SlideShare a Scribd company logo
1 of 13
Download to read offline
PAPER

      J
                       ctice s
                    Pra stion
                    Que




              inter national    DO NOT OPEN THIS BOOKLET UNTIL INSTRUCTED.
              competitions       STUDENT’S NAME:
              and assessments
              for schools

                                Read the instructions on the ANSWER SHEET and fill in your
                                NAME, SCHOOL and OTHER INFORMATION.
                                Use a 2B or B pencil.
                                Do NOT use a pen.
                                Rub out any mistakes completely.

                                You MUST record your answers on the ANSWER SHEET.

                                Mark only ONE answer for each question.
MatheMatics                     Your score will be the number of correct answers.
                                Marks are NOT deducted for incorrect answers.

                                MULTIPLE-CHOICE QUESTIONS:
                                Use the information provided to choose the BEST answer from
                                the four possible options.
                                On your ANSWER SHEET fill in the oval that matches your answer.

                                FREE-RESPONSE QUESTIONS:
                                Write your answer in the boxes provided on the ANSWER SHEET
                                and fill in the oval that matches your answer

                                You may use a ruler and spare paper.
                                A CALCULATOR is required.
1.         The diagram below represents the                    3.   During 2001, Australia exported goods to
            products of (x + 5) and (3x + 2).                        a total value of $123 000 million.
                                                                     The graph shows the percentage of these
                                               3x + 2                goods exported to different parts of the
                                                                     world.
                                           3x           2

                         x                                                                          Key
                                                                           19%
                                                                                                     Japan
                                                                                                     USA
             x+5                                                                         41%
                                                                     10%                             ASEAN
                         5
                                                                                                     EU
                                                                      12%
                                                                                                     China
                                                                             12%    6%
                                                                                                     Other
            What product is represented by the
                              NOT TO SCALE

            shaded rectangle?                                        What was the value, in millions of dollars,
                                                                     of the goods exported to China?
            (A)              2x
            (B)              6x                                      (A) 7 380
            (C)               x2                                     (B) 12 300
            (D)              3x2                                     (C) 14 760
                                                                     (D) 23 370

 2.         Jules has a package gift-wrapped, as
            shown.


                    10 cm


                10 cm


                                          30 cm



            What is the volume, in cm3, of the
            package?

            (A)           50
            (B)          300
            (C)         1400
            (D)         3000




ICAS Mathematics Practice Questions Paper J © EAA   	       2
4.	   Jane	was	tossing	a	coin,	but	one	side	of		           6.						
          the	coin	was	weighted	more	heavily	than		
                                                                                                 X                 F
                                                                                          L=M 1–
          the	other.                                                                             Y

          Here	are	the	results	she	obtained.	                               Y = 5 F = 10 M =100 000 L = 120 000


                                                                           What	is	the	value	of	X	correct	to	two	
                                                                           decimal	places?

                                                                           (A)	 – 0.09
                                                                           (B)	 – 0.02
                                                                           (C)	   0.02
                                                                           (D)	   0.09


                                                               7.	         The	area	of	one	of	these	isosceles	
                                                                           triangles	is	60	square	units.



                                                                                              base
          Based	on	her	results,	which	of	these	is		
          the	best	estimate	of	the	probability	of	                         The	length	of	the	base	of	the	triangle	is	10	
          getting	a	head	in	a	single	toss	of	Jane’s	                       units.
          coin?                                                                                base
                                                                           The	grid	below	is	made	up	of	triangles	
          (A)	   0.4                                                       exactly	the	same	size	as	the	triangle	
          (B)	   0.5                                                       above.
          (C)	   0.6
          (D)	   0.7


    5.	   This	picture	is	based	on	the	style	of	the	
          Dutch	artist	Piet	Mondrian	(1872–1944).

                              6         2
                 2                                                   		

                                            4             	               	What	is	the	perimeter	of	the	shaded	shape?
                 6                                        	
                                                          	               	(A)	   105	units
                                                          	               	(B)	   150	units
                 4                                        	               	(C)	   160	units
                                                          	               	(D)	   162	units
                         NOT TO SCALE



          Which	expression	gives	the	total	area	of	the	
          three	coloured	rectangles	in	the	picture?

