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1. 1. Solusi Solusi OSN Matematika 2014 Part 3 f (x) = 2 2 + 4x maka: f 1006 2014 = 2 2 + 4 1006 2014 f 1008 2014 = 2 2 + 4 1008 2014 Edy Wihardjo Soal Solusi Olimpiade Matematika 6 Mei 2014 1 / 4
2. 2. Solusi f 1006 2014 + f 1008 2014 = 2 2 + 4 1006 2014 + 2 2 + 4 1008 2014 = 2 2 + 4 1008 2014 + 2 2 + 4 1006 2014 2 + 4 1006 2014 2 + 4 1008 2014 = 4 + 2 4 1008 2014 + 4 + 2 4 1006 2014 4 + 2 4 1008 2014 + 2 4 1006 2014 + 4 1006 2014 4 1008 2014 Edy Wihardjo Soal Solusi Olimpiade Matematika 6 Mei 2014 2 / 4
3. 3. Solusi f 1006 2014 + f 1008 2014 = 8 + 2 4 1008 2014 + 2 4 1006 2014 4 + 2 4 1008 2014 + 2 4 1006 2014 + 4( 1006 2014+1008 2014 ) = 8 + 2 4 1008 2014 + 2 4 1006 2014 4 + 2 4 1008 2014 + 2 4 1006 2014 + 41 = 8 + 2 4 1008 2014 + 2 4 1006 2014 8 + 2 4 1008 2014 + 2 4 1006 2014 = 1 Edy Wihardjo Soal Solusi Olimpiade Matematika 6 Mei 2014 3 / 4
4. 4. Solusi f 1006 2014 + f 1008 2014 = 1 Edy Wihardjo Soal Solusi Olimpiade Matematika 6 Mei 2014 4 / 4
• #### edyjo1

Oct. 14, 2014

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