WATS 3 (1-50) Fluid Mechanics and Thermodynamics

704 views

Published on

The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information.
The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution.

What follows is a set of STUDENT UNIQUE SHEETS for WATS 3.

Published in: Education, Technology
0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total views
704
On SlideShare
0
From Embeds
0
Number of Embeds
3
Actions
Shares
0
Downloads
18
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

WATS 3 (1-50) Fluid Mechanics and Thermodynamics

  1. 1. Fluid Mechanics and Thermodynamics<br />Weekly Assessed Tutorial Sheets<br />Student Sheets: WATS 3.<br />The WATS approach to assessment was developed as part of an LTSN Engineering Mini-Project, funded at the University of Hertfordshire which aimed to develop a set of 'student unique' tutorial sheets to actively encourage and improve student participation within a first year first ‘fluid mechanics and thermodynamics’ module. Please see the accompanying Mini-Project Report “Improving student success and retention through greater participation and tackling student-unique tutorial sheets” for more information.<br />The WATS cover core Fluid Mechanics and Thermodynamics topics at first year undergraduate level. 11 tutorial sheets and their worked solutions are provided here for you to utilise in your teaching. The variables within each question can be altered so that each student answers the same question but will need to produce a unique solution.<br />FURTHER INFORMATION<br />Please see http://tinyurl.com/2wf2lfh to access the WATS Random Factor Generating Wizard. <br />There are also explanatory videos on how to use the Wizard and how to implement WATS available at http://www.youtube.com/user/MBRBLU#p/u/7/0wgC4wy1cV0 and http://www.youtube.com/user/MBRBLU#p/u/6/MGpueiPHpqk.<br />For more information on WATS, its use and impact on students please contact Mark Russell, School of Aerospace, Automotive and Design Engineering at University of Hertfordshire.<br /> <br /> <br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number1NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.66 has a downward slope of 1 in 55. At point ‘A’ in the pipe the static (gauge) pressure is 1325 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 90 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 62 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.70cm diameter pipe rising directly from an open tank to a height of 2.80m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.20m below point A. Assuming the fluid has a relative density of 0.97 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.79 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.18m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number2NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.64 has a downward slope of 1 in 35. At point ‘A’ in the pipe the static (gauge) pressure is 525 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 96 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 20 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.90cm diameter pipe rising directly from an open tank to a height of 3.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.00m below point A. Assuming the fluid has a relative density of 0.67 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.70 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.34m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number3NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.87 has a downward slope of 1 in 50. At point ‘A’ in the pipe the static (gauge) pressure is 1450 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 86 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 58 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 1.60cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.20m below point A. Assuming the fluid has a relative density of 0.69 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.99 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.81m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number4NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.67 has a downward slope of 1 in 70. At point ‘A’ in the pipe the static (gauge) pressure is 875 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 50 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 76 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.30cm diameter pipe rising directly from an open tank to a height of 1.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.70m below point A. Assuming the fluid has a relative density of 0.91 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.58 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.91m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number5NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.78 has a downward slope of 1 in 65. At point ‘A’ in the pipe the static (gauge) pressure is 1400 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 84 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 98 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.00cm diameter pipe rising directly from an open tank to a height of 2.10m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.80m below point A. Assuming the fluid has a relative density of 0.84 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.61 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.39m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number6NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.77 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 1325 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 48 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 12 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.00cm diameter pipe rising directly from an open tank to a height of 3.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.20m below point A. Assuming the fluid has a relative density of 0.81 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.57 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.33m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number7NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.89 has a downward slope of 1 in 45. At point ‘A’ in the pipe the static (gauge) pressure is 725 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 70 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 80 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 2.30cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.20m below point A. Assuming the fluid has a relative density of 0.89 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.91 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.34m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number8NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.92 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 1400 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 10 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 34 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.60cm diameter pipe rising directly from an open tank to a height of 4.40m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.10m below point A. Assuming the fluid has a relative density of 0.75 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.72 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.26m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number9NameHand out dateHand in date<br />Q1. A 2cm diameter pipe conveying a fluid of relative density 0.64 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 1175 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 64 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 18 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.80cm diameter pipe rising directly from an open tank to a height of 1.