          (A)	   6a2 + 48ab – 32b2
          (B)	   20a2 + 24b2
          (C)	   4a2 + 36ab – 24b2
          (D)	   6a2 + 16b2
	                                                         3	                                  ICAS	Mathematics	Practice	Questions	Paper	J	©	EAA
QUESTIONS	9	AND	10	ARE	FREE	RESPONSE.
 8.         Anna forgot the code of a 3-digit lock on
            her case. The code was made of 3 digits Write	your	answer	in	the	boxes	provided	on	
            ranging from 0 to 9. She remembered that the	ANSWER	SHEET	and	fill	in	the	ovals	that	
            the first digit was less than 5, the second match	your	answer.
            digit was an odd number, and the third
            one was either 7 or 8. There were no
            identical digits in the code.               9.   The diagram represents a regular octagon
                                                             of area 500 cm2.
            How many different combinations could
            possibly open her lock?




            (A)       25
            (B)       36
                                                                    How long, to the nearest centimetre,
            (C)       41
                                                                    is one side of the octagon?
            (D)       50
                                                            10.     In the diagram H represents the position
                                                                    of a hawk hovering above the ground, and
                                                                    M the position of a mouse on the ground.



                                                                  250

                                                                  200

                                                                  150                                           H
                                                                  100

                                                                  50
                                                                                               M
                                                                   0
                                                                        50                                                      0
                                                                             100                                           50
                                                                                   150                               100
                                                                                         200                   150
                                                                                                         200
                                                                                                   250
                                                                             ALL MEASUREMENTS IN CENTIMETRES


                                                                    The mouse moves to a new position N,
                                                                    which is 50 cm from position M.

                                                                    What is the maximum possible distance,
                                                                    in cm, from H to the new position N
                                                                    correct to the nearest whole number?


                                                                                   END OF PAPER
ICAS Mathematics Practice Questions Paper J © EAA   	   4
This page may be used for working.




                 5                   ICAS Mathematics Practice Questions Paper J © EAA
Acknowledgment
copyright in this booklet is owned by educational
assessment australia, UNsW Global Pty Limited, unless
otherwise indicated. every effort has been made to trace and
acknowledge copyright. educational assessment australia
apologises for any accidental infringement and welcomes
information to redress the situation.




    The following year levels should sit THIS Paper:

    Australia                                       Year 12
    Brunei                                 Pre-University 2
    Malaysia                                       Upper 6
    New Zealand                                     Year 13
    Pacific                                         Year 12
    Singapore                             Junior college 1
    South Africa                                  Grade 12     PAPER

                                                                J

                                                               Educational       © 2010 educational assessment australia.
                                                                                 eaa is an education group of UNsW Global Pty
                                                               Assessment        Limited, a not-for-profit provider of education,

              THE UNIVERSITY OF NEW SOUTH WALES                Australia         training and consulting services and a wholly
                                                                                 owned enterprise of the University of New
                                                               eaa.unsw.edu.au   south Wales. aBN 62 086 418 582
PaPer


     J                   M
                                                                                                                                           Inter national
                                                                                                                                           Competitions
                                                                                                                                           and Assessments                                       THE UNIVERSITY OF NEW SOUTH WALES
                                                                                                                                           for Schools




