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CPO ScienceFoundations of Physics                         Chapter 9   Unit 2, Chapter 6
Unit 2: Motion and Force in            One Dimension    Chapter 6: Forces and Equilibrium 6.1 Mass, Weight and Gravity 6...
Chapter 6 Objectives   Calculate the weight of an object using the strength of    gravity ( g) and mass.   Describe the ...
Chapter 6 Vocabulary Terms mas s                 n o rmal                c o m p r e s s io n w e ig h t             f...
6.1 Mass, Weight, and Gravity Mass is a measure of  matter. Mass is constant. Weight is a force. Weight is not constant.
6.1 Mass, Weight, and Gravity The weight of an object  depends on the strength  of gravity wherever the  object is. The ...
6.1 Weight                                Gravity (9.8 m/sec2)Weight force (N)   Fw = mg                             Mass ...
6.1 Free fall and weightlessness An e l e v a t o r is a c c e l e r a t in g  d o w n w a r d a t 9 .8 m /s e c 2 . T h...
6.1 Calculate weight          How much would a person           who weighs 490 N ( 110           lbs) on Earth weigh on  ...
6.1 Calculate force      A 10-kilogram ball is supported at       the end of a rope. H much force                        ...
6.1 Mass, Weight, and Gravity    Key Question:    W h a t is s p e e d a n d h o w is it     meas ured ?*Students read Sec...
6.2 Friction Friction results from relative motion  between objects. Frictional forces are forces that resist or  oppose...
6.2 Types of Friction Static friction Sliding friction Rolling friction
6.2 Types of Friction Air friction Viscous friction
6.2 Friction                                     Normal force (N)Friction force (N)   Ff = µ Fn                           ...
6.2 Calculate force of friction A 10 N force pushes down on a box that weighs 100 N. As the box is pushed horizontally, ...
6.2 Sliding Friction                                      Normal force (N)Friction force (N)   Ff = µ sFn                 ...
Table of friction coefficients
6.2 Calculate using friction A s t e e l p o t w it h a w e ig h t o f 5 0 N s it s  on a s teel countertop. H o w m u c...
6.2 Calculate using friction       The engine applies a forward force of        1,000 newtons to a 500-kg car.       Fin...
6.2 FrictionKey Question:H o w c a n w e d e s c r ib e a n d m o d e l  f r ic t io n ?*Students read Section 6.2 AFTER I...
6.3 Equilibrium and Hookes Law When the net force  acting on an object is  zero, the forces on the  object are balanced....
6.3 Equilibrium and Hookes LawNewton’s second law simply requires that for an object to be in equilibrium, the net force, ...
6.3 Equilibrium and Hookes LawMany problems have more than one force applied to an object in more than one place.
6.3 Calculate net force Four people are pulling on the same 200 kg box  with the forces shown. Calculate the acceleratio...
6.3 Calculate force using equilibrium               Two chains are used to lift a                small boat. One of the c...
6.3 Equilibrium and Hookes Law The most common type of spring is a coil of metal or  plastic that creates a force when it...
6.3 Equilibrium and Hookes Law               The force from a spring                has two important                char...
6.3 Hookes Law                           Deformation (m)Force (N)    F=-kx                       Spring constant N/m
6.3 Calculate force A spring with k = 250 N m is extended by one                         /  centimeter. H much force doe...
6.3 Equilibrium and Hookes Law T h e r e s t o r in g  force from a  w a l l is a l w a y s  exactly eq ual  a n d o p p ...
6.3 Calculate using equilibrium The spring constant for a piece of solid wood is 1 × 10 8  N/m. Use Hooke’s law to calcu...
6.3 Equilibrium of Forces and Hookes LawKey Question:Ho w d o yo u p r e d ic t t h e force on a s p r in g ? *Students re...
Application: The design of structures
Forces
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Forces

