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# MONEY

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### MONEY

1. 1. Learning OutcomesPerform mixed operations with money up to a valueof RM 10 million.Solve problems in real context involvingcomputation of money.
2. 2. Perform mixed operations with money up to a value of RM10 million EXAMPLE 1 RM8000 + RM1254 ─ RM5555 = Step 1 : Check winner’s platform. ( ) ×÷ ÷× 1 +─ 2 ─+ 3 Note : + and ─ are on the same scale. So calculate as in the order given. Step 2: Step 3: RM8000 RM9254 + RM1254 ─ RM5555 RM9254 RM3699
3. 3. EXAMPLE 2(RM125 × 8) ─ (RM40 × 8) =Step 1 : Check winner’s platform. ( ) ×÷ ÷× 1 +─ 2 3 + ─Note : Do the operations that are in the bracketsfirst (x) then do the subtraction.Step 2: Step 3: Step 4: RM125 RM40 RM1000× 8 × 8 ─ RM 320RM1000 RM320 RM 680
4. 4. Solve problems in real context involving computation of money IMPORTANT KEY WORDS Savings Income Expenditure Investments Cost Price Selling Price Profit Loss Discount Computation IMPORTANT FORMULAS PROFIT = SELLING PRICE (SP) ─ COST PRICE(CP) LOSS = COST PRICE ─ SELLING PRICE
5. 5. Example 1: The cost price of a television is RM1 357. Rahim sold each television for RM1 475. He sold 15 televisions. W is his profit? W What Step 1 : Read and understand question. As you read, underline the key words. The cost price of a television is RM1 357. Rahim sold each television for RM1 475. He sold 15 televisions. What is his p profit? Step 2 : Write the operation / formula the keywords signify. The cost price of a television is RM1 357. Rahim × sold each television for RM1 475. He sold 15 SP - CP ? televisions. What is his profit? Step 3 : Find the profit of a TV Step 4 :Profit of 15 TV RM1 475 RM118 × 15 = RM1 770 - RM1357 RM 118
6. 6. EXAMPLE 2Kumari bought a gold chain and a gold bracelet. Thegold chain costs RM3 518 and the gold bracelet costsRM755 less than the gold chain. How much did she payaaltogether?Step 1 :Read and understand question. As you read, underline thekey words.Kumari bought a gold chain and a gold bracelet. Thegold chain costs RM3 518 and the gold bracelet costsRM755 less than the gold chain. How much did she payaaltogether?Step 2 :Write the operation / formula the keywords signify.Kumari bought a gold chain and a gold bracelet. Thegold chain costs RM3 518 and the gold bracelet costs ─ RM755 less than the gold chain. How much did she Chain + Bracelet Pay altogether? ?Step 3 : Find the bracelet’s price Step 4 : Chain + Bracelet RM3 518 RM3 518─RM 755 + RM2 763 RM2 763 RM6 281
7. 7. EXAMPLE 3A packet of health food supplements costs RM690.There is a discount of RM15.90 per packet. Yoongbought 7 packets of the supplements. How much did heppay?Step 1 :Read and understand question. As you read, underline thekey words.A packet of health food supplements costs RM690. Thereis a discount of RM15.90 per packet. Yoong bought 7packets of the supplements. How much did he p pay?Step 2 :Write the operation / formula the keywords signify.A packet of health food supplements costs RM690. ─ ×There is a discount of RM15.90 per packet. Yoong bought7 packets of the supplements. How much did he p pay?Step 3 : Step 4 :Find the price after Discount price × 7discount of a packet. RM690.00 RM674.10─RM 15.90 × 7 RM674.10 RM4 718.70