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# 11.8 probabilities of disjoint and overlapping events

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### 11.8 probabilities of disjoint and overlapping events

1. 1. 11.8 Probabilities of Disjoint and Overlapping Events esson Title: 11.8 Probability of Disjoint and Overlapping Events Lesson Title: 11.8 Probability of Disjoint and OverlappingObjective: The students will be able to find the probability that Events vent A or B occurs.Method: April 26, 2011 Objective: The students will be able to find the probability that event A or B occurs. 1. Show the students how to use a venn diagram to explain Method: how events occur. Show the difference between disjoint 1. Review the homework with the students. events and overlapping events. 2. Allow the students to ask any questions that they 2. Next have the students complete an example where they may have from the homework. have to decide whether two events are disjoint or 3. Go over more practice problems with the students. overlapping. A: 11.8 odd 3. Explain to the students how to find the probability of disjoint events. 4. Next, explain to the students how to find the probability of overlapping events. 5. Lastly, explain complementary events. Show the students how to find the probability of complementary events. 6. Give the students several examples to practice. : 11.8 even
2. 2. Disjoint Events or Mutually ExclusiveEvents: events that have no commonoutcomes.
3. 3. Disjoint Events or Mutually ExclusiveEvents: events that have no commonoutcomes. Overlapping Events: events that haveone or more outcomes in common.
4. 4. Example 1:
5. 5. Example 1:
6. 6. Example 1:
7. 7. Example 2:
8. 8. Example 2:
9. 9. Example 3:
10. 10. Example 3:
11. 11. Two events are complementaryevents if they are disjoint events and oneevent or the other must occur.
12. 12. Two events are complementaryevents if they are disjoint events and oneevent or the other must occur. The sum of the probabilities of t wo complementary events is 1.
13. 13. Two events are complementaryevents if they are disjoint events and oneevent or the other must occur. P(not A) = 1 - P(A) The sum of the probabilities of t wo complementary events is 1.
14. 14. Example 4:
15. 15. Example 4: