Definition of oxidation

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  • 3 things I like:
    - good use of mnemonics
    - SUPER LOVE CHIP AND DALE!
    - Thanks for the video!

    2 things that can be improved:
    - Explore oxidation and reduction in terms of hydrogen and electron gain/loss
    - On slide 8, would be good to superscript the charges so it is clearer for the reader

    1 question:
    - Mannnnnny questions. Try my quiz!

    Good job at verifying your facts!
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  • 3 things i like:detailed information,lots of pictures and enough words.2 to improve more pic and more explanation.I question none-kian leong
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  • 3 things i like:

    a lot of pictures

    different fonts

    LEOGER

    2 areas to be improved on:

    more pictures relavant to the topic

    brighter background

    1 question:

    the LEOGER is found on the internet or by yourselves? Jeremy
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  • 3 things i like - there video theres is little words in a slide there is vivd infomation 2 things to be improve-vary background,more pictures?

    1 question none 7-8/10 edwin
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  • Useful pictures, interesting texts, funny at times. excessive use of pictures and can get pretty stale. where did you get this info from? no errors. -Syakiran Group B
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Definition of oxidation

  1. 1. Oxidation is gain of
  2. 2. Definition of Reduction
  3. 3. ExAmPle
  4. 4. Hard tO Remember? LEOLose Electrons in OxidationGain Electrons in Reduction
  5. 5. VIDEO!!http://www.youtube.com/watch?v=dxlWtsFinT M
  6. 6. FUN F@CTS!-My name is BOND…Convalent Bond!:D-When an atom or molecule combines with oxygen, it tends to give up electrons to the oxygen in forming a chemical bond.
  7. 7. Pls click to the next pg, thank you
  8. 8. For example, in the reaction (unbalanced),MnO4- + H+ -> Mn2+ + H2Othe oxidation of Mn goes from +7 to +2. Thus, Mnis reduced. In the following reaction (unbalanced),H2C2O4 + O2 -> CO2 + H2O C is oxidized, because its oxidation statethe elementchanges from +3 to +4 in the reaction.
  9. 9. The oxidation state of an uncombinedelement is .Thatsobviously so, because it hasnt beeneither oxidised or reduced yet! The sum of the oxidation states of all the atoms or ions in a neutral compound is zero.
  10. 10. • First determine what the oxidation numbers of your known atoms are.• we know the oxidation number for H is +1.• Then set this value equal to the overall net charge of the ion.• In this case, it is +1.• Our equation now looks like this: 1(4) = 1, You use the multiplier of 4 to indicate that the ammonium ion has 4 hydrogen.• Next substitute a variable in the equation for the missing oxidation number:• +1(4) + N = +1• Solve for N.• +1(4) + N = +1• N + 4 = +1• N = +1 - 4• N = -3• Thus, the oxidation number for Nitrogen is -3.
  11. 11. CREDITS:

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