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Calcular el area dad'

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Calcular el area dad'

  1. 1. 1. r= 3 cosө es de la forma r= 2ª cosөdonde 2a = 3 → a = 3/2 → centro (3/2,0)en c. polares tangente al eje π/22. r= 1+ cosөsi sustituimos (r, ө) por (r,- ө) obtenemosecuaciones equivalentes entonces la grafica essimetrica con respecto al eje polar.Si r= 0 → 1+cosө = 0 → cosө = -1 → ө= πө r0 2π/6 1,866π/3 1,52 π/3 0,55 π/6 0,134π 0
  2. 2. Ptos de cortesr= 3cosөr= 1+cosө3 cosө = 1+cosө3 cosө- cosө= 12 cosө= 1Cosө= ½Cosө = 0,5Cosө = 60°A = 2 [f(ө)2- g(ө)2]dөA = 2 (1+cosө)2- (3cosө)2]dө= 2. 1/2 1+2cosө+cos2ө-9cos2ө]dө= 1+2cosө-8 cos2ө]dө = +2 -8 2ө dө= ө +2 senө -8 (1/2 ө+1/4sen 2ө)=π/3+2 (o,866) - 8(π/6+ 1/4(0.866))== π/3+2 (-4/3 π-2)= π/3-4/3π=

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