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Introduction to Vectors 
Week 1, Lesson 2 
• Vectors & Scalar Quantities 
• Addition of Vectors 
• Graphical Addition 
• Parallelogram Method 
• Rectangular Components 
• Subtraction of Vectors 
References/Reading Preparation: 
Schaum’s Outline Ch. 1 
Principles of Physics by Beuche – Ch.1 
Week 1, Lesson 2 Introduction to Vectors 1
 Scalar Quantities 
Whenever we measure a quantity, we express our result in terms 
of a number. 
For example, there are 50 students in this class. 
This quantity has both a Numerical value (50), and 
A unit of measure (persons) 
We can measure our height (165 cm, or 65 in or 5.4 ft) 
In all cases, the quantity has a magnitude and a unit of measure – 
there is no direction associated with them. 
Week 1, Lesson 2 Introduction to Vectors 2
Quantities that have no direction associated with 
them are called Scalar Quantities. 
Week 1, Lesson 2 Introduction to Vectors 3
 Vector Quantities 
In contrast, a vector quantity has both a magnitude and a direction. 
For example, motion is a quantity that involves direction as well as 
magnitude – such as a car traveling 40 km/h eastward. 
Other vector quantities are forces and the movement one must 
undergo to travel from one city to another. 
Week 1, Lesson 2 Introduction to Vectors 4
A vector quantity can be represented by an arrow drawn to scale. 
For example, 40 km/h eastward can be represented by and arrow 
drawn to scale pointing east: 
10 20 30 40 km/h 
The length of the arrow is proportional to the magnitude of the 
vector quantity. 
The direction of the arrow represents the direction of the vector 
quantity. 
Week 1, Lesson 2 Introduction to Vectors 5
 Vector Addition 
The sum of two scalars is simply the sum of their two magnitudes – 
they add numerically. 
i.e : Adding 1600cm3 of water to 200cm3 of water gives 1800cm3. 
Vector quantities do not add this way. 
Example: 30.0 km east plus 10.0 km north 
C We are interested in the total 
Resultant 
A 30.0 km east 
B 
10.0 km north 
displacement resulting 
from these two displacements-the 
displacement from A to C. 
This displacement is called the Resultant displacement. 
Note: its magnitude is 302 102  31.6km  32km 
Week 1, Lesson 2 Introduction to Vectors 6
 Graphical Addition 
Example – Find the resultant of 10 km east, 16 km south, 14 km 
east, 6 km north and 4 km west. 
Solution: We can solve this graphically by drawing each vector to scale and 
successively adding them to find the resultant vector. 
10 km 
Resultant - R 
16 km 
The result of adding vectors does 
not depend on the order in which 
you add them. 
4 km 
14 km 
6 km 
The resultant displacement 
extends from the tail of the 
First vector to the tip of the 
last vector. 
Week 1, Lesson 2 Introduction to Vectors 7
 Parallelogram Method for Adding Two Vectors 
For two vectors acting at an any angle, the resultant can be 
represented by the diagonal of a parallelogram. 
Resultant - R 
Week 1, Lesson 2 Introduction to Vectors 8
 Vector Subtraction 
To subtract a vector, reverse the direction of the one being 
subtracted, then add. 
For example, to subtract vector B from vector A, reverse the 
direction of B and then add it to A . 
In math terms: A – B = A + (-B) 
A 
10 m 
Vector A 
B 6 m 
Vector B 
A 
10 m 
6 m - B 
R 
Week 1, Lesson 2 Introduction to Vectors 9
 Rectangular Components of Vectors 
Although the graphical method for adding vectors is simple and 
straightforward, it is cumbersome and only as accurate as our 
scale drawings. 
Therefore, another method is needed that that does not have these 
drawbacks. 
First, we must learn how to find rectangular components. 
Week 1, Lesson 2 Introduction to Vectors 10
Suppose we have the following vector. 
B 
 
