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# Uv vis spectroscopy

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### Uv vis spectroscopy

1. 1. UV-Vis spectroscopy Spectroscopyis the study of the interaction betweenmatterandradiated energy. By: Bijaya Kumar Uprety
4. 4. •Frequency: The number of complete cycles of a periodic process occurring per unit time. Its unit is Hertz (Hz). •Wavelength: Distance between two consecutive crest or trough is called wavelength. It can be measured in cm, μm, nm or angstrom (Å). Where, 1 nm= 10-3μm =10-6=10-7cm =10-9m and 1 Å = 10-8cm. •Amplitude: The maximum extent of a vibration or oscillation, measured from the position of equilibrium. It is the intensity of wave. Its unit is meter.
5. 5. •Frequency shares an inverse relationship with the wavelength so that; v = c/λ Where; v= frequency c= speed of light (3 x 108m/s) λ= wavelength •Sometimes radiation, mostly in the infrared region is characterized by another term known as the wave number and is given as; •Wave number means the number of complete cycles occurring per centimeter.
6. 6. Energy of Electromagnetic radiation- Particle theory •Electromagnetic energy/radiation is emitted only in tiny packets or quanta of energy that were later known as photons. •Each photon pulses with a frequency and travels with the speed of light. •The energy of the photon of electromagnetic radiation is proportional to its frequency. •Energy of photon= E = hv Where, h= proportionality constant=planck’sconstant= 6.63 x 10-34J.s & v= frequency
7. 7. •Energy = Planck’s constant x frequency or, E = h x v or, J = Js x s-1 •Most chemical energies are quoted in Jmol-1or KJmol-1rather than in Joules for an individual atom. •We therefore need to multiply our value of h x v by the Avogadro constant to obtain Jmol-1 •Avogadro constant = NA= 6.02 x 1023mol-1 •Energy = Avogadro constant x Planck’s constant x frequency E = NAx h x v Jmol-1= mol-1x J s x s-1
9. 9. Light comparison Name Wavelength Frequency (Hz) PhotonEnergy(eV) Gamma ray less than 0.01nm more than 15EHz more than 62.1keVX-Ray 0.01nm –10nm 30 EHz –30PHz 124 keV–124 eV Ultraviolet 10nm –400nm 30 PHz –750 THz 124 eV–3 eV Visible 390nm –750nm 770 THz –400 THz 3.2 eV–1.7 eV Infrared 750nm –1mm 400 THz –300GHz 1.7 eV–1.24meV Microwave 1mm –1 meter 300GHz –300MHz 1.24 meV–1.24μeV Radio 1mm –1,000km 300 GHz–3 Hz 1.24 meV–12.4feV
10. 10. Numerical
11. 11. Laws of Absorption •Theabsorptionoflightbyanyabsorbingmaterialisgovernedbytwolaws •ThefirstoftheselawsisknownastheBouger-Lambertlaw. •Bouger-lambertlaw:Itstatesthattheamountoflightabsorbedisproportionaltothethicknessoftheabsorbingmaterialandisindependentoftheintensityoftheincidentlight. •Tounderstandtheabovestatementletusassumethatathicknessbhastheabilitytoabsorb50%oftheincidentintensityofthelightpassingthroughit.Iftheintensityoftheradiationincidentuponsuchathicknessisassignedavalueof1.0, theoutcomingi.e.thetransmittedbeamwillhaveavalueof0.5.Ifwenowplaceasecondequalthicknessb,itwillabsorb50%ofthetransmittedbeam,i.e.50%of0.5.Thesecondtransmitttedbeamwillthenhaveavalueof0.25. i.e100%50%25%12.5%6.25%3.125%
12. 12. •Thesuccessivelightintensitiesarethesequence(0.5)1,(0.5)2, (0.5)3etc.Thisisclearlyanexponentialfunctionandmaybeexpressedas; I/I0=e–kb-----(1) Where, I = the intensity of the transmitted light, I0= the intensity of the incident light. b= the absorbing thickness, better known by the term path-length. k= the linear absorption coefficient of the absorbing material. The power term in the above relationship can be removed by converting to the logarithmic form. Thus, ln I/I0 = -kb, or, ln I0/ I =kb------------(2) Changing to common logarithms we get, 2.303 log10( I0/I) = kb ---------------(3)
13. 13. •ThesecondlawofabsorptionisknownastheBeer’slaw.Thisstatesthattheamountoflightabsorbedbyamaterialisproportionaltothenumberofabsorbingmoleculesi.e.theconcentrationofabsorbingsolution. •Thiscanbemathematicallyexpressedintheformoftheequationsimilartotheoneabove. 2.303log10(I0/I)=k’C-----------(4) Where,k’=absorptivityconstantand C=theconcentrationoftheabsorbingmaterial •WecannowcombinethetwoequationsfortheBouger- lambertlawandtheBeer’slaw.Here,kandk’mergetobecomeasingleconstant‘a‘.Thecombineequationiswrittenas,
14. 14. log10(I0/I)=abC-------(5) OrA=abc-------(6) where,A=absorbanceisadimensionless b=pathlength(cm) c=concentration(M) a=Molarabsorptivityconstant(M-1cm-1)ormolarextinctioncoefficientorspecificabsorptioncoefficient(gL-1cm-1) Foramixture,Atotal=A1+A2+A3….+An •Molarabsorptivityisthecharacteristicofasubstancethattellshowmuchoflightisabsorbedataparticularwavelength. •ThisequationhasbeenalternatelyreferedtoastheBeer-Lambertlaw,theBouger-Beerlaw,ormoresimply,Beer’slaw.Thiscombinedlawstatesthattheamountoflightabsorbed(absorbanceorextinction)isproportionaltotheconcentrationoftheabsorbingsubstanceandtothethicknessoftheabsorbingmaterial(path– length).