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 15.00m below point A. Assuming the fluid has a relative density of 0.63 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.83 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.01m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number10NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.66 has a downward slope of 1 in 55. At point ‘A’ in the pipe the static (gauge) pressure is 525 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 72 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 82 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 2.80cm diameter pipe rising directly from an open tank to a height of 3.60m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.40m below point A. Assuming the fluid has a relative density of 0.80 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.79 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.39m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number11NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.67 has a downward slope of 1 in 55. At point ‘A’ in the pipe the static (gauge) pressure is 700 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 36 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 78 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.00cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.80m below point A. Assuming the fluid has a relative density of 0.96 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.86 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.95m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number12NameHand out dateHand in date<br />Q1. A 7cm diameter pipe conveying a fluid of relative density 0.94 has a downward slope of 1 in 65. At point ‘A’ in the pipe the static (gauge) pressure is 950 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 50 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 52 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 1.80cm diameter pipe rising directly from an open tank to a height of 1.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.90m below point A. Assuming the fluid has a relative density of 0.74 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.63 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.91m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number13NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.88 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 800 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 44 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 70 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.10cm diameter pipe rising directly from an open tank to a height of 1.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.90m below point A. Assuming the fluid has a relative density of 0.82 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.60 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.82m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number14NameHand out dateHand in date<br />Q1. A 7cm diameter pipe conveying a fluid of relative density 0.70 has a downward slope of 1 in 50. At point ‘A’ in the pipe the static (gauge) pressure is 1350 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 40 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 24 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 3.50cm diameter pipe rising directly from an open tank to a height of 4.40m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.80m below point A. Assuming the fluid has a relative density of 0.91 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.80 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.35m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number15NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.92 has a downward slope of 1 in 45. At point ‘A’ in the pipe the static (gauge) pressure is 850 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 98 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 66 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.60cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.90m below point A. Assuming the fluid has a relative density of 0.82 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.83 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.91m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number16NameHand out dateHand in date<br />Q1. A 9cm diameter pipe conveying a fluid of relative density 0.91 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 1350 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 34 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 78 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 7.50cm diameter pipe rising directly from an open tank to a height of 1.60m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 8.60m below point A. Assuming the fluid has a relative density of 0.86 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.74 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.94m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number17NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.78 has a downward slope of 1 in 75. At point ‘A’ in the pipe the static (gauge) pressure is 1100 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 70 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 42 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.90cm diameter pipe rising directly from an open tank to a height of 1.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.10m below point A. Assuming the fluid has a relative density of 0.79 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.82 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.81m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number18NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.91 has a downward slope of 1 in 35. At point ‘A’ in the pipe the static (gauge) pressure is 1450 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 94 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 40 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.40cm diameter pipe rising directly from an open tank to a height of 2.20m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 13.50m below point A. Assuming the fluid has a relative density of 0.86 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.58 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.19m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number19NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.68 has a downward slope of 1 in 45. At point ‘A’ in the pipe the static (gauge) pressure is 525 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 62 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 78 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.40cm diameter pipe rising directly from an open tank to a height of 1.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.80m below point A. Assuming the fluid has a relative density of 0.89 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.67 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.22m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number20NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.74 has a downward slope of 1 in 45. At point ‘A’ in the pipe the static (gauge) pressure is 1100 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 26 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 46 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.40cm diameter pipe rising directly from an open tank to a height of 4.