Upcoming SlideShare
×

# Day 40 Ppt Batfink Momentum

473 views

Published on

Published in: Education, Technology, Business
0 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
Your message goes here
• Be the first to comment

• Be the first to like this

Views
Total views
473
On SlideShare
0
From Embeds
0
Number of Embeds
2
Actions
Shares
0
3
0
Likes
0
Embeds 0
No embeds

No notes for slide

### Day 40 Ppt Batfink Momentum

1. 1. the Short circuit case<br />
2. 2. Rules of This Activity<br />#1 All students must perform all of the work of the activity in their science journals even though you are working in your lab group.<br />#2 When you are sure of your answer, transfer the information onto individual mini whiteboards.<br />#3 The whiteboard work is to remain on the white board until it is approved. <br />
3. 3. Stating the Problem<br />The mad scientist, Hugo A-go-go has developed a way to disrupt the electrical service to Chicago.<br />The mass of the Eastbound (traveling to your right) CTA is 40,000 kg while the mass of the Westbound CTA is 30,000kg.<br />The Eastbound transit is traveling at 20 m/s and the Westbound transit is traveling at 25 m/s.<br />There are two separate, stationary cars also on the same track. They are 10,000 kg each. <br />
4. 4. Working the Problem<br />What is the eastbound train’s momentum?<br />
5. 5. What is the eastbound train’s momentum?<br />P = mv<br /> Known Want<br />m = 40,000 kg P (momentum)<br /> v = 20 m/s<br />P = mv<br />P = (40,000 kg )(20 m/s) <br />P = 800,000 (kg)( m/s) <br />
6. 6. Working the Problem<br />Draw a momentum vector diagram of the eastbound train.<br />
7. 7. Draw the Eastbound Train Momentum Vector Diagram<br />N y <br />W E<br /> S<br /> x<br /> 800,000 (kg)( m/s)<br />
8. 8. Working the Problem<br />What is the westbound train’s momentum?<br />
9. 9. What is the westbound train’s momentum?<br />P = mv<br /> Known Want<br />m = 30,000 kg P (momentum)<br /> v = 25 m/s<br />P = mv<br />P = (30,000 kg )(25 m/s) <br />P = 750,000 (kg)( m/s) <br />
10. 10. Working the Problem<br />Draw a momentum vector diagram of the westbound train.<br />
11. 11. Draw the Westbound Train Momentum Vector Diagram<br /> y<br /> x<br /> 750,000 (kg)( m/s)<br />
12. 12. Working the Problem<br />What is the momentum of each of the stationary transits?<br />
13. 13. What is the momentum of each of the stationary transits?<br />P = mv<br /> Known Want<br />m = 10,000 kg P (momentum)<br /> v = 0 m/s<br />P = mv<br />P = (10,000 kg )(0 m/s) <br />P = 0 (kg)( m/s) <br />
14. 14. Working the Problem<br />The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just before the collision.<br />
15. 15. Draw the Momentum Vector Diagram before the collision.<br /> y<br /> x<br /> 800,000 (kg)( m/s)<br />
16. 16. Working the Problem<br />The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just after the collision.<br />
17. 17. Net Momentum a collision= Net Momentum p collision<br /> y<br />800,000 (kg)( m/s)x<br />
18. 18. Working the Problem<br />The Eastbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?<br />
19. 19. Velocity after the Collision<br />Net Momentum before = Net Momentum after<br />Known Want<br />me = 40,000 kg P before<br />ve = 20 m/s v after<br />ms = 10,000 kg<br />vs = 0 m/s<br />Pnet = (mv)net<br />P = me ve + msvs<br />P = (40,000 kg )(20 m/s) + (10,000 kg )(0 m/s) <br />P = 800,000 (kg)( m/s) <br /> v = P/mv = 800,000 (kg)( m/s) / (40,000 kg ) + (10,000 kg )<br />v = 16 m/s E<br />
20. 20. Working the Problem<br />The Westbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?<br />
21. 21. Velocity after the Collision<br />Net Momentum before = Net Momentum after<br /> Known Want<br />mw = 30,000 kg P before<br />vw = 25m/s v after<br />ms = 10,000 kg<br />vs = 0 m/s<br />Pnet = (mv)net<br />P = mw vw + msvs<br />P = (30,000 kg )(25 m/s) + (10,000 kg )(0 m/s) <br />P = 750,000 (kg)( m/s) <br /> v = P/m<br />v = 750,000 (kg)( m/s) / (30,000 kg ) + (10,000 kg )<br />v = 18.75 m/s W<br />
22. 22. Working the Problem<br />The Westbound train, after the initial impact with the stationary transit collides with the Eastbound train also after its initial impact with one of the stationary transits. Calculate the velocity after the crash between the two trains if they stuck together. <br />
23. 23. Calculate the velocity after the crash between the two trains<br />Net Momentum before = Net Momentum after<br /> Known Want<br />Pw = 750,000 (kg)( m/s) Pnet before<br />Pe = -800,000 (kg)( m/s) v after<br />Pnet = Pe- Pw<br />Pnet = 800,000 (kg)( m/s) - 750,000 (kg)( m/s) <br />Pnet = 50,000 (kg)( m/s) <br /> v = P/m<br />v = 50,000 (kg)( m/s) / (40,000 kg ) + (50,000 kg )<br />v = .56 m/s E<br />
24. 24. Stating the Problem<br />The Battalac, which has a mass of 1500 kg is occupied by batfink, 50 kg, and Karate, 150kg and is traveling at 50 m/s when it is forced off the road anddown a 50 meter embankment. <br />
25. 25. Working the Problem<br />Calculate the vertical velocity of the Battalac just before it strikes the ground.<br />
26. 26. Find the vfy<br /> Known Want<br />mB= 1,500 kg v<br />vohB= 50 m/s<br />mb= 50 kg<br />mk= 150 kg<br /> vf2 = vo2 + 2a∆y<br /> vf2= 0 m/s + 2(9.8 m/s2)(50m)<br /> v = 31.3 m/s<br />
27. 27. Working the Problem<br />Calculate the magnitude of the velocity of the Battalac at impact with the ground.<br />
28. 28. Calculate the magnitude of the velocity of the Battalac<br /> y<br />50 m/s<br /> 31.3 m/s x<br />a2 + b2 = c2<br />502+ 31.32= 58.99 m/s<br />or<br />TAN -1= 31.3/50<br /> = 32.05*<br />Vf = Vx/COS 32.05*<br /> = 58.99 m/s<br />or<br />Vf = Vy/SIN 32.05*<br /> = 58.98 m/s<br />
29. 29. Working the Problem<br />Calculate the momentum of the Battalac at the moment of first impact with the ground.<br />
30. 30. The momentum of the Battalac at impact with the ground.<br />Known Want<br />mB = 1,500 kg P<br />vfB= 58.99 m/s<br />mb = 50 kg<br />mk = 150 kg<br /> P = mv<br /> P = (1700 kg)(58.99 m/s)<br /> P = 100,283 (kg)(m/s)<br />
31. 31. I’ll Bounce Back and be Okay!<br />