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CHM16017 - 2023-01-16T144658.475.pptx

  1. Phase Equilibrium B. Sc. VI Semister Physical Chemistry By Dr. Anjali Acharya Institute for Excellence in Higher Education Bhopal
  2. Contents •Phase equilibrium •Statement and meaning of terms C,P, F •Darivation of Gibb’ s Phase Rule •One component system,
  3. Phase Transformation प्रावस्था रूपाांतरण 1. For Heterogeneous System ववषमाांग तांत्रां 2. Transfermation of phases रूप पररवततन 3. Diagramatic reprepresentation प्रावस्था आलेख़
  4. Phases - प्रावस्था Solid ठरस Liquid तरल Gaseous गैस
  5. Tools Variables- Temperature ताप Pressure दाब Composition सांध्रता Volume आयतन
  6. Gibb’s Phase Rule F = Degree of Freedom स्वांत्ता की करवि Diagrammatic representation आलेख वित् F = C – P + 2 C = Component घिक P = Phase प्रावस्था
  7. Definition – पररभाषा Phase – Physically distinct and mechanically separable part of Heterogeneous system भौवतक रूप से सुस्पष्ट एवां याांवत्क वववि से अलग हरने वाले भाग कर प्रावस्था कहते है.
  8. Definition – पररभाषा Component – minimum number of phases required to explain composition of each phase chemically is known as the component. घिक - प्रावस्थाओ की कमतर सांख्या विस से प्रत्येक अवस्था कर एक रासायवनक सूत् वदया िा सक े , घिक कहलाता है.
  9. Definition – पररभाषा Degree of freedom – minimum number of variables to explain phase diagram is called as degree of freedom. स्वतांत्ता की करवि - पररवती अवयव की आवश्यक सांख्या विस से पूणत प्रावस्था आलेख समझाया िा सक े स्वतांत्ता की करवि कहलाता है .
  10. Phase Equilibrium Example Water system Sulphur system Carbondioxide System Calcium Carbonete Ammonium Chloride Alloys – Pb-Ag Zn- Mg
  11. Example - Water system Number of component = 1 = H2O Number of phases 3 Ice Liquid Vapour
  12. Sulphur system Number of phases – Four SR SM Sl Sv Component = 1 i.e. S
  13. Calcium Carbonate Phases –3 Solid CaCO3 Solid CaO Gaseous CO2 CaCO3 CaO + CO2 Number of component = 2 because at least two phases required to give chemical formula for each phase
  14. Darivation of Gibb’s Phase Rule For heterogeneous system if components represented by 1,2,3 and phases are a,b,c Chemical potential (µ ) for each phase is given by – (µ1a ) , (µ2a ) , (µ3a ) , (µ1b ), (µ2b) , (µ3b ) , (µ1c) , (µ2c ) , (µ3c )
  15. Darivation of Gibb’s Phase Rule According to Gibb’s Duhem Equation ∑ µ dn = 0 (µ1a ) = (µ1b ) = (µ1c) = (µ1P) (µ2a =(µ2b) = (µ3c ) = µ2P (µ3a = (µ3b ) = (µ3c ) = µ3P = µcP number of independent equation = C ( P – 1)
  16. Darivation of Gibb’s Phase Rule Each phase contain all the C components. To define composition of each phase C – 1 concentration should be specified at constant P and T . Total number of variable = P ( C – 1) + 2 -----------( eq.1) Number of equations = C ( P -1) ------------------------ ( eq 2) F = eq.1 – eq.2 F = P ( C -1 ) +2 – C (P -1) F = PC –P + 2 – CP + C F= C – P + 2 -------------------- Phase Rule
  17. One Component sustem एक घिक का तांत् Water system िल तांत् Phases / प्रावस्था– •Ice बर् त •liquid द्रव H2O •Vapours वाष्प F = C – P + 2 Phase Rule प्रावस्था वनयम C = 1 P = 1 Therfore 1 – 1 + 2 = 2
  18. 0oC T 100oC A O B C Critical T Critical P Vaporization curve Sublimation curve 217.5 Atm 374oC .0075oC Tripal point 4.58mm Supersublimation curve Melting point curve P P-T Diagram Water system प्रावस्थ आलेख Phase rule digram – P – T Diagra
  19. 0oC T 100oC A O B C Critical T Critical P Vaporization curve Sublimation curve 217.5 Atm 374oC .0075oC Triple point 4.58mm Super sublimation curve Melting point curve P P-T Diagram Water system प्रावस्थ आलेख Phase rule digram – P – T Diagra A’ Vapours Liquid Ice Super cool
  20. प्रावस्थ आलेख Phase rule digram – P – T Diagrame S.No. Curve Name Phases F = C – P +2 D.F. = F 1 AO Sublimation curve ICE and Vapours = 1 – 2 + 2 1, Mono variant, uni variant 2 BO Vaporisation curve Liquid and Vapours = 1 – 2 + 2 1, Mono variant, uni variant 3 CO Melting point curve of water Ice and liquid = 1 – 2 + 2 1, Mono variant, uni variant 4 A. O Super sublimation curve Ice and super cold water = 1 – 2 + 2 Curve s
  21. प्रावस्थ आलेख Phase rule digram – P – T Diagram S.No. Point Name Phases Temperatu re Pressure D.F. 1 O Triple Point Ice, liquid Vapours .0075 0 C 4.58 mm F = 1 - 3 + 2 = 0 Invaria nt Point
  22. प्रावस्था आलेख Phase rule digram – P – T Diagram S.No . Name Phases D.F.( F = C – P +2) D.F. 1 Out side AOC Ice F = 1 -1 +2 2, Bivariant 2 BELOW AOB Vapours F = 1 -1 +2 2, Bivariant 3 Above COB Liquid, water F = 1 -1 +2 2, Bivariant 4 AOA’ Super cooled liquid, water F = 1 -1 +2 2, Bivariant Areas
  23. Carbon dioxide System No. of Phases Solid ice Liquid Gas
  24. Carbon dioxide System 1. त्रिक त्र िंदु पर कौन सी प्रावस्था होगी ? 2. प्रावस्था आलेख में वकतने वक्र है एवां उनक े F का मान हरगा ------ 3. वत्क वबांदु वकस ताप और दाप पर है एवां F का मान ------?