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.70m below point A. Assuming the fluid has a relative density of 0.67 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.64 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.94m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number21NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.73 has a downward slope of 1 in 70. At point ‘A’ in the pipe the static (gauge) pressure is 1150 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 84 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 42 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.80cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.00m below point A. Assuming the fluid has a relative density of 0.90 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.85 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.11m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number22NameHand out dateHand in date<br />Q1. A 2cm diameter pipe conveying a fluid of relative density 0.77 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 1200 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 50 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 72 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.80cm diameter pipe rising directly from an open tank to a height of 2.60m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.80m below point A. Assuming the fluid has a relative density of 0.87 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.92 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.81m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number23NameHand out dateHand in date<br />Q1. A 3cm diameter pipe conveying a fluid of relative density 0.62 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 550 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 14 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 28 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.60cm diameter pipe rising directly from an open tank to a height of 2.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 8.70m below point A. Assuming the fluid has a relative density of 0.76 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.82 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.00m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number24NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.68 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 700 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 64 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 94 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 7.00cm diameter pipe rising directly from an open tank to a height of 4.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 11.80m below point A. Assuming the fluid has a relative density of 0.69 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.85 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.19m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number25NameHand out dateHand in date<br />Q1. A 2cm diameter pipe conveying a fluid of relative density 0.96 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 675 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 52 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 78 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.80cm diameter pipe rising directly from an open tank to a height of 1.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.30m below point A. Assuming the fluid has a relative density of 0.79 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.78 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.06m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number26NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.93 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 1400 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 86 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 22 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 1.00cm diameter pipe rising directly from an open tank to a height of 2.20m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 13.10m below point A. Assuming the fluid has a relative density of 0.65 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.61 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.93m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number27NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.91 has a downward slope of 1 in 70. At point ‘A’ in the pipe the static (gauge) pressure is 750 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 90 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 32 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.00cm diameter pipe rising directly from an open tank to a height of 3.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.30m below point A. Assuming the fluid has a relative density of 0.91 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.57 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.10m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number28NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.70 has a downward slope of 1 in 55. At point ‘A’ in the pipe the static (gauge) pressure is 1250 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 20 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 80 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.50cm diameter pipe rising directly from an open tank to a height of 2.60m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.70m below point A. Assuming the fluid has a relative density of 0.64 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.54 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.08m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number29NameHand out dateHand in date<br />Q1. A 3cm diameter pipe conveying a fluid of relative density 0.87 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 650 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 22 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 20 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.60cm diameter pipe rising directly from an open tank to a height of 4.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.70m below point A. Assuming the fluid has a relative density of 0.67 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.67 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.32m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number30NameHand out dateHand in date<br />Q1. A 7cm diameter pipe conveying a fluid of relative density 0.73 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 625 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 54 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 68 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.80cm diameter pipe rising directly from an open tank to a height of 3.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.20m below point A. Assuming the fluid has a relative density of 0.78 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.75 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.92m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number31NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.64 has a downward slope of 1 in 60. At point ‘A’ in the pipe the static (gauge) pressure is 1350 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 72 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 84 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 3.20cm diameter pipe rising directly from an open tank to a height of 2.