15. 15. •Absorbancesharesalinearrelationshipwithsampleconcentration.Ontheotherhand,therelationshipbetweentransmittanceandsampleconcentrationisanon-linearone.Itisthereforeeasiertouseabsorbanceasanindexofsampleconcentration. •ThequantityI/I0isknownastransmittanceandisdenotedbyT(amountoflightwhichescapesabsorptionandistransmitted). •Thus,therelationshipbetweenAbsorbanceandtransmittanceisgivenby; A=-log(I/I0)=-logT Standardcurve: Forquantitativeanalysis,astandardcurveorcalibrationcurveispreparedinwhichabsorbance(A)ataspecificwavelength(λ)isplottedagainsttheconcentrationinaseriesofstandards[sameanalyte,knownconcentration(c)]. As‘A’isproportionaltotheC,itshouldbeastraightlinepassingthroughtheorigin.
16. 16. A = abc + 0 Beer lambert law Y = mx + c Equation of straight line It allows us to calculate the concentration of unknown analyte.
17. 17. Analysis of Mixtures of Absorbing Substances •When the sample solution contains more than one absorbing species, the absorbance of the solution will be the sum of allabsorbances: •At= A1+ A2+ A3+ …. •The different constituents can be determined if we build equations equal to the number of unknowns. However, this procedure, if manually performed, is impractical due to lengthy and difficult math involved. When only two absorbing species are present, the solution is formidable and is executed by finding the absorbance of the solution at twowavelength(wavelength maximum for eachanalyte): •Al’=ex’bcx+ey’bcy(1) •Al”=ex”bcx+ey”bcy(2) •ex’,ex”,ey’,ey” can be determined from standards ofanalytesx and y atl’,l” and values obtained are inserted in equations 1 and 2 where two equations in two unknowns can be easily solved.
20. 20. •Fluorescence:Somesolutefluoresce.Forsuchsubstances, deviationoccurbecauseapartfromthetransmittedintensity, fluorescentintensityalsoreachesthedetector. •Turbidity:Turbidsolutionalwaysendupgivinghigherabsorbancethanwhatisdeterminedbycolor.
21. 21. Q.1 Q.2
22. 22. Q.2 (a) and 2 (b) 2 (a) 2 (b)
23. 23. Q. 2 continued…..
24. 24. Q. 2 (c) and (d) solution
25. 25. Q.3
26. 26. Solution of Q.3
27. 27. Electronic transition •Therearegenerallythreetypesoforbitalsfoundinthegroundstateoforganicmolecules. 1.Bondingσ–orbitals:Theseareextremelystrongandconstitutesinglebondsbetweenatoms.Theelectronsarenotatalldelocalizedandthedistributionofelectronsiscylindricallysymmetricalabouttheaxis. 2.Bondingπ–orbitals:Theseconstitutemultiplebondsbetweenatomsandarebasedonacombinationofatomicp-orbitals.Theelectronsarestronglydelocalizedandinteractwiththesurroundingenvironmentwithrelativeease. 3.n–orbitals:Certainmoleculescontainsheteroatoms(i.e.heteroatomisanyatomthatisnotcarbonorhydrogene.g.oxygen,nitrogen,sulfur,etc). Theoccupiedorbitalswithhighestenergyinsuchmoleculesarethoseoflonepairs.Theselonepairsarenotinvolvedinbondsandthusretaintheiratomiccharacters.
