Jeopardy review Electricity test ch 1

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Jeopardy review Electricity test ch 1

  1. 1. Electricity Being Ec”Static” Staying Current Circuit Training By the numbers 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4
  2. 2. BEING EC’STATIC’ 1 • What is better at generating a static charge via the friction method? A conductor or an insulator? Why?
  3. 3. BEING EC’STATIC’ 1 • An insulator: Insulators don’t let the charge flow off the object during the rubbing that occurs with the friction method. You want the electrons to build up and stay put…not to flow off the surface.
  4. 4. BEING EC’STATIC’ 2 • If the leaves in an electroscope are repelling each other state what you know about the charge of each leaf. • Would you be able to state the sign of their charge? (positive or negative)
  5. 5. BEING EC’STATIC’ 2 • They have same charge, but you can’t tell if that charge is either positive or negative
  6. 6. BEING EC’STATIC’3 It is believed negative charge builds up in the base of a cloud and that leads to the ground having a positive charge. What method of charging is causing the ground to have this charge? How does it create the positive charge?
  7. 7. BEING EC’STATIC’ 3 • Induction….the electric field of the cloud pushes electrons on the ground away; thereby inducing a positive charge on the ground
  8. 8. BEING EC’STATIC’ 4 • If electrons transfer from a charged object to a neutral one, the process of charging called ____________ has occurred and the act of the electrons making that jump is known as electric___________.
  9. 9. BEING EC’STATIC’ 4 • Conduction, discharge
  10. 10. Staying Current 1 • Pick the items that create voltage: a light bulb a battery a wire a photocell an electric motor a switch
  11. 11. Staying Current 1 a light bulb a battery a wire a photocell an electric motor a switch
  12. 12. Staying Current 2 The term “potential difference” refers to the circuit’s _______________
  13. 13. Staying Current 2 • voltage
  14. 14. Staying Current 3 Measuring the rate of the electricity’s ability to do work is when you measure ____________ and the units are ________________ Whereas, electrical energy is measured in ___________
  15. 15. Staying Current 3 • Power, watts, joules (or kilowatt-hours)
  16. 16. Staying Current 4 • A 9 volt battery is connected to an open circuit that has a total resistance of 8 ohms. How much current is flowing in it? (give answer in proper units of measure)
  17. 17. Staying Current 4 • Zero amps. (open circuit!)
  18. 18. Circuit Training 1 Which circuit would have higher resistance? Why?
  19. 19. Circuit Training 1 • The series circuit on the left has higher resistance. Parallel circuits have more branches which allows electrons to flow freer in more “lanes”; yielding lower resistance
  20. 20. Circuit Training 2 • Placing a switch between points 3 and 4 in the circuit will cause what to occur when the switch is opened? • (R1, R2, R3 are light Bulbs) • R2D2 is a droid
  21. 21. Circuit Training 2 • The “R3” to turn off.
  22. 22. Circuit Training 3 1) Will this bulb light? 2) Is this a regular circuit or a short circuit?
  23. 23. Circuit Training 3 • 1) no • 2) it’s a short circuit
  24. 24. Circuit Training 4 • List the four properties of the circuit parts that affect resistance in a circuit
  25. 25. Circuit Training 4 • Thickness of parts, length of circuit, temperature of parts, materials used in circuit
  26. 26. By the Numbers 1 • If a circuit has 20 ohms of resistance and is running with 20 amps of current, what is the voltage?
  27. 27. By the Numbers 1 • V= IR • V= 20 amps * 20 ohms= 400 volts
  28. 28. By the Numbers 2 • If the circuit of an appliance is closed for 60 seconds and is using 600 J of energy, what power is used by the appliance?
  29. 29. By the Numbers 2 • E= PT • So E/T=P 600 J/ 60 s= 10 Watts
  30. 30. By the Numbers 3 • A circuit has 10 Ω resistance under normal conditions. • A short circuit occurs and the circuit’s current jumps to 10 amps. It was at 1 amp before the short circuit. • It’s voltage is set at 10 V. • What is the resistance of the short circuit?
  31. 31. By the Numbers 3 • R=V/I • 10 V/ 10A= 1 Ω
  32. 32. By the Numbers 4 Calculate the current of this circuit
  33. 33. By the Numbers 4 • • • • Total resistance = 18 ohms Voltage= 9 V V/R= I So, answer is 9 V/ 18 ohms= .5A

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