The function f(x) = (x ? 8)2 + 4, x ? 8.is one-to-one. Find its inverse and check your answer. State the domain of f and find its range using f-1. Solution y=(x-8)^2+4 y-4=(x-8)^2 x=8+ sqrt(y-4) so it is not one to one as for one y, you can have two different x values depending upon which square root value you are considering. domain of f= (-infinity, 8] range of f=domain of f^-1=[8, infinity).