29. 29. 1.TherearefourdifferenttypesofelectronictransitionswhichcantakeplaceinmoleculeswhentheyabsorbUV-Visradiation.ThemajorelectronictransitionswithintheUV-visregionsalongwiththeenergiesassociatedwiththetransitionaregivenbelow: σσ*>nσ*>ππ*>nπ* •Aσσ*arenotusefulforfollowingreasons: Theσσ*transitionrequiresveryhighenergywhichoccursinvacuumUV.AndItisnotwisetothinkofdoingUVmeasurementsonmolecularspeciesinthevacuumUVregion(125-185nm)forfiveimportantreasons: •Thehighenergyrequiredcancauseruptureoftheσbondsandbreakdownofthemolecule. •AircomponentssuchasoxygenabsorbstronglyinvacuumUVwhichlimitstheapplicationofthemethod. •WorkinginvacuumUVrequiresspecialtrainingandprecautionswhichlimitwideapplicationofthemethod. •Specialsourcesanddetectorsmustbeused. •Allsolventscontainσbonds.
30. 30. Thenσ*transitionrequireslowerenergythanthatrequiredforσσ*transition.Thistypeoftransitionusuallytakesplaceinsaturatedcompoundscontainingoneheteroatomwithunsharedpairofelectrons.Moleculessuchaswater,ether,andaminesshowabsorptionattributedtothistypeoftransitions. •Theabsorptionwavelengthforanσ*transitionoccursatabout185nmwhere,unfortunately,mostsolventsabsorb.Forexample, themostimportantsolventis,undoubtedly,waterwhichhastwopairsofnonbondingelectronsthatwillstronglyabsorbasaresultofthenσ*transitions;whichprecludestheuseofthistransitionforstudiesinaqueousandothersolventswithnonbondingelectrons.Insummary,itisalsoimpracticaltothinkofusingUV- Visabsorptionspectroscopytodetermineanalytesbasedonan σ*transition.
32. 32. •Thenπ*transitionrequiresverylittleenergyandseemtobepotentiallyuseful. •BywayofgeneralizingitmaybesaidthattheabsorptionbandsofalmostallorganicmoleculesnormallyfoundinthenearUVandvisibleregionsareduetoeitherππ*orn π*.Onecandistinguishbetweenππ*ornπ*transitionbylookingattheextinctionco-efficientsofthepeaksatλmax. •Thenπ*transitionhaveextinctioncoefficientoftheorderofmagnitudeofjust10whereasforππ*transitionisoftheorderofmagnitude103-104. •Compoundssuchasacetaldehydeandnitrosobutanegiveabsorbanceandundergoesthistypeoftransition. •However,unfortunately,theabsorptivityofthistransitionisverysmallwhichprecludesitsuseforsensitivequantitativeanalysis.
38. 38. •Simpleglassprismareusedforvisiblerange. •Foruvregionsilica,fusedsilicaorquartzareused.FlouriteisusedinvacuumUltravioletrange. Gratings:Gratingsareoftenusedinthemonochromatorsofspectrophotometersoperatinginultraviolet,VisandIRregions.Thegratingpossessesahighlyaluminizedsurfaceetchedwithlargenumberofparallelgrooveswhichareequallyspaced.Thesegroovesarealsoknownaslines.Agratingmayhaveanywerebetween600to2000linespermmonthesurfacedependingontheregaionofthespectruminwhichitisintendedtooperateit. Inrealpractice,themonochromatorconsistofboth,prismandagrating. Theprismplacedbeforethegratingisknownastheforeprism.Itpreselectsaportionofthespectrumwhichisthenallowedtobediffractedbythegrating.
39. 39. Sample container: •Samples to be studied in the UV-Vis region are usually gas or solution and are put in cells known as cuvette. •Spectra of gases are taken using enclosed cells, with an evacuated cell as a reference. Standard path-length of gas cells is usually 1 mm but cells with path length of 0.1 to 100 mm are available for special cases. •Most of the spectrophotometric studies are made in solution. The solutions are dispensed in cells known as cuvettes. •Cuvette meant for ultraviolet region are made up of either ordinary glass or sometimes quartz. Since glass absorbs in the UV region, quartz or fused silica cells are used in this region. Standard path length of these cuvettes is usually 1 cm. However, cuvettes of path-length of 1 mm to 10 cm are available for special purposes. •The surface of the cuvette must be kept very clean, free from fingerprints smudge, and traces of previous samples which might otherwise cause interference in the optical path.