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Lista 9º ano resolvida

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Lista 9º ano resolvida

1. 1. Professora Andréia Santana1) x² - 5x + 6 = 0a=1b= – 5c=6∆=∆= (-5)² - 4.1.6∆= 25 - 24∆= 1√∆ ( ) √2) x² - 8x + 12 = 0a=1b= – 8c=12∆=∆= (-8)² - 4.1.12∆= 64 – 48∆= 16√∆ ( ) √
2. 2. Professora Andréia Santana3) x² + 2x - 8 = 0a=1b= 2c=-8∆=∆= 2² - 4.1.(-8)∆= 4+32∆= 36√∆ √4) x² - 5x + 8 = 0a=1b= – 5c=8∆=∆ ( )∆ –∆Não possui raízes reais
3. 3. Professora Andréia Santana5) 2x² - 8x + 8 = 0a=2b= –8c=8∆=∆= (-8)² - 4.2.8∆= 64-64∆= 0√∆ ( ) √6) x² - 4x - 5 = 0a=1b= – 4c= – 5∆=∆= (-4)² - 4.1.(-5)∆= 16 + 20∆= 36√∆ ( ) √
4. 4. Professora Andréia Santana7) - x² + x + 12 = 0a= – 1b= 1c=12∆=∆= 1² - 4.(-1).12∆= 1+48∆= 49√∆ √( )8) -x² + 6x - 5 = 0a= – 1b= 6c= – 5∆=∆= ( ) ( )∆= 36 – 20∆= 16√∆ √( )
5. 5. Professora Andréia Santana9) 6x² + x - 1 = 0a= 6b= 1c= – 1∆=∆= ( )∆= 1+24∆= 25√∆ √10) 3x² - 7x + 2 = 0a= 6b= 1c= – 1∆=∆= ( )∆= 1+24∆= 25√∆ √
6. 6. Professora Andréia Santana11) 2x² - 7x = 15  2x² – 7x – 15 = 0a=2b= -7c= -15∆=∆= (-7)² - 4.2.(-15)∆= 49 + 120∆= 169√∆ ( ) √12) 4x² + 9 = 12x  4x² - 12x + 9 = 0a=4b= -12c= 9∆=∆= (-12)² - 4.4.9∆= 144 - 144∆= 0√∆ √
7. 7. Professora Andréia Santana13) x² = x + 12  x² - x – 12 = 0a=1b= 2c=-8∆=∆= 2² - 4.1.(-8)∆= 4+32∆= 36√∆ √14) 2x² = -12x - 18  2x² +12x + 18 = 0a=2b= 12c=18∆=∆= 12² - 4.2.18∆= 144 - 144∆= 0√∆ √
8. 8. Professora Andréia Santana15) ( x - 5)² = 1( )( )a=1b= -10c= 24∆=∆= (-10)² - 4.1.24∆= 100 - 96∆= 4√∆ ( ) √
9. 9. Professora Andréia Santana16) 25x² = 20x – 4a=25b= -20c= 4∆=∆= (-20)² - 4.25.4∆= 400 – 400∆= 0√∆ ( ) √17) 2x = 15 – x²a=1b= 2c= -15∆=∆= 2² - 4.1.(-15)∆= 4+60∆= 64√∆ √
10. 10. Professora Andréia Santana18) x² + 3x – 6 = -8a=1b= 3c= 2∆=∆= 3² - 4.1.2∆= 9-8∆= 1√∆ √19) x² + x – 7 = 5a=1b= 1c= -12∆=∆= 1² - 4.1.(-12)∆= 1+48∆= 49√∆ √
11. 11. Professora Andréia Santana20) 4x² - x + 1 = x + 3x²a=1b= -2c= 1∆=∆= (-2)² - 4.1.1∆= 4 - 4∆= 0√∆ ( ) √21) 3x² + 5x = -x – 9 + 2x²a=1b= 6c= 9∆=∆= 6² - 4.1.9∆= 36-36∆= 0√∆ √
12. 12. Professora Andréia Santana22) 4 + x ( x - 4) = xa=1b= -5c= 4∆=∆= (-5)² - 4.1.4∆= 25 - 16∆= 9√∆ ( ) √23) x ( x + 3) – 40 = 0a=1b= 3c= -40∆=∆= 3² - 4.1.(-40)∆= 9+160∆= 169√∆ √
13. 13. Professora Andréia Santana24) x² + 5x + 6 = 0a=1b= 5c= 6∆=∆= 5² - 4.1.6∆= 25-24∆= 1√∆ √25) x² - 7x + 12 = 0a=1b= -7c= 12∆=∆= (-7)² - 4.1.12∆= 49-48∆= 1√∆ ( ) √
14. 14. Professora Andréia Santana26) x² + 5x + 4 = 0a=1b= 5c= 4∆=∆= 5² - 4.1.4∆= 25-16∆= 9√∆ √27) ( 2x - 4)² = 0( )( )a=4b= -16c= 16∆=∆= (-16)² - 4.4.16∆= 256-256∆= 0√∆ ( ) √
15. 15. Professora Andréia Santana28) x² - 18x + 45 = 0 _____(R:3,15)a=1b= -18c= 45∆=∆= (-18)² - 4.1.45∆= 324 - 180∆= 144√∆ ( ) √29) -x² - x + 30 = 0a=-1b= -1c= 30∆=∆= (-1)² - 4.(-1).30∆= 1 + 120∆= 121√∆ ( ) √( )
16. 16. Professora Andréia Santana30) x² - 6x + 9 = 0a=1b= -6c= 9∆=∆= (-6)² - 4.1.9∆= 36-36∆= 0√∆ ( ) √31) ( x + 3)² = 1( )( )a=1b= 6c= 8∆=∆= 6² - 4.1.8∆= 36-32∆= 4√∆ √
17. 17. Professora Andréia Santana32) x² + 3x - 28 = 0 (R: -7,4)a=1b= 3c= -28∆=∆= 3² - 4.1.(-28)∆= 9+112∆= 121√∆ √33) x² - 3 = 4x + 2 (R: -1,5)a=1b= -4c= -5∆=∆= (-4)² - 4.1.(-5)∆= 16+20∆= 36√∆ ( ) √

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