accounting assignment help


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accounting assignment help

  2. 2. Thompson’s Mining & Smelting Co.Bank Ground of The studyThe company is planning to increase it’sproduction rate. The company’s refinery atWekusko is under discussion, whereproduction is planned to increase to 35000tons per week. Mr. Brian Walker, thesuperintendent of the plant had carriedout a study at the plant to ensure forachieving the target. An analysis ofoperation was carried out for maximizingthe use of available resources.Facts of the Wekusko Plant1. Location : California2. Resources Avaialble
  3. 3. a) Three Yard Shovels -3Nos. Located at different areasb) 20 Ton Trucks 12 Nos.c) Primary Crusher - 1 No.3) Opearating schedule ofthe Planta) Shift – I for 8hours:2 shovels along with 4 trucks /shovel.b) Shift – II for 8 hours1 Shovel along with 5 Trucks4. Trucks could not be switch over fromone shovel to another.5. The plant is working 5 days a week
  4. 4. 6. Capacity of Primary Crusher : 9600Tons per Shift (480 Trucks Load)ObjectivesThe Company’s objective of increasedproduction to 35000 Tons per week couldbe achieved by exploring 7000 tons of oreper day from all the shovels. whereas theCrusher is having the capacity of 9600tons per shift.Criteria1. It could be possible with thefollowing by 100% utilizing thecrusher to the best of it’s capacity,which is possible only by reducingthe waiting time for crusher, for
  5. 5. which, the waiting time of thetrucks at each shovel as tabulatedbelow, needs to be eliminated.S.No.Shovel Waitingtime forTrucks atshovel inevery roundtrip (inMinutes)Extra Costper Hourin US$ *1 1 1.17 1.362 2 -0.41 1.00* Computation of Extra Cost Per HourIn shift – I at shovel - I, the truck remains idlefor 1.17 min for every round trip, which comesto 10.74 min per hour (60/6.54*1.17) resultinginto extra cost of US$ 1.36 per hour.In shift – I at Shovel - II, the shovel remainsidle for 0.41 min for every round trip, which
  6. 6. comes to 3.03 min per hour (60/8.12*0.41)resulting into extra cost of US$ 1.00 per hour.
  7. 7. End ResultUnder the above situation the Crusheris supplied with 10601 Tons of Material(60/8.12*8*4*20+60/6.54*8*4*20)against its capacity of 9600 Tons perShift. It is not out of place to mentionhere that there is the scope ofreducing the transportation cost &Shovel Cost as attributable to the1001 Tons to line up with the capacityof Crusher.Parameters Used in CalculationsA queuing model is defined with formulaethat make use of the variables describedin the following.
  8. 8. QUEUING MODEL CHARACTERISTICSPrimary Queuing ModelCharacteristicsA queuing model is defined in terms of thefollowing primary characteristics. For usein calculations, these characteristics areexpressed using the letter that is indicatedin brackets following the name of thecharacteristic.• Request Arrival Rate (a). Servicerequests arrive according to one of
  9. 9. four patterns: steady, irregular,regular, or random.• Service Distribution Rate (s). Themean number of requests that areprocessed within a time period.• Utilization (u). The intensity of thetraffic. That is, the request arrival ratedivided by the service rate.• Number of Servers (c). Thenumber of servers that can processthe request. The number of tellers onduty affects the length of the line. Aserver in this case may not be thephysical server, but may be a critical
  10. 10. subcomponent, depending on what isbeing modelled.• Queue Discipline. How queuedrequests are processed, which affectsthe standard deviation calculation.Examples are: first-in-first-out (FIFO),last-in-first-out (LIFO), and priorityordered. This technique assumes FIFOqueues in all cases.Variables in Queuing ModelFormulaeThe primary queuing modelcharacteristics are common in themodel formulae. In addition, the
  11. 11. following variables may be useddepending on the queuing model.• Average number of waitingrequests (w),• Average number in the system (S),• Average waiting time (Tw),• Average time in system, i.e.,response time (Ts),• Delay due to queuing (D),• Number of requests or clients (K),• Probability that all servers are busy(P(c)),• Probability that there are Krequests in the system (P(K)),• Probability that there is no delay(P(0)),
  12. 12. • Erlang-B (B(c,U)),• Erlang-C (C(c,U)),• Erlang moment (m).The formulae used to calculate thesevalues depend on the type of queueand the type of distribution. Morecomplex queues, for example multipleserver queues, require use of more ofthese values.
  13. 13. We will Solve your :-ACCOUNTINGASSIGNMENTS&
  14. 14. GET QUOTE IN2
  15. 15. We will Solve your :-ACCOUNTINGASSIGNMENTS&
  16. 16. GET QUOTE IN2
  17. 17. GET QUOTE IN2