HOW TO FILL OUT THIS SHEET:
                                                  EXAMPLE 1: Debbie Bach                                               EXAMPLE 2: Chan Ai Beng                                                   EXAMPLE 3: Jamal bin Abas
                                                  FIRST NAME                          LAST NAME                        FIRST NAME               LAST NAME                                        FIRST NAME                                          LAST NAME
•	 Rub	out	all	mistakes	completely.
•	 Print	your	details	clearly		                   A   A   A   A       A   A   A       A    A       A   A   A           A   A       A   A    A   A    A       A   A   A       A       A   A       A   A       A       A   A   A       A   A   A   A       A   A   A       A
	 in	the	boxes	provided.                          B   B   B   B       B   B   B       B    B       B   B   B           B   B       B   B   B    B    B       B   B   B       B       B   B       B   B       B       B   B   B       B   B   B   B       B   B   B       B
                                                  C   C   C   C       C   C   C       C    C       C   C   C           C   C       C   C   C    C    C       C   C   C       C       C   C       C   C       C       C   C   C       C   C   C   C       C   C   C       C
•	 Make	sure	you	fill	in	only		                   D   D   D   D       D   D   D       D    D       D   D   D           D   D       D   D   D    D    D       D   D   D       D       D   D       D   D       D       D   D   D       D   D   D   D       D   D   D       D
	 one	oval	in	each	column.



FIRST NAME to appear on certificate                                                                                                        LAST NAME to appear on certificate



 A   A   A   A   A   A   A   A    A   A   A   A       A   A       A       A       A   A        A       A   A       A   A   A               A     A       A       A   A           A       A   A   A   A           A       A       A       A   A       A       A       A       A

 B   B   B   B   B   B   B   B    B   B   B   B       B   B       B       B       B   B        B       B   B       B   B   B               B     B       B       B   B           B       B   B   B   B           B       B       B       B   B       B       B       B       B




                                                                                                                                                                                                               S
 C   C   C   C   C   C   C   C    C   C   C   C       C   C       C       C       C   C        C       C   C       C   C   C               C     C       C       C   C           C       C   C   C   C           C       C       C       C   C       C       C       C       C




                                                                                                                                                                                                             N
 D   D   D   D   D   D   D   D    D   D   D   D       D   D       D       D       D   D        D       D   D       D   D   D               D     D       D       D   D           D       D   D   D   D           D       D       D       D   D       D       D       D       D

 E   E   E   E   E   E   E   E    E   E   E   E       E   E       E       E       E   E        E       E   E       E   E   E               E     E       E       E   E           E       E   E   E   E           E       E       E       E   E       E       E       E       E




                                                                                                                                                     IO
 F   F   F   F   F   F   F   F    F   F   F   F       F   F       F       F       F   F        F       F   F       F   F   F               F     F       F       F   F           F       F   F   F   F           F       F       F       F   F       F       F       F       F

 G   G   G   G   G   G   G   G    G   G   G   G       G   G       G       G   G       G        G       G   G       G   G   G               G     G       G       G   G           G       G   G   G   G           G       G       G       G   G       G       G       G       G




                                                                                                                                                   T
 H   H   H   H   H   H   H   H    H   H   H   H       H   H       H       H       H   H        H       H   H       H   H   H               H     H       H       H   H           H       H   H   H   H           H       H       H       H   H       H       H       H       H




                                                                                                                                                  S
 I   I   I   I   I   I   I   I    I   I   I   I       I   I       I       I       I    I       I       I       I   I   I       I            I    I       I       I       I       I       I   I   I       I       I       I       I       I   I       I       I       I       I




                                                                                                                                                E
 J   J   J   J   J   J   J   J    J   J   J   J       J   J       J       J       J   J        J       J       J   J   J   J                J    J       J       J       J       J       J   J   J   J           J       J       J       J   J       J       J       J       J

 K   K   K   K   K   K   K   K    K   K   K   K       K   K       K       K       K   K        K       K   K       K   K   K               K     K       K       K   K           K       K   K   K   K           K       K       K       K   K       K       K       K       K




                                                                                                                        U
 L   L   L   L   L   L   L   L    L   L   L   L       L   L       L       L       L   L        L       L       L   L   L   L                L    L       L       L       L       L       L   L   L   L           L       L       L       L   L       L       L       L       L




