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Deret fourier.pptx

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Deret fourier.pptx

  1. 1. DERET FOURIER RHAKA FEBRIANDI EC 2A 1803321039
  2. 2. β€’ Contoh soal : 8 0 -4 Hitunglah an dari table berikut 0 ; 0 < π‘₯ < 2 8 ; 2 < π‘₯ < 4 βˆ’4 ; 4 < π‘₯ < 6 2 4 6 2L = 6 L = 3
  3. 3. β€’ Rumus : Type equation here. 1 𝐿 βˆ’πΏ 𝐿 𝑓 𝑑 cos π‘›πœ‹π‘‘ 𝐿 𝑑𝑑 Jawab : 1 3 0 2 𝑓 𝑑 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 + 1 3 2 4 𝑓 𝑑 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 + 1 3 4 6 𝑓 𝑑 π‘π‘œπ‘  π‘›πœ‹π‘‘ 3 𝑑𝑑 1 3 0 2 0 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 + 1 3 2 4 8 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 + 1 3 4 6 βˆ’4 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 1 3 2 4 8 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 + 4 6 βˆ’4 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 4 3 2 4 2 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 βˆ’ 4 6 cos π‘›πœ‹π‘‘ 3 𝑑𝑑 4 3 3 π‘›πœ‹ . 2 sin π‘›πœ‹ 3 𝑑 4 2 βˆ’ 3 π‘›πœ‹ . sin π‘›πœ‹ 3 𝑑 6 2 4 3 3 π‘›πœ‹ 2 sin π‘›πœ‹ 3 .4 βˆ’ sin π‘›πœ‹ 3 . 2 βˆ’ sin π‘›πœ‹ 3 . 6 βˆ’ sin π‘›πœ‹ 3 . 4
  4. 4. β€’ 4 π‘›πœ‹ 2 sin 4 3 π‘›πœ‹ βˆ’ 2 sin 2 3 π‘›πœ‹ βˆ’ sin 2π‘›πœ‹ βˆ’ sin 4 3 π‘›πœ‹ β€’ 4 π‘›πœ‹ 3 sin 4 3 π‘›πœ‹ βˆ’ 2 sin 2 3 π‘›πœ‹ βˆ’ sin 2π‘›πœ‹ sin 4 3 π‘›πœ‹ = ? n Hasil n= 1 -0,87 n = 2 0,87 n = 3 0 n = 4 -0,87 sin 2 3 π‘›πœ‹ = ? n Hasil n= 1 0,87 n = 2 -0,87 n = 3 0 n = 4 0,87
  5. 5. β€’ sin 2π‘›πœ‹ = ? n Hasil n= 1 0 n = 2 0 n = 3 0 n = 4 0

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