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Forces

  1. 1. CPO ScienceFoundations of Physics Chapter 9 Unit 2, Chapter 6
  2. 2. Unit 2: Motion and Force in One Dimension Chapter 6: Forces and Equilibrium 6.1 Mass, Weight and Gravity 6.2 Friction 6.3 Equilibrium of Forces and Hooke’s Law
  3. 3. Chapter 6 Objectives Calculate the weight of an object using the strength of gravity ( g) and mass. Describe the difference between mass and weight. Describe at least three processes that cause friction. Calculate the force of friction on an object when given the coefficient of friction and normal force. Calculate the acceleration of an object including the effect of friction. Draw a free-body diagram and solve one-dimensional equilibrium force problems. Calculate the force or deformation of a spring when given the spring constant and either of the other two variables.
  4. 4. Chapter 6 Vocabulary Terms mas s  n o rmal  c o m p r e s s io n w e ig h t force  s p r in g w e ig h t l e s s  e x t e n s io n c o n s tan t g -f o r c e  net force  d e f o r m a t io n f r ic t io n  f r e e -b o d y  r e s t o r in g d ia g r a m force s t a t ic f r ic t io n  l u b r ic a n t  c o e f f ic ie n t s l id in g  e q u il ib r iu m o f f r ic t io n f r ic t io n  b a l l b e a r in g  e n g in e e r in g r o l l in g  d im e n s io n  d e s ig n c y c l e f r ic t io n  s p r in g  s u b s c r ip t v is c o u s  prototype
  5. 5. 6.1 Mass, Weight, and Gravity Mass is a measure of matter. Mass is constant. Weight is a force. Weight is not constant.
  6. 6. 6.1 Mass, Weight, and Gravity The weight of an object depends on the strength of gravity wherever the object is. The mass always stays the same.
  7. 7. 6.1 Weight Gravity (9.8 m/sec2)Weight force (N) Fw = mg Mass (kg)
  8. 8. 6.1 Free fall and weightlessness An e l e v a t o r is a c c e l e r a t in g d o w n w a r d a t 9 .8 m /s e c 2 . T h e s c a l e f e e l s n o f o r c e b e c a u s e it is f a l l in g a w a y f r o m y o u r f e e t a t t h e s a m e r a t e y o u a r e f a l l in g . As a r e s u l t , y o u a r e w e ig h t l e s s .
  9. 9. 6.1 Calculate weight  How much would a person who weighs 490 N ( 110 lbs) on Earth weigh on Jupiter?  The value of g at the top of J upiter’s atmosphere is 23 N kg. /  (Since J upiter may not actually have a surface, “on” means at the top of the atmosphere.)
  10. 10. 6.1 Calculate force  A 10-kilogram ball is supported at the end of a rope. H much force ow (tension) is in the rope?
  11. 11. 6.1 Mass, Weight, and Gravity Key Question: W h a t is s p e e d a n d h o w is it meas ured ?*Students read Section 6.1 BEFORE Investigation 6.1
  12. 12. 6.2 Friction Friction results from relative motion between objects. Frictional forces are forces that resist or oppose motion.
  13. 13. 6.2 Types of Friction Static friction Sliding friction Rolling friction
  14. 14. 6.2 Types of Friction Air friction Viscous friction
  15. 15. 6.2 Friction Normal force (N)Friction force (N) Ff = µ Fn Coefficient of friction
  16. 16. 6.2 Calculate force of friction A 10 N force pushes down on a box that weighs 100 N. As the box is pushed horizontally, the coefficient of sliding friction is 0.25. Determine the force of friction resisting the motion.
  17. 17. 6.2 Sliding Friction Normal force (N)Friction force (N) Ff = µ sFn Coefficient of sliding friction
  18. 18. Table of friction coefficients
  19. 19. 6.2 Calculate using friction A s t e e l p o t w it h a w e ig h t o f 5 0 N s it s on a s teel countertop. H o w m u c h f o r c e d o e s it t a k e t o s t a r t t h e p o t s l id in g ?
  20. 20. 6.2 Calculate using friction  The engine applies a forward force of 1,000 newtons to a 500-kg car.  Find the acceleration of the car if the coefficient of rolling friction is 0.07.
  21. 21. 6.2 FrictionKey Question:H o w c a n w e d e s c r ib e a n d m o d e l f r ic t io n ?*Students read Section 6.2 AFTER Investigation 6.2
  22. 22. 6.3 Equilibrium and Hookes Law When the net force acting on an object is zero, the forces on the object are balanced. We call this condition equilibrium.
  23. 23. 6.3 Equilibrium and Hookes LawNewton’s second law simply requires that for an object to be in equilibrium, the net force, or the sum of the forces, has to be zero.
  24. 24. 6.3 Equilibrium and Hookes LawMany problems have more than one force applied to an object in more than one place.
  25. 25. 6.3 Calculate net force Four people are pulling on the same 200 kg box with the forces shown. Calculate the acceleration of the box.
  26. 26. 6.3 Calculate force using equilibrium  Two chains are used to lift a small boat. One of the chains has a force of 600 newtons.  Find the force in the other chain if the mass of the boat is 150 kilograms.
  27. 27. 6.3 Equilibrium and Hookes Law The most common type of spring is a coil of metal or plastic that creates a force when it is extended ( stretched) or compressed ( squeezed) .
  28. 28. 6.3 Equilibrium and Hookes Law  The force from a spring has two important characteristics: — The force always acts in a direction that tries to return the spring to its unstretched shape. — The strength of the force is proportional to the amount of extension or compression in the spring.
  29. 29. 6.3 Hookes Law Deformation (m)Force (N) F=-kx Spring constant N/m
  30. 30. 6.3 Calculate force A spring with k = 250 N m is extended by one / centimeter. H much force does the spring exert? ow
  31. 31. 6.3 Equilibrium and Hookes Law T h e r e s t o r in g force from a w a l l is a l w a y s exactly eq ual a n d o p p o s it e t o th e fo rce yo u a p p l y , b e c a u s e it is c a u s e d b y t h e d e f o r m a t io n r e s u l t in g f r o m
  32. 32. 6.3 Calculate using equilibrium The spring constant for a piece of solid wood is 1 × 10 8 N/m. Use Hooke’s law to calculate the deformation when a force of 500 N ( 112 lbs) is applied.
  33. 33. 6.3 Equilibrium of Forces and Hookes LawKey Question:Ho w d o yo u p r e d ic t t h e force on a s p r in g ? *Students read Section 6.3 AFTER Investigation 6.3
  34. 34. Application: The design of structures

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