                                                                                                                       Q
 M   M   M   M   M   M   M   M    M   M   M   M       M   M       M       M   M       M        M       M   M       M   M   M               M     M       M       M   M           M       M   M   M   M           M       M       M       M   M       M       M       M       M

 N   N   N   N   N   N   N   N    N   N   N   N       N   N       N       N       N   N        N       N   N       N   N   N               N     N       N       N   N           N       N   N   N   N           N       N       N       N   N       N       N       N       N




                                                                                        E
 O   O   O   O   O   O   O   O    O   O   O   O       O   O       O       O   O       O        O       O   O       O   O   O               O     O       O       O   O           O       O   O   O   O           O       O       O       O   O       O       O       O       O

 P   P   P   P   P   P   P   P    P   P   P   P       P   P       P       P       P   P        P       P   P       P   P   P               P     P       P       P   P           P       P   P   P   P           P       P       P       P   P       P       P       P       P




                                                                    I                 C
 Q   Q   Q   Q   Q   Q   Q   Q    Q   Q   Q   Q       Q   Q       Q       Q   Q       Q        Q       Q   Q       Q   Q   Q               Q     Q       Q       Q   Q           Q       Q   Q   Q   Q           Q       Q       Q       Q   Q       Q       Q       Q       Q

 R   R   R   R   R   R   R   R    R   R   R   R       R   R       R       R       R   R        R       R   R       R   R   R               R     R       R       R   R           R       R   R   R   R           R       R       R       R   R       R       R       R       R




                                                                  T
 S   S   S   S   S   S   S   S    S   S   S   S       S   S       S       S       S   S        S       S   S       S   S   S               S     S       S       S   S           S       S   S   S   S           S       S       S       S   S       S       S       S       S




                                     C
 T   T   T   T   T   T   T   T    T   T   T   T       T   T       T       T       T   T        T       T       T   T   T   T                T    T       T       T   T           T       T   T   T   T           T       T       T       T   T       T       T       T       T




                                    A
 U   U   U   U   U   U   U   U    U   U   U   U       U   U       U       U       U   U        U       U   U       U   U   U               U     U       U       U   U           U       U   U   U   U           U       U       U       U   U       U       U       U       U

 V   V   V   V   V   V   V   V    V   V   V   V       V   V       V       V       V   V        V       V   V       V   V   V               V     V       V       V   V           V       V   V   V   V           V       V       V       V   V       V       V       V       V




                                  R
 W   W   W   W   W   W   W   W    W   W   W   W       W   W       W       W   W       W        W       W   W       W   W   W               W    W        W       W   W           W       W   W   W   W           W       W   W           W   W       W       W       W       W




                         P
 X   X   X   X   X   X   X   X    X   X   X   X       X   X       X       X       X   X        X       X   X       X   X   X               X     X       X       X   X           X       X   X   X   X           X       X       X       X   X       X       X       X       X

 Y   Y   Y   Y   Y   Y   Y   Y    Y   Y   Y   Y       Y   Y       Y       Y       Y   Y        Y       Y   Y       Y   Y   Y               Y     Y       Y       Y   Y           Y       Y   Y   Y   Y           Y       Y       Y       Y   Y       Y       Y       Y       Y

 Z   Z   Z   Z   Z   Z   Z   Z    Z   Z   Z   Z       Z   Z       Z       Z       Z   Z        Z       Z   Z       Z   Z   Z               Z     Z       Z       Z   Z           Z       Z   Z   Z   Z           Z       Z       Z       Z   Z       Z       Z       Z       Z


 ’   ’   ’   ’   ’   ’   ’   ’    ’   ’   ’   ’       ’   ’       ’       ’       ’    ’       ’       ’       ’   ’   ’   ’                ’    ’       ’       ’       ’       ’       ’   ’   ’       ’       ’       ’       ’       ’   ’       ’       ’       ’       ’
 –   –   –   –   –   –   –   –    –   –   –   –       –   –       –       –       –   –        –       –       –   –   –   –                –    –       –       –       –       –       –   –   –   –           –       –       –       –   –       –       –       –       –

