Alg2 lesson 7-4

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Alg2 lesson 7-4

  1. 1. Use synthetic division to divide the polynomialf(a) = 4a2 – 3a + 6 by a – 2 Quotient: 4a + 5 Remainder: 16If f(a) = 4a2 – 3a + 6, find f(2) f(2) = 4(2)2 – 3(2) + 6 = 16 – 6 + 6 Remainder Theorem = 16 If a polynomial f(x) is divided by x – a , the remainder is equal to f(a)
  2. 2. If find f (4).Method 1 Method 2Direct Substitution Synthetic Substitution 3 10 41 164 654 f (4) = 654. f (4) = 654
  3. 3. If find f(3). 3 2 -3 0 7 6 9 27 2 3 9 34 Answer: f(3) = 34
  4. 4. Show that is a factor ofThen find the remaining factors of the polynomial. The remainder is 0, so x – 3 is 1 7 6 0 a factor of the polynomial =
  5. 5. Show that is a factor ofThen find the remaining factors of the polynomial. 1 6 5 0
  6. 6. Geometry The volume of arectangular prism is givenbyFind the missing measures. lwh = 1 9 20 0The missing measures of the prism are x + 4 and x + 5.

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