (Chemical
Engineering Volume 1, Sixth Edition
Fluid Flow, Heat Transfer and Mass
Transfer)...
• We use this chart to solve it but
we first calculate humidity from
chart 13.4

53. Imp. Dia.
90
1000
60
800
15
Efficiency (83)
PUMPCURVES

54. • These are called the pump curves
and give us information about the
following characteristics of the
pump.
1.Pump head
2.Pump efficiency
3.Pump power
4.Pump NPSHR

56. • Above is what we call pipe friction
tables, basically we get the values of
velocity, velocity head and head loss
per 100 feet of pipe against a specific
flow rate in gallons per minute.
• Note: for head loss you must calculate
head loss for the feet of pipe YOU HAVE.
For example for 50 feet of pipe the head
loss against 7 GPM of flow will be 24
cause (48.8/100*50=24 feet).
100 feet of pipe
48.8 feet of head loss We have 50 feet of pipe
=24 feet

57. Product
Name
1.9
Pump Curves
This Means that at flow
of 2.7 m^3/hour in the
product 7 we get a pump
head of 1.9 meters.