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 7.00m below point A. Assuming the fluid has a relative density of 0.98 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.83 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.86m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number32NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.71 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 975 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 14 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 66 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.00cm diameter pipe rising directly from an open tank to a height of 2.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 11.20m below point A. Assuming the fluid has a relative density of 0.82 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.80 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.28m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number33NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.82 has a downward slope of 1 in 60. At point ‘A’ in the pipe the static (gauge) pressure is 725 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 64 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 92 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.90cm diameter pipe rising directly from an open tank to a height of 2.40m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.30m below point A. Assuming the fluid has a relative density of 0.83 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.82 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.20m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number34NameHand out dateHand in date<br />Q1. A 7cm diameter pipe conveying a fluid of relative density 0.72 has a downward slope of 1 in 50. At point ‘A’ in the pipe the static (gauge) pressure is 750 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 80 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 86 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.60cm diameter pipe rising directly from an open tank to a height of 3.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 11.40m below point A. Assuming the fluid has a relative density of 0.90 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 1.00 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.97m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number35NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.72 has a downward slope of 1 in 75. At point ‘A’ in the pipe the static (gauge) pressure is 550 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 64 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 22 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 2.40cm diameter pipe rising directly from an open tank to a height of 4.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.70m below point A. Assuming the fluid has a relative density of 0.75 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.85 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.80m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number36NameHand out dateHand in date<br />Q1. A 4cm diameter pipe conveying a fluid of relative density 0.76 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 575 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 94 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 16 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.60cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 13.40m below point A. Assuming the fluid has a relative density of 0.71 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.88 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.99m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number37NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.76 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 775 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 58 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 22 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.20cm diameter pipe rising directly from an open tank to a height of 4.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 15.00m below point A. Assuming the fluid has a relative density of 0.97 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.51 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.28m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number38NameHand out dateHand in date<br />Q1. A 9cm diameter pipe conveying a fluid of relative density 0.86 has a downward slope of 1 in 60. At point ‘A’ in the pipe the static (gauge) pressure is 550 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 54 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 40 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.10cm diameter pipe rising directly from an open tank to a height of 4.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.90m below point A. Assuming the fluid has a relative density of 0.79 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.76 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.19m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number39NameHand out dateHand in date<br />Q1. A 7cm diameter pipe conveying a fluid of relative density 0.97 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 1000 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 92 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 14 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.60cm diameter pipe rising directly from an open tank to a height of 2.30m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.10m below point A. Assuming the fluid has a relative density of 0.71 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.97 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.10m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number40NameHand out dateHand in date<br />Q1. A 3cm diameter pipe conveying a fluid of relative density 0.80 has a downward slope of 1 in 70. At point ‘A’ in the pipe the static (gauge) pressure is 950 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 96 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 94 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.80cm diameter pipe rising directly from an open tank to a height of 1.20m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.40m below point A. Assuming the fluid has a relative density of 0.77 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.95 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.25m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number41NameHand out dateHand in date<br />Q1. A 8cm diameter pipe conveying a fluid of relative density 0.83 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 1325 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 90 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 72 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.40cm diameter pipe rising directly from an open tank to a height of 2.