  25. One component एक घिक का तांत् Sulphur system सल्फर तांत् Phases - प्रवास्थाये Sm Sulphur monoclinic SR Sulphur Rhombic Sl Sulphur Liquid SV Sulphur Vapour Example Polymorphysim S – S Tronsformation Meaning – in solid phase two types of crystalline structure
  26. Components All the four phases can be represented by the only chemical individual “ SULPHUR” itself. Hence an one component system - Phase Rule F = C – P + 2
  27. Phase Transfermation 368.5 K SR Sm 388 K 393 K Sl 717.7 K Sv
  28. 0.03mm 0.04mm 1288 atm .0006mm A B C D E M.P. curve of SR F SR G SM SL 368.5OK 388OK 393OK 428OK S Vapor T P P-T Diagram Sulphur System
  29. 0.03mm 0.04mm 1288 atm Transition curve Vapor pressure curve of SR .0006mm A B C D E Sublimation curve of SM Vapor pressure curve of SL M.P. curve of SM M.P. curve of SR F SR G SM SL 368.5OK 388OK 393OK 428OK S Vapor T P P-T Diagram Sulphur System
  30. Sulpher system सल्फर तांत् Curves / वक्र S. No Curve Name Phases Degree of Freedom ( F) 1 A B vapour presure curve of SR SR का वाष्पदाब वक्र SR and SV 1 univariant एक िर 2 BC Sublimation curve of SM उर्ध्तपातन वक्र SM and SV 1 univariant एक िर 3 CD vapour pracure curve of SL वाष्प दाब वक्र SL and SV 1 univariant एक िर 4 BE transition curve of SR रूपाांतरण वक्र SR and SM 1 univariant एक िर 5 CE Melting point curve of SM SM का गलनाांक वक्र SM and SL 1 univariant एक िर 6 EF Melting point curve of SR SR का गलनाांक वक्र SR and SL Melting point curve of SM SM का गलनाांक वक्र
  31. Sulpher system सल्फर तांत् S. No Point s Name Phases Tempratu re Pressure D.F.( F) 1 B Triple Point वत्क वबांदु SR- SM-SV 368.5 K .0006 mm 0 invariant अिर 2 C TriplePoint वत्क वबांदु SM- SL –SV 393 K 0.04 mm 0 invariant अिर 3 E Triple Point वत्क वबांदु SR-SM –SL 428 K 1288 mm 0 invariant अिर 4 G Meta StableTriple Point वत्क वबांदु SM – SL –SV 388 K 0.03 mm 0 invariant अिर Triple Points / वत्क वबांदु
  32. Sulpher system सल्फर तिंि S. No Area क्षेत् phase F = C – P +2 D.F ( F) 1 Below ABCD SV 1-1+2 = 2 2 Above ABEF SR 1-1+2 =2 3 Between DCEF SL 1-1+2 =2 4 Inside BCE SM 1-1+2 =2 Area क्षेत्
  33. Expected Questions 1. पाररभावषत कीविए –a . प्रावस्था b घिक c. स्वतांत्ता की करवि 2. एक घिक का तांत् िल अथवा सल्फर का प्रावस्था आलेख बनाएां . 3. वगब्स’ क े प्रावस्था वनयम की उत्पवि कीविये . 4. वकसी प्रावस्था आलेख में F का वनिातरण क ै से वकया िाता है ? 5. वक्र, वबांदु एवां क्षेत् की स्वतांत्ता की करवि क्या हरती है ?
  34. Dr. Anjali Acharya Email- anjaliacharya2007@rediffmail.com
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