STARTER – label the forces on a car
Tight Corners 2
Physics in Sport
Learning Intentions
 Identify vertical and horizontal forces on a vehicle moving at constant velocity

 Explain that whe...
Italian Job
Forces on a moving vehicle (at a constant speed)
FN

Horizontally
Vertically

FN1

FN2

FR

FD

Tell me about the forces
E...
Forces on a car when cornering

2

v
F m
r

 Centripetal forces are from
friction between the road an
the tyres of the c...
Coefficient of Friction
 The friction between a moving
vehicle/person and the ground is
determined by a number of factors...
Centripetal Force Calculation

150 kg

1. Calculate the
centripetal force acting
on this motor racer.
2. Find the coeffici...
Road Banking
Road Banking Forces
(We assume that frictional forces are now minimal)
 Vertical forces must balance

Fncosθ=mg

Fn =

mg...
Road Banking Forces
(We assume that frictional forces are now minimal)
 Horizontal forces provide the
centripetal force

...
Deriving the formula

Fnsinθ= mv2
r
mg sinθ= mv2
cosθ
r
sinθ= v2
cosθ rg

tanθ= v2
rg
Calculations
 A road is to be constructed with a
bend of radius 200m. It will be banked
so that the cars travelling up to...
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Physics in sport 2

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Physics in sport 2

  1. 1. STARTER – label the forces on a car
  2. 2. Tight Corners 2 Physics in Sport
  3. 3. Learning Intentions  Identify vertical and horizontal forces on a vehicle moving at constant velocity  Explain that when a vehicle travels around a banked curve the horizontal component of the normal force provides the centripetal force.  Derive and use tanθ=v2/rg for banked curves.
  4. 4. Italian Job
  5. 5. Forces on a moving vehicle (at a constant speed) FN Horizontally Vertically FN1 FN2 FR FD Tell me about the forces Express in maths W
  6. 6. Forces on a car when cornering 2 v F m r  Centripetal forces are from friction between the road an the tyres of the car  Resistive and driving forces are not shown
  7. 7. Coefficient of Friction  The friction between a moving vehicle/person and the ground is determined by a number of factors.  Weight  Surface contact  Surface conditions etc.  The reaction force “available” for friction is referred to as the coefficient of friction.  Ff= friction force (N)  FN= Normal (reaction) force (N)  μf= coefficient of friction 𝐹𝑓 = 𝜇 𝑓 𝐹 𝑁
  8. 8. Centripetal Force Calculation 150 kg 1. Calculate the centripetal force acting on this motor racer. 2. Find the coefficient of friction. 835N 0.57
  9. 9. Road Banking
  10. 10. Road Banking Forces (We assume that frictional forces are now minimal)  Vertical forces must balance Fncosθ=mg Fn = mg cosθ
  11. 11. Road Banking Forces (We assume that frictional forces are now minimal)  Horizontal forces provide the centripetal force Fnsinθ= mv2 r
  12. 12. Deriving the formula Fnsinθ= mv2 r mg sinθ= mv2 cosθ r sinθ= v2 cosθ rg tanθ= v2 rg
  13. 13. Calculations  A road is to be constructed with a bend of radius 200m. It will be banked so that the cars travelling up to 100km/h will not rely on friction. What banking angle is necessary?

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