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 11.00m below point A. Assuming the fluid has a relative density of 0.83 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.71 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.82m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number42NameHand out dateHand in date<br />Q1. A 9cm diameter pipe conveying a fluid of relative density 0.78 has a downward slope of 1 in 50. At point ‘A’ in the pipe the static (gauge) pressure is 1075 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 44 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 46 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 8.90cm diameter pipe rising directly from an open tank to a height of 2.40m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.40m below point A. Assuming the fluid has a relative density of 0.85 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.52 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.24m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number43NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.71 has a downward slope of 1 in 25. At point ‘A’ in the pipe the static (gauge) pressure is 1300 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 46 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 68 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 9.30cm diameter pipe rising directly from an open tank to a height of 3.70m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 13.20m below point A. Assuming the fluid has a relative density of 0.67 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.90 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.32m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number44NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.95 has a downward slope of 1 in 20. At point ‘A’ in the pipe the static (gauge) pressure is 1475 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 62 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 98 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.40cm diameter pipe rising directly from an open tank to a height of 3.90m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 12.30m below point A. Assuming the fluid has a relative density of 0.64 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.83 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.06m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number45NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.74 has a downward slope of 1 in 70. At point ‘A’ in the pipe the static (gauge) pressure is 1175 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 54 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 96 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 1.80cm diameter pipe rising directly from an open tank to a height of 3.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 11.50m below point A. Assuming the fluid has a relative density of 0.78 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.92 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.95m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number46NameHand out dateHand in date<br />Q1. A 6cm diameter pipe conveying a fluid of relative density 0.71 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 1225 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 70 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 36 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.10cm diameter pipe rising directly from an open tank to a height of 3.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 10.20m below point A. Assuming the fluid has a relative density of 0.80 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.53 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.31m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number47NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.90 has a downward slope of 1 in 30. At point ‘A’ in the pipe the static (gauge) pressure is 1500 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 10 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 74 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 4.00cm diameter pipe rising directly from an open tank to a height of 2.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 9.10m below point A. Assuming the fluid has a relative density of 0.79 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.95 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.27m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number48NameHand out dateHand in date<br />Q1. A 2cm diameter pipe conveying a fluid of relative density 0.84 has a downward slope of 1 in 40. At point ‘A’ in the pipe the static (gauge) pressure is 675 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 90 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 28 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 6.70cm diameter pipe rising directly from an open tank to a height of 2.60m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.80m below point A. Assuming the fluid has a relative density of 0.93 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.78 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.25m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number49NameHand out dateHand in date<br />Q1. A 10cm diameter pipe conveying a fluid of relative density 0.80 has a downward slope of 1 in 75. At point ‘A’ in the pipe the static (gauge) pressure is 775 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 52 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 30 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 1.20cm diameter pipe rising directly from an open tank to a height of 3.00m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 13.10m below point A. Assuming the fluid has a relative density of 0.81 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.82 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 9.86m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Fluid Mechanics and Thermodynamics.<br />Weekly Assessed Tutorial Sheet 3.<br />Student Number50NameHand out dateHand in date<br />Q1. A 5cm diameter pipe conveying a fluid of relative density 0.93 has a downward slope of 1 in 50. At point ‘A’ in the pipe the static (gauge) pressure is 1225 kN/m2. <br />Calculate – <br />i) the static gauge pressure in the pipe 58 m downstream of point A. (kN/m2) 2 marks<br />ii) the static gauge pressure in the pipe 94 m upstream of point A. (kN/m2) 2 marks<br />Q2. A siphon consists of a 5.30cm diameter pipe rising directly from an open tank to a height of 1.50m above the fluids free surface. At this point, ‘A’, the pipe bends downwards and continues to drop until point B. Point B being the siphons discharge 14.10m below point A. Assuming the fluid has a relative density of 0.62 calculate – <br />i)the velocity of the fluid in the pipe. (m/s)2 marks<br />ii)the volumetric fluid flow rate through the siphon (m3/s) 1 mark<br />iii)the mass flow rate of fluid through the siphon. (kg/s) 1 mark<br />Assume now that the length A->B changes but the height of A does not change with respect to the free surface. Assume also that that the head at point A should not fall below 0.58 m of water at 4ºC. Calculate -<br />iv) the new volumetric fluid flow rate through the siphon (m3/s) 3 marks<br />v) the new length to A->B (m) 2 marks<br />Take the atmospheric pressure as being equivalent to 10.17m head of water at 4ºC. You may assume that the density of water at 4ºC is 1000 kg/m3 and that the acceleration due to gravity is 9.81 m/s2. Pi = 3.142.<br />Credits<br />This resource was created by the University of Hertfordshire and released as an open educational resource through the Open Engineering Resources project of the HE Academy Engineering Subject Centre. The Open Engineering Resources project was funded by HEFCE and part of the JISC/HE Academy UKOER programme.<br />© University of Hertfordshire 2009<br />This work is licensed under a Creative Commons Attribution 2.0 License. <br />The name of the University of Hertfordshire, UH and the UH logo are the name and registered marks of the University of Hertfordshire. To the fullest extent permitted by law the University of Hertfordshire reserves all its rights in its name and marks which may not be used except with its written permission.<br />The JISC logo is licensed under the terms of the Creative Commons Attribution-Non-Commercial-No Derivative Works 2.0 UK: England & Wales Licence.  All reproductions must comply with the terms of that licence.<br />The HEA logo is owned by the Higher Education Academy Limited may be freely distributed and copied for educational purposes only, provided that appropriate acknowledgement is given to the Higher Education Academy as the copyright holder and original publisher.<br />

×