This vector can be replaced 
by two component vectors. 
B 
Bx 
By 
 
The displacement vector B can 
be replaced by the two vectors 
A and C which are at right angles 
to each other. 
We call these two vectors the Rectangular Components of the original vector. 
Week 1, Lesson 2 Introduction to Vectors 11
Before we go further, let’s review the simple trigonometric 
functions of a right triangle. 
c a 
b 
90 
 
sin  = 
opposite side 
hypotenuse = 
a 
c 
cos  = 
adjacent side 
hypotenuse = 
b 
c 
tan  = 
opposite side 
adjacent side = 
a 
b 
It follows from these equations that the two sides can be found if we know the 
hypotenuse and one angle. 
a = csin b = ccos 
Week 1, Lesson 2 Introduction to Vectors 12
Week 1, Lesson 2 Introduction to Vectors 13
Let us apply this to finding the components of a vector. 
The following figure shows a 20 cm displacement that makes an 
angle of 37 with the x-axis. 
c = 20 cm 
cy 
37 x-axis 
cx 
This vector c is equivalent to the vector sum of the two component 
vectors cx and cy. 
Where: cx = c cos 37 = (20 cm)(0.80) = 16 cm 
cy = c sin 37 = (20 cm)(0.60) = 12 cm 
Week 1, Lesson 2 Introduction to Vectors 14
The 20 cm displacement at an angle of 37 to the x-axis is equivalent 
to the sum of two rectangular component vectors: 
cx = 16 cm in the positive x-direction, and 
cy = 12 cm in the positive y-direction 
It is possible in this way to to replace any vector by its rectangular 
components – in this way it is a simple matter to add, or subtract, 
vectors of all types. 
Week 1, Lesson 2 Introduction to Vectors 15
 Component Method for Adding Vectors 
Each vector is resolved into its x-, y- and z-components, with negative 
directed components taken as negative. 
The x-component Rx of the resultant vector R is the algebraic sum 
of all the x-components. The y- and z-components of the resultant 
are found in a similar way. 
With the components known, the magnitude of the resultant is 
given by: 
R = (Rx 
2 + Ry 
2 + Rz 
2) 
In two dimensions, the angle of the resultant with the x-axis is: 
Tan  = Ry/Rx 
Week 1, Lesson 2 Introduction to Vectors 16
Example: 
Five coplanar forces act on an object as shown. Find 
their component. 
x-axis 
y - axis 
15 N 
19 N 
40 
16 N 
45 
22 N 
30 
10 N 
Week 1, Lesson 2 Introduction to Vectors 17
Solution: 
Vector x-component y-component 
19 N 
15 N 
16 N 
22 N 
10 N 
Week 1, Lesson 2 Introduction to Vectors 18

