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# Stats survey project

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### Stats survey project

1. 1. AP Statistics Survey Project<br />Desiree Acevedo, Frank Palomarez, Paul Ortiz<br />Mr. Eastvedt <br />Period 4<br />June 4, 2011<br />
2. 2. Survey Questions<br />Q1 - What grade are you in?<br />Q2 - How old are you?<br />Q3 - Are you male or female?<br />Q4 - How many siblings do you have?<br />Q5 - How many people live in your house?<br />Q6 - How many days of the week do you typically get homework?<br />Q7 - How many pairs of jeans do you own?<br />
3. 3. Questions continued …. <br />Q8 - Which do you prefer to watch: College Football or Professional Football<br />Q9 - What type of phone do you prefer: Touch screen or Full Keyboard<br />Q10 - Which do you prefer: Fast Food or Home-made Food<br />Q11 - Would you rather play videogames or physical sports?<br />
4. 4. Confidence Intervals for Means<br />Question 1: Grade level of participants<br /> x= 9.93 s= 1.095 n= 84 df= 83 <br /> 9.93 ± (T*)×(1.095/√84) <br />= (9.70, 10.16)<br />This confidence interval means that we are 95% confident that the true mean grade level of survey participants is between 9.70 and 10.16<br />
5. 5. Confidence Intervals for Means<br />Question 2: Age of participants<br />x= 15.27 s= 1.19 n= 84 df= 83<br /> 15.27 ± (T*)×(1.19/√84)<br />= (15.02, 15.53)<br />This confidence interval means that we are 95% confident that the true mean age of survey participants is between 15.02 and 15.53<br />
6. 6. Confidence Intervals for Means<br />Question 4: Number of siblings participants have<br />x= 2.63 s= 1.63 n= 84 df= 83<br /> 2.63 ± (T*)×(1.63/√84)<br />= (2.28, 2.98)<br />This confidence interval means that we are 95% confident that the true mean of number siblings of survey participants is between 2.28 and 2.98<br />
7. 7. Confidence Intervals for Means<br />Question 5: Number of people in participant’s household<br />x= 5.71 s= 2.39 n= 84 df= 83<br /> 5.71 ± (T*)×(2.39/√84)<br />= (5.20, 6.23)<br />This confidence interval means that we are 95% confident that the true mean of people in the household of survey participants is between 5.20 and 6.23<br />
8. 8. Confidence Intervals for Means<br />Question 6: Day of week participants typically receive homework<br />x= 4.44 s= 1.13 n= 73 df= 72<br /> 4.44 ± (T*)×(1.13/√73)<br />= (4.17, 4.70)<br />This confidence interval means that we are 95% confident that the true mean of days per week survey participants receive homework is between<br />
9. 9. Confidence Intervals for Means<br />Question 7: Pairs of jeans participants own<br />x= 10.91 s= 12.87 n= 67 df= 66<br /> 10.91 ± (T*)×(12.87/√67)<br />= (7.77, 14.05)<br />This confidence interval means that we are 95% confident that the true mean age of survey participants is between 7.77 and 14.05<br />
10. 10. Confidence Intervals for Proportions<br />Question 3: Gender (p=female q=male)<br /> p= .548 q= .452 z*= 1.960 n= 84<br /> .548 ± 1.960√((.548×.452)/84) <br />= (.442, .654)<br />This means that we are 95% confident that the true proportion of affirmative participants (females) is between .442 and .654<br />
11. 11. Confidence Intervals for Proportions<br />Question 8: Watching NFL vs. NCAA Football<br /> (p = prefer NFL ; q = prefer NCAA)<br /> p= .868 q= .132 z*= 1.960 n= 76<br /> .868 ± 1.960√((.868×.132)/76) <br />= (.792, .944)<br />This means that we are 95% confident that the true proportion of affirmative participants (prefer watching NFL) is between .792 and .944<br />
12. 12. Confidence Intervals for Proportions<br />Question 9: Touch screen vs. Full Keyboard<br />(p= Full keyboard q= Touch screen)<br />p= .561 q= .439 Z*= 1.960 n= 82<br /> .561 ± 1.960√((.561×.439)/82)<br />= (.454, .668)<br />This means that we are 95% confident that the true proportion of affirmative participants (prefer a full keyboard cell phone) is between .454 and .668<br />
13. 13. Confidence Intervals for Proportions<br />Question 10: Fast food vs. Home-made <br />(p= Fast Food q= Home-made)<br /> p= .296 q= .701 Z*= 1.960 n= 81<br /> .296 ± 1.960√((.296×.701)/81)<br />= (.197, .396)<br />This means that we are 95% confident that the true proportion of affirmative participants (prefer fast food) is between .197 and .396<br />
14. 14. Confidence Intervals for Proportions<br />Question 11: Videogames vs. Physical sports<br />(p= Videogames q= Sports)<br />p= .266 q= .742 Z*= 1.960 n= 79<br /> .266 ± 1.960√((.266×.742)/79)<br />= (.168, .364)<br />This means that we are 95% confident that the true proportion of affirmative participants (prefer playing videogames) is between .168 and .364<br />
15. 15. Hypothesis Test: Question 6<br />How many days of the week do you typically get homework?<br />“ … researchers say that American students have just the right amount of homework.”<br />1. Ho: x=4.44 Ha: x≠4.44<br />2. Assumptions/Conditions:<br /> *Randomness-our sample was randomly selected<br /> *10%-our sample is less than 10% of the student population<br /> *Distribution-we can assume that the sample is randomly distributed<br />3. We will conduct a 1 sample T-test<br />4. p-value= .612<br />5. With such a high p-value we cannot reject the null hypothesis. This means that we can assume that the average student receives homework about four to five days a week.<br />
16. 16. Larger Study Links<br />Question 6- http://www.greatschools.org/students/homework-help/251-homework-is-too-much.gs<br />Question 7- http://www.fashionwindows.net/2009/06/american-own-7-pairs-of-denim-jeans-on-average/<br />Question 8- http://www.cbssports.com/collegefootball/story/11212751<br />
17. 17. Males vs. Females: Question 11<br />Would you rather play videogames or physical sports?<br />1. Ho: proportion of males > proportion of females (prefer playing video games)<br /> Ha: proportion of males < proportion of females (prefer playing video games)<br />2. Assumptions/Conditions:<br /> *Randomness-our sample was randomly selected<br /> *10%-our sample is less than 10% of the student population<br /> *Distribution-we can assume that the sample is randomly distributed<br />3. We will conduct a 2-proportion Z-test<br />4. females = .256 males = .286<br /> p-value = .322<br />5. With a high p-value we cannot reject the null hypothesis. This means that we can assume that the average teenage male prefers to play video games over physical sports than the average teenage female.<br />