 /   /   /   /   /   /   /   /    /   /   /   /       /   /       /       /       /    /       /       /       /   /   /       /            /    /       /       /       /       /       /   /   /       /       /       /       /       /   /       /       /       /       /




                                                                                                                                                                                             DATE OF BIRTH                                               CLASS
                                                                                                                                                                                             Day     Month Year                                          (optional)

Are you male or female?
	  Male	          Female                                                                   *045912*                                                                                          0

                                                                                                                                                                                             1
                                                                                                                                                                                                 0

                                                                                                                                                                                                 1
                                                                                                                                                                                                     0

                                                                                                                                                                                                     1
                                                                                                                                                                                                                 0

                                                                                                                                                                                                                 1
                                                                                                                                                                                                                         0

                                                                                                                                                                                                                         1
                                                                                                                                                                                                                                 0

                                                                                                                                                                                                                                 1
                                                                                                                                                                                                                                                             A

                                                                                                                                                                                                                                                             B
                                                                                                                                                                                                                                                                     K

                                                                                                                                                                                                                                                                     L

Does anyone in your home usually speak a language other than English?                                                                                                                        2   2               2       2       2                           C       M

	  Yes	          No                                                                                                                                                                          3   3               3       3       3                           D       N

                                                                                                                                                                                                 4               4       4       4                           E       O

School name:                                                                                                                                                                                     5               5       5       5                           F       P

                                                                                                                                                                                                 6               6       6       6                           G       Q

Town / suburb:                                                                                                                                                                                   7               7       7       7                           H       R

                                                                                                                                                                                                 8               8       8       8                           I       S

Today’s date:                                                                         Postcode:                                                                                                  9               9       9       9                           J       T
TO ANSWER THE QUESTIONS
MULTIPLE CHOICE	 	                                            FREE RESPONSE



Example:	            4	+	6	=	 	                               Example:					6	+	6	=

	            (A)	    		2	                                     ●	The	answer	is	12,	so	WRITE	your                 1 2
	            (B)	    		9	                                     			answer	in	the	boxes.                      0     0      0

	            (C)	    10	                                      ●	Write	only	ONE	digit	in	each	box,          1     1      1
                                                                                                           2     2      2
	            (D)	    24	                                      			as	shown,	and	fill	in	the	correct	oval,   3     3      3

	            	       	                                        			as	shown.                                 4     4      4
                                                                                                           5     5      5
The	answer	is	10,	so	fill	in	the	oval					,	as	shown.
                                        C
                                                                                                           6     6      6
                                                                                                           7     7      7

     A       B       C       D                                                                             8     8      8
                                                                                                           9     9      9




START
 1       A       B       C       D




 2       A       B       C       D




 3       A       B       C       D




 4       A       B       C       D




 5       A       B       C       D




 6       A       B       C       D




 7       A       B       C       D




 8       A       B       C       D




 9                                   10
         0       0       0                0   0   0

         1       1       1                1   1   1

         2       2       2                2   2   2

         3       3       3                3   3   3

         4       4       4                4   4   4

         5       5       5                5   5   5

         6       6       6                6   6   6

         7       7       7                7   7   7

         8       8       8                8   8   8

         9       9       9                9   9   9




                                                      PaPer


                                                      J M
                                                                                                           Inter national
                                                                                                           Competitions
Your privacy is assured as EAA fully complies                                                              and Assessments
with appropriate Australian privacy legislation.                                                           for Schools

