Identities Identities Identities Identities Identities
2. Prove the following Identity using two different methods:   2. Prove the following Identity using two different methods:
For this question.  You can work with the more complicated side.  In this case it is the left side. Method # 1: Line of Se...
1} 1} In step one, we realized that we can multiply by reciprocal of the bottom fraction instead of dividing.
2} 2} For step two you can think of tanθ as sinθ/cosθ.
3} In step three we can multiply sinθ by sinθ/cosθ. 3}
4} 4} Here we can multiply sin²θ/cosθ out by 1/cosθcos³θ.  We can also factor out cos²θ in the denominator.
5} 5} In this last step we can say that sin²θ/cos²θ is tan²θ and by the Pythagorean identity (1-cos²θ) is sin²θ.
QED
QED
Method # 2: Line of Separation /  “Great Wall of China” Working with both sides can also work:
1} Here we can say that tan²θ is equal to sin²θ/cos²θ. ~by saying that, it can be simplified to 1/cos²θ. 1} [Right Side]
2} 2} Here we recognize cosθ-cos³θ as cosθ - (cosθcos²θ) or cosθ - cosθ (1-sin²θ). Also, tanθ as sinθ/cosθ. [Left Side]
3} 3} In this step we can multiply cosθ by (1-sin²θ).
4} 4} By multiplying by the reciprocal of sinθ/cosθ we can see that when cosθ gets multiplied out, we get cos²θ-cos²θ+sin²...
5} 5} In this last step we see that sin²θcosθ/sinθ leaves us sinθcosθ.  The sinθ’s reduce leaving us 1/cosθ.
QED
QED
Identities Identities Identities Identities Identities
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Identitieslong

  1. 1. Identities Identities Identities Identities Identities
  2. 2. 2. Prove the following Identity using two different methods: 2. Prove the following Identity using two different methods:
  3. 3. For this question. You can work with the more complicated side. In this case it is the left side. Method # 1: Line of Separation / “Great Wall of China”
  4. 4. 1} 1} In step one, we realized that we can multiply by reciprocal of the bottom fraction instead of dividing.
  5. 5. 2} 2} For step two you can think of tanθ as sinθ/cosθ.
  6. 6. 3} In step three we can multiply sinθ by sinθ/cosθ. 3}
  7. 7. 4} 4} Here we can multiply sin²θ/cosθ out by 1/cosθcos³θ. We can also factor out cos²θ in the denominator.
  8. 8. 5} 5} In this last step we can say that sin²θ/cos²θ is tan²θ and by the Pythagorean identity (1-cos²θ) is sin²θ.
  9. 9. QED
  10. 10. QED
  11. 11. Method # 2: Line of Separation / “Great Wall of China” Working with both sides can also work:
  12. 12. 1} Here we can say that tan²θ is equal to sin²θ/cos²θ. ~by saying that, it can be simplified to 1/cos²θ. 1} [Right Side]
  13. 13. 2} 2} Here we recognize cosθ-cos³θ as cosθ - (cosθcos²θ) or cosθ - cosθ (1-sin²θ). Also, tanθ as sinθ/cosθ. [Left Side]
  14. 14. 3} 3} In this step we can multiply cosθ by (1-sin²θ).
  15. 15. 4} 4} By multiplying by the reciprocal of sinθ/cosθ we can see that when cosθ gets multiplied out, we get cos²θ-cos²θ+sin²θcosθ. The two cos²θ’s cancel and you’re left with sin²θcosθ.
  16. 16. 5} 5} In this last step we see that sin²θcosθ/sinθ leaves us sinθcosθ. The sinθ’s reduce leaving us 1/cosθ.
  17. 17. QED
  18. 18. QED
  19. 19. Identities Identities Identities Identities Identities

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