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# Module 4 topic 1 2nd

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Even more Coordinate Planes - Midpoint - Relations and Functions

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### Module 4 topic 1 2nd

1. 1. More – Coordinate Plane, Midpoint, and Relations and Functions<br />Module 4 Topic 1 <br />
2. 2. Example 1<br />Remember that the quadrants are I, II, III, or IV.<br />Quadrant I = (positive x-value, positive y-value)<br />Quadrant II = (negative x-value, positive y-value)<br />Quadrant III = (negative x-value, negative y-value)<br />Quadrant IV = (positive x-value, negative y-value) <br />
3. 3. Example 2<br />Similar Problem: Find the coordinates of the midpoint of M(-3, 0) and N(-7, -5).<br />Midpoint is the average of the x-values and the average of the y-values.<br />Midpoint = (x2 + x1) ÷ 2 , (y2 + y1) ÷ 2<br />Midpoint = (-7 + -3) ÷ 2 , (-5 + 0) ÷ 2<br />Midpoint = -10 ÷ 2 , -5 ÷ 2<br />Midpoint = -5, -2.5 so we write it as an ordered pair (-5, -2.5) <br />
4. 4. Example 3<br />Similar Problem: Use the following relation to answer questions 7 - 9.<br />{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}<br />Is the relation a function?<br />Yes - because the x-values do not repeat! <br />
5. 5. Example 4<br />Similar Problem: Use the following relation to answer questions 7 - 9.<br />{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}<br />State the domain of the relation.<br />Domain = all x-values of the relation<br />2, 7, -5, -2, 0 but let's put these in order so we have<br />-5, -2, 0, 2, 7 <br />
6. 6. Example 5<br />Similar Problem: Use the following relation to answer questions 7 - 9.<br />{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}<br />State the range of the relation.<br />Range = all y-values of the relation<br />4, 7, 4, -8, 0 but let's put these in order so we have<br />-8, 0, 4, 4, 7 and let's not repeat any so we have -8, 0 , 4, 7 <br />
7. 7. Example 6<br />Similar Problem: If f(x) = 3x + 6, find f(-4).<br />Plug in -4 for x in the function 3x + 6<br />3(-4) + 6<br />-12 + 6<br />-6 <br />