Visit www.eaa.unsw.edu.au for more details.
LEVEL OF
QUESTION   KEY   SOLUTION                                           STRAND
                                                                                           DIFFICULTY
                 The shaded rectangle has a side of 2 and a side
                                                                   Algebra and
   1        A    of x. Therefore, the product of these two sides                           Easy
                                                                     Pattern
                 is 2x.
                 Volume of a box = length × width × height
   2       D     V = 30 × 10 × 10                                  Measurement             Easy
                 V = 3000 cm3
                 6% of the total products are exported to China.
                                                                   Chance and
   3        A    6% of 123 000 million = 0.06 × 123 000                                    Easy
                                                                      Data
                 million = $7380 million
                 Experimental Probability equals:
                  Number of times an event has occurred
                  Number of times an event has occurred
                            Number of trials
                            Number of trials
                                                                   Chance and
   4        C    Applying this formula:                                                    Medium
                                                                      Data
                  67 + 286 + 581 + 2989
                  67 + 286 + 581 + 2989 = 0.59
                 100 + 500 + 1000 + 5000
                 100 + 500 + 1000 + 5000
                 Therefore, the best estimate is 0.6.

                 The green area is 2a × a = 2a2
                 The orange area is 4a × a = 4a2
                 The blue area is = length × width = (6b + 2b)
                 × (6a − 4b)
   5        A    = 8b × (6a − 4b)                                  Algebra and
                                                                                           Medium
                 = 48ab − 32b2                                       Pattern
                 Therefore the total area that is coloured is =
                 green + orange + blue
                 = 2a2 + 4a2 + 48ab − 32b2
                 = 6a2 + 48ab − 32b2
                 Substitute all values in the given expression:

                  120000 = 100000(1− )10
                                          X
                 120000 = 100000(1− X)10
                                         X 10
                                          5
                 120000 = 100000(1− get: 5)
                 By simplifying you will 5
                             X
                  6 = 5(1− )10
                            X)10
                             5
                 120000 = X 10
                                         X
                 6 = 5(1− 100000(1− 5 )10 by 5 to get:
                 6 = 5(1−   5 ) , then divide
                            5
                  120000 = X)10
                   6         100000(1− )10
                                          X
                     = (1−X               5
                  6= 5(1− 5 10
                   5
                 66 = (1− X)10 10
                  5 = (1− 5 )
                  5 X 5X 10   6                                    Algebra and
   6        A    By= 5(1−X the tenth root to the two sides of
                  6
                  1− =10 5 )                                                               Medium/Hard
                  6 applying5
                      X =10 6 10
                       5                                             Pattern
                    = (1− 6
                 1− X        )
                 the equation:
                 1− 5 =10 55
                  5
                   6 5      X
                            5
                  X = 5(1−10 66 )
                     = (1− )10
                   5 X 10 6 5
                 X = 5 = 105 65
                 1− 5(1−10 )
                 X = 5(1− 5 )
                      X      65
                  1− =10 subject of the equation:
                 Make5X the 5
                 X = 5(1−10 6 )
                              5
                           10 6
                  X = 5(1−        )
                                5
                 X = −0.09

                                                                      ICAS Mathematics Practice Questions Paper J © EAA
The perimeter of the shaded shape is made of
                                           11 bases of the given triangle + 2 heights +
                                           2 sides.
                                           You need to calculate the height and the side
                                           of the triangle first.
                                           Calculating the height: the area is given
                                           (60 square units), therefore you can find the
                                           height using the formula: Area = ½ × height
                                                           h × 10
                                           × base, 60 =        2    which gives
                                           h = 12 units
                                                                                              Space and
            7                   C          Calculating the side by cutting the triangle                    Hard
                                                    s middle, a right-angled triangle is      Geometry
                                           down the = 12 + 5
                                                             2    2


                                           formed with base = 5 cm and height = 12 cm.
                                           The unknown side is called s. Using Pythagoras’
                                                   h × 10
                                           60 =
                                                      2
                                           Theorem, h2 + 52 =s2. Substitute h = 12 and
                                           find s:
                                           s = 122 + 52 . Therefore, s = 13 units.
                                           Now add all the values in the original
                                           calculation: 11 bases of the given triangle +
                                           2 heights + 2 sides.
                                           11 × 10 + 2 × 12 + 2 × 13 = 160 units.

