# I will answer for 33. Because you had to give me the number to solve.pdf

The document shows the steps to solve an equation involving the squares of three odd integers separated by 2. It expands and combines terms to get x2 - 4x - 45 = 0, then factors this as (x - 9)(x + 5) = 0. The possible solutions are x = 9 or x = -5, but the question asks for the smallest number, which is 9.

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### I will answer for 33. Because you had to give me the number to solve.pdf

• 1. I will answer for 33. Because you had to give me the number to solve the exercise. If a different number you only have to replace the number. Every other number is an odd integer, so they are separated by 2: Let x be the first odd integer Let x+2 be the second odd integer Let x+4 be the third odd integer The square of the third is 33 less than the sum of the squares of the first two. x² + (x + 2)² - 33 = (x + 4)² Expand each one by using FOIL: x² + x² + 4x + 4 - 33 = x² + 8x + 16 Get everything on the left side: x² + x² + 4x + 4 - 33 - x² - 8x - 16 = 0 Combine like terms: (x² + x² - x²) + (4x - 8x) + (4 - 33 - 16) = 0 x² - 4x - 45 = 0 Factor that as: (x - 9)(x + 5) = 0 The zero product rule gives us two possible answers for the smallest number. x = 9 or x = -5 You already have 9, 11 and 13 Solution I will answer for 33. Because you had to give me the number to solve the exercise. If a different number you only have to replace the number.
• 2. Every other number is an odd integer, so they are separated by 2: Let x be the first odd integer Let x+2 be the second odd integer Let x+4 be the third odd integer The square of the third is 33 less than the sum of the squares of the first two. x² + (x + 2)² - 33 = (x + 4)² Expand each one by using FOIL: x² + x² + 4x + 4 - 33 = x² + 8x + 16 Get everything on the left side: x² + x² + 4x + 4 - 33 - x² - 8x - 16 = 0 Combine like terms: (x² + x² - x²) + (4x - 8x) + (4 - 33 - 16) = 0 x² - 4x - 45 = 0 Factor that as: (x - 9)(x + 5) = 0 The zero product rule gives us two possible answers for the smallest number. x = 9 or x = -5 You already have 9, 11 and 13
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