Stoichiometry

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  • Stoichiometry

    1. 1. Stoichiometry, The Mole,and Quantitative Review our discussion ofChemistry mathematical applications to chemistry: The mole and Dimensional analysis.• How many atoms are in 12.00 grams of Iron? Nylon Rope
    2. 2. We tie together the concepts of Formula writing, identifying reactions, and quantitative chemistryIf we take a look again at the reactionfrom the Types of Chemical Reactionschapter between Cl2 and NaBr, thistime from a quantitative standpoint. Cl2 + 2 NaBr Br2 + 2 NaCl Polypropylene knife handles
    3. 3. A Sample Problem... Cl2 + 2 NaBr Br2 + 2 NaClIf we react 5.00 grams of NaBr with excess Cl2, how many grams of Br2will be formed?Construct a pathway…Grams Reactant-->Moles Reactant-->Moles Product-->Grams ProductThe Solution...5.00g NaBr x 1 mole NaBr/102.90 g NaBr x 1 mole Br2/2 mole NaBr x159.80g Br2/1 mole Br2=3.88 g Br2
    4. 4. Try This One... CaCl2+ Na2CO3 CaCO3 + 2 NaCl• How many grams of CaCO3 will be formed if 8.00 grams of CaCl2 are completely reacted with Na2CO3? Limestone formation in South Africa
    5. 5. Limiting Reactant Problems Ideally, each reactant in a reaction is completely used up. Sometimes, however, one reactant is used up before the other and the reaction stops. This is called the Limiting Reactant. Let’s Take Another Look Cl2 + 2 NaBr Br2 + 2 NaCl
    6. 6. The Solution...If we reacted 5.00 g of NaBr with 8.00 g of Cl2, how many grams of Br2 will be formed?What is the limiting reactant? How many grams of excess reactant remain?5.00g NaBr x 1 mole NaBr/102.90g NaBr x 1 mole Br2/2 mole NaBr x 159.80g Br2/1moleBr2=3.88g Br2 *NaBr is the Limiting Reactant8.00g Cl2 x 1 mole Cl2/70.90g Cl2 x 1 mole Cl2/1mole Br2 x 159.80g Br2/1 mole Br2=18.03 g Br2 *Cl2 is the excess reactant3.88g Br2 x 1mole Br2/159.80 g Br2 x 1 mole Cl2/1mole Br2 x 70.90 g Cl2/1mole Cl2=1.72 g Cl2 needed

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