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- 1. DegreesSl. Level of Test Formula ofNo. Significance Freedom Chi Square Test Test for As per given in1 Goodness of the question or (n-1) Fit: else 0.05. E= Test for independence As per given in2. the question or (r-1)(c-1) of attributes E= else 0.05. T-Test As per given in t= Test for Single the question or Mean else 0.05.3 (n-1) S= (Depends on the type of tail of test) As per given in t= Test for the question or difference else 0.05.4 (m+n-2) mean (Depends on the S= type of tail of test) t= As per given in Test for Paired the question or5 (n-1) t Test else 0.05. S= (Depends on thePraveenKumar Keskar 1
- 2. type of tail of test) F – Test f= if, or (m-1,n-1) Test for6 0.05. or Variance f= if, (n-1,m-1) Z – Test Test for Single Z= 0.05 = 1.967 mean Or Nil 0.01 = 2.58 Test for Z= 0.05 = 1.968 difference of Or Nil mean 0.01 = 2.58 Test for Z= 0.05 = 1.969 Or Nil proportion 0.01 = 2.58 Z= Test for 0.05 = 1.9610 difference of Or Nil proportion 0.01 = 2.58 P= Run Test Z= 0.05 = 1.9611 Run Test Or Nil E= 0.01 = 2.58PraveenKumar Keskar 2
- 3. =PraveenKumar Keskar 3

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