                                           The first two digits filled 5 × 5 ways, the last
                                           digit 2 ways BUT must delete                       Chance and
            8                   C                                                                          Hard
                                           117, 118, 337,338, 077,177,277,377 and 477.           Data
                                           5 × 5 × 2 – 9 = 41.

                                           This item requires a lot of work and some
                                           knowledge of Pythagoras’ Theorem and the
                                           internal angles of an octagon.

                                           There are several approaches, but they all work
                                           by finding the area of triangles, rectangles
                                           or trapeziums. From there, an equation that
                                           relates the area of the octagon to the length of
                                           the side can be written.
                                           One method is to think of the octagon as a
                                           rectangle between two trapeziums. A different
                                           way is to think of it as a square with triangles
                                           cut off.                                           Space and
            9                  10                                                                          Hard
                                                                                              Geometry




                                                                      x  2x
                                                                            2



                                                            45°
                                                                  x
                                                                  2
                                                                        x
                                                             y
                                                    	
                                                        y
ICAS Mathematics Practice Questions Paper J © EAA
x
                 y

       y
                 x


       x


       y         x

Either method results in the same answer.

Let’s approach it using x second way:
       500 = 2(1+ 2) the 2

We need to calculate y first.
using Phythagoras’ Theorem:
y 2 + y 2 = x2
      x
y=
       2
The side of the square equals x + 2y
            2x
that is x +
             2
                                   2
                                2x 
The area of the square is
                           x + 2
                                   
The area of each of the four triangles on the
          1           1     x     x     x2
corners is × y × y = ×         ×      =
          2           2     2      2 4
Therefore,
area of square – area of 4 triangles = 500
            2
     2x 
 x       − x = 500
                2

        2
             2x × 2x
 x2  2 x2          − x2 = 500
                 2
         4 
 x2  2     = 500
          2
Solving for x gives an answer of 10.176, cm.
Which is 10 to the nearest centimetre.




                                                ICAS Mathematics Practice Questions Paper J © EAA
Apart from reading 3D coordinates the main
                                           mathematics in this question is Pythagoras’
                                           Theorem.
                                           If we look at the mouse and the hawk from
                                           above we would see this:
                                                                    M
                                                     M
                                                                         H
                                                           H

                                                            M
                                                                H
                                           The line shows the hawk’s path. The distance
                                           along the ground of this path (the horizontal
                                           component)2is 1002 + 502 . This is about
                                                     M
                                           111.8 cm.50 mouse runs 50 cm away from
                                             1002 + The
                                                           H
                                           the hawk M a new position ‘N’. The mouse can
                                                     to
                                                          H
                                           run in any direction but wants to maximise the
                                             1002 +from the hawk. This means he should
                                           distance  502         N
                                                   N
                                           run in the same direction as the line NH in the
                                                                          H
                                           diagram below. H
                                                    N
                                               1002 + 502       H
                                              1002 + 502

                                                        N                                       H
           10                 190                                            H                 Measurement   Hard
                                           Along the ground H this gives a distance of
                                                   N
                                           111.8+50=161.8 cm                                 100 cm
                                                            H                 100 cm
                                                                              H
                                           This is just the horizontal distance. Fortunately
                                           for the mouse, the hawk is further away than
                                                            N
                                            N                            161.8 cmcm
                                           that because it is hovering above 100 ground at
                                                                              the
                                                          161.8 cm
                                           a height of 100 cm.
                                           We can show this on a new diagram from a
                                                                              H
                                            N
                                           different point of view.
                                                          161.8 cm            H
                                                              161.82 + 1002 100 cm
                                              161.82 + 1002
                                                                              100 cm
                                            N
                                                          161.8 cm
                                              161.82 + 1002
                                            N
                                                          161.8 cm
                                           We can now use Pythagoras’ Theorem again to
                                           find the distance from the hawk to the mouse.
                                              161.82 + 1002
                                           This gives an answer of 190.2 cm. To the
                                             161.82 + 1002
                                           nearest whole number this is 190.
                                           Comment
                                           The underlying mathematics in this problem is
                                           not very difficult and boils down to two instances
                                           of Pythagoras’ Theorem. As a problem, though,
                                           the question is more difficult. Students have
                                           to realise that Pythagoras’ Theorem is the
                                           appropriate piece of mathematics to use and have
                                           to extract information presented in an unusual
                                           way. Also some insight is required to understand
                                           in what direction the mouse should run.