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Introduction to Vectors

  • 1. Introduction to Vectors Week 1, Lesson 2 • Vectors & Scalar Quantities • Addition of Vectors • Graphical Addition • Parallelogram Method • Rectangular Components • Subtraction of Vectors References/Reading Preparation: Schaum’s Outline Ch. 1 Principles of Physics by Beuche – Ch.1 Week 1, Lesson 2 Introduction to Vectors 1
  • 2.  Scalar Quantities Whenever we measure a quantity, we express our result in terms of a number. For example, there are 50 students in this class. This quantity has both a Numerical value (50), and A unit of measure (persons) We can measure our height (165 cm, or 65 in or 5.4 ft) In all cases, the quantity has a magnitude and a unit of measure – there is no direction associated with them. Week 1, Lesson 2 Introduction to Vectors 2
  • 3. Quantities that have no direction associated with them are called Scalar Quantities. Week 1, Lesson 2 Introduction to Vectors 3
  • 4.  Vector Quantities In contrast, a vector quantity has both a magnitude and a direction. For example, motion is a quantity that involves direction as well as magnitude – such as a car traveling 40 km/h eastward. Other vector quantities are forces and the movement one must undergo to travel from one city to another. Week 1, Lesson 2 Introduction to Vectors 4
  • 5. A vector quantity can be represented by an arrow drawn to scale. For example, 40 km/h eastward can be represented by and arrow drawn to scale pointing east: 10 20 30 40 km/h The length of the arrow is proportional to the magnitude of the vector quantity. The direction of the arrow represents the direction of the vector quantity. Week 1, Lesson 2 Introduction to Vectors 5
  • 6.  Vector Addition The sum of two scalars is simply the sum of their two magnitudes – they add numerically. i.e : Adding 1600cm3 of water to 200cm3 of water gives 1800cm3. Vector quantities do not add this way. Example: 30.0 km east plus 10.0 km north C We are interested in the total Resultant A 30.0 km east B 10.0 km north displacement resulting from these two displacements-the displacement from A to C. This displacement is called the Resultant displacement. Note: its magnitude is 302 102  31.6km  32km Week 1, Lesson 2 Introduction to Vectors 6
  • 7.  Graphical Addition Example – Find the resultant of 10 km east, 16 km south, 14 km east, 6 km north and 4 km west. Solution: We can solve this graphically by drawing each vector to scale and successively adding them to find the resultant vector. 10 km Resultant - R 16 km The result of adding vectors does not depend on the order in which you add them. 4 km 14 km 6 km The resultant displacement extends from the tail of the First vector to the tip of the last vector. Week 1, Lesson 2 Introduction to Vectors 7
  • 8.  Parallelogram Method for Adding Two Vectors For two vectors acting at an any angle, the resultant can be represented by the diagonal of a parallelogram. Resultant - R Week 1, Lesson 2 Introduction to Vectors 8
  • 9.  Vector Subtraction To subtract a vector, reverse the direction of the one being subtracted, then add. For example, to subtract vector B from vector A, reverse the direction of B and then add it to A . In math terms: A – B = A + (-B) A 10 m Vector A B 6 m Vector B A 10 m 6 m - B R Week 1, Lesson 2 Introduction to Vectors 9
  • 10.  Rectangular Components of Vectors Although the graphical method for adding vectors is simple and straightforward, it is cumbersome and only as accurate as our scale drawings. Therefore, another method is needed that that does not have these drawbacks. First, we must learn how to find rectangular components. Week 1, Lesson 2 Introduction to Vectors 10
  • 11. Suppose we have the following vector. B  This vector can be replaced by two component vectors. B Bx By  The displacement vector B can be replaced by the two vectors A and C which are at right angles to each other. We call these two vectors the Rectangular Components of the original vector. Week 1, Lesson 2 Introduction to Vectors 11
  • 12. Before we go further, let’s review the simple trigonometric functions of a right triangle. c a b 90  sin  = opposite side hypotenuse = a c cos  = adjacent side hypotenuse = b c tan  = opposite side adjacent side = a b It follows from these equations that the two sides can be found if we know the hypotenuse and one angle. a = csin b = ccos Week 1, Lesson 2 Introduction to Vectors 12
  • 13. Week 1, Lesson 2 Introduction to Vectors 13
  • 14. Let us apply this to finding the components of a vector. The following figure shows a 20 cm displacement that makes an angle of 37 with the x-axis. c = 20 cm cy 37 x-axis cx This vector c is equivalent to the vector sum of the two component vectors cx and cy. Where: cx = c cos 37 = (20 cm)(0.80) = 16 cm cy = c sin 37 = (20 cm)(0.60) = 12 cm Week 1, Lesson 2 Introduction to Vectors 14
  • 15. The 20 cm displacement at an angle of 37 to the x-axis is equivalent to the sum of two rectangular component vectors: cx = 16 cm in the positive x-direction, and cy = 12 cm in the positive y-direction It is possible in this way to to replace any vector by its rectangular components – in this way it is a simple matter to add, or subtract, vectors of all types. Week 1, Lesson 2 Introduction to Vectors 15
  • 16.  Component Method for Adding Vectors Each vector is resolved into its x-, y- and z-components, with negative directed components taken as negative. The x-component Rx of the resultant vector R is the algebraic sum of all the x-components. The y- and z-components of the resultant are found in a similar way. With the components known, the magnitude of the resultant is given by: R = (Rx 2 + Ry 2 + Rz 2) In two dimensions, the angle of the resultant with the x-axis is: Tan  = Ry/Rx Week 1, Lesson 2 Introduction to Vectors 16
  • 17. Example: Five coplanar forces act on an object as shown. Find their component. x-axis y - axis 15 N 19 N 40 16 N 45 22 N 30 10 N Week 1, Lesson 2 Introduction to Vectors 17
  • 18. Solution: Vector x-component y-component 19 N 15 N 16 N 22 N 10 N Week 1, Lesson 2 Introduction to Vectors 18