Lever's law

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Lever's law

  1. 1. F x d1= R x d2LAW OF THE LEVER (OR LEVER’S LAW)The lever is balanced when the effort F, multiplied by its distance, d1 is equal tothe load R, multiplied by its distance from the fulcrum, d2.This is called the Law of the LeverF= force (in newtons, N)R = load or resistance (in newtons, N)d1= distance from the fulcrum to the force (in meters, m)d2=distance from the fulcrum to the resistance (in meters, m)
  2. 2. EXERCISES:Use your dictionary to learn new words.1. You have a first lever class and here you have the data:• Distance from the fulcrum to the load 3 meters• Distance from the fulcrum to the effort 5 meters• Load 1000 NCalculate the effort F, you have to do to balance that load.Draw the lever.F???R= 1000 Nd2= 3 m F * d1= R * d2 (F = x)d1=5 m F= x= (R* d2)/ d1F= (1000* 3)/ 5F= 600 N2. How far from the fulcrum of a seesaw should a boy weighing 30 kg sit, ifa girl at the other end who weights 20 kg, is sitting 2 m from the fulcrum?And if the girl is now sitting 4 m from the fulcrum?What conclusions can you write?3. Write an exercise about the Lever’s Law. Solve the exercise and draw adrawing.4. Draw and colour a fishing rod and indicate clearly the fulcrum, the loadand the effort.
  3. 3. 5. Explain with your own words THE LAW OF THE LEVER. Do a picture toexplain it.

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