6.2 (b) molten compound2

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6.2 (b) molten compound2

  1. 1. KPD4033TEKNOLOGI DAN INOVASI DALAM PENDIDIKAN Ahli Kumpulan:Noor Emy Liana Daud L20112007112Nor Azieda Azahari L20112007081Mahfuza Mansor L20112007049Zeti Farhana Mohd Lazim L20112007113Amimah Mohammad Ayub L20112007076
  2. 2. ELECTROCHEMISTRYELECTROLYSIS IN MOLTEN STATE
  3. 3. ObjectiveInduction Set Introduction Molten State Exercises Conclusion
  4. 4. Objective AFTER THE LESSON STUDENTS ARE ABLE TO…..Induction Set  Identify the ions present inIntroduction molten compound.  Name the cations and anionsMolten State of a molten compound.Exercises  Determine the product formed in cathode andConclusion anode.
  5. 5. ObjectiveInduction SetIntroductionMolten State ExercisesConclusion
  6. 6. Objective Do you remember?Induction Set  Why solid sodium chloride doesIntroduction not conduct electricity?  Why molten sodium chloride is anMolten State electrolyte?  When electrolysis of a moltenExercises compound, where should anion and cation move?Conclusion
  7. 7. Objective ELECTROLYSIS OF A MOLTEN COMPOUNDInduction SetIntroductionMolten StateExercisesConclusion
  8. 8. Steps to identify ion inObjective electrolysis of MOLTEN STATEInduction Set 1. Identify all ion present in molten stateIntroduction 2. Identify ion moving to cathode and anode electrodeMolten State 3. Identify the ion that will be dischargeExercises in cathode and anodeConclusion 4. Write half equation in cathode and anode
  9. 9. COMPREHENSION
  10. 10. Complete the following passage to describe the electrolysis of lead bromide.Objective Use the words from the box to complete the passage.Induction Set  Ions non-metal lead Electrode electrons bromine molten metal positive negative bromideIntroduction  When lead bromide is molten it contains free ions of lead and bromine. Lead isMolten State a metal so it forms positive ions. Bromine is a non - metal so it forms negative ions. The lead ions are attracted to theExercises negative electrode where they gain electrons to form lead metal. The bromide ions are attracted to theConclusion positive electrode where they lose electrons to form bromine gas.
  11. 11. Objective Ready for Quiz???Induction Set Electrolytes can conduct electricity because there have free moving…Introduction A) Electrons B) MoleculesMolten StateExercises C) Atoms D) IonsConclusion
  12. 12. Objective Ready for Quiz??? What are the ions present in aqueousInduction Set solution of silver nitrate?Introduction A) Silver ions and nitrate ionsMolten State B) Silver ions, nitrate ions and hydroxide ionsExercises C) Silver ions, nitrate ions, hydroxide ions and hydrogen ionsConclusion D) Hydroxide ions and hydrogen ions
  13. 13. Ready for Quiz???Objective What is the final product producedInduction Set at anode?Introduction A) Sodium B) Chloride ionMolten StateExercises C) Sodium Chloride D) Chlorine gasConclusion
  14. 14. Objective Ready for Quiz??? Which of the following ions attractedInduction Set to anode during electrolysis of aqueous Zinc chloride solution?Introduction B) Zinc ion and A) Zinc ion only. chloride ion.Molten StateExercises C) Zinc ion and D) Chloride ion and hydrogen ion. hydroxide ion.Conclusion
  15. 15. Objective CONCLUSIONSInduction Set  Ions present in the compound of NaCl in molten state are Na+ and Cl-Introduction  Cations : Na+ Anions : Cl-Molten State  Product at cathode : Sodium Product at anode : Chlorine gasExercisesConclusion
  16. 16. 1. Identify all ion present in molten state Electrolysis of a molten compo ONLY occur 2 ions in the electro1. Molten 2. Molten PbI2 NaCl • Pb2+ • Na+ • I- • Cl-
  17. 17. 2. Identify ion moving to cathode and anode electrode1. Molten 2. Molten PbI2 NaCl • Pb2+ cathode cathode • Na+ anode • I- anode • Cl-
  18. 18. 3. Identify the ion that will be discharge in cathode and anode1. Molten 2. Molten PbI2 NaCl • Pb cathode cathode • Na anode • I2(g) anode • Cl2(g)
  19. 19. 4. Write half equation in cathode and anode1. Molten NaCl 2. Molten PbI2 • Na+ • Pb2+ Cathode: Cathode: • Na+ + 2e Na • Pb2+ + 2e Pb • Cl- • I- Anode: Anode: • 2Cl- Cl2 + 2e • 2I- I2 + 2e

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