ICAS Mathematics Practice Questions Paper J © EAA
Level of difficulty refers to the expected level of difficulty for the question.

Easy                          more than 70% of candidates will choose the correct option

Medium                        about 50–70% of candidates will choose the correct option

Medium/Hard                   about 30–50% of candidates will choose the correct option

Hard                          less than 30% of candidates will choose the correct option




                                                                                   ICAS Mathematics Practice Questions Paper J © EAA

More Related Content

What's hot

Unit 11 family letter
Unit 11 family letterUnit 11 family letter
Unit 11 family letterackerkri
 
Yayasan MENDAKI Seminar for Parents
Yayasan MENDAKI Seminar for ParentsYayasan MENDAKI Seminar for Parents
Yayasan MENDAKI Seminar for ParentsJimmy Keng
 
04a 5 mb2f_unit_2_november_2011_mark_scheme
04a 5 mb2f_unit_2_november_2011_mark_scheme04a 5 mb2f_unit_2_november_2011_mark_scheme
04a 5 mb2f_unit_2_november_2011_mark_schemeclaire meadows-smith
 
Form 2441-Child and Dependent Care Expenses
Form 2441-Child and Dependent Care ExpensesForm 2441-Child and Dependent Care Expenses
Form 2441-Child and Dependent Care Expensestaxman taxman
 
M1ED taxes.state.mn.us
M1ED taxes.state.mn.usM1ED taxes.state.mn.us
M1ED taxes.state.mn.ustaxman taxman
 
F4 Maths Ppsmi 2007 P2
F4 Maths Ppsmi 2007 P2F4 Maths Ppsmi 2007 P2
F4 Maths Ppsmi 2007 P2norainisaser
 
08a 5 mb2h_unit_2_mark_scheme_–_march_2012
08a 5 mb2h_unit_2_mark_scheme_–_march_201208a 5 mb2h_unit_2_mark_scheme_–_march_2012
08a 5 mb2h_unit_2_mark_scheme_–_march_2012claire meadows-smith
 
Unit 2 higher_mark_scheme_march_2012
 Unit 2 higher_mark_scheme_march_2012 Unit 2 higher_mark_scheme_march_2012
Unit 2 higher_mark_scheme_march_2012claire meadows-smith
 
F4 Final Sbp 2007 Maths P2
F4 Final Sbp 2007 Maths P2F4 Final Sbp 2007 Maths P2
F4 Final Sbp 2007 Maths P2norainisaser
 
Millionaire game-idioms
Millionaire game-idiomsMillionaire game-idioms
Millionaire game-idiomsjesusmarcos42
 
Seminar for Parents at Beacon Primary School
Seminar for Parents at Beacon Primary SchoolSeminar for Parents at Beacon Primary School
Seminar for Parents at Beacon Primary SchoolJimmy Keng
 
F4 Final Sbp2007 Maths P1
F4 Final Sbp2007 Maths P1F4 Final Sbp2007 Maths P1
F4 Final Sbp2007 Maths P1norainisaser
 
1. fizik k2 set b soalan
1. fizik k2 set b soalan1. fizik k2 set b soalan
1. fizik k2 set b soalanjamaliahali
 
F4 Final Sbp2006 Math P 2
F4 Final Sbp2006 Math P 2F4 Final Sbp2006 Math P 2
F4 Final Sbp2006 Math P 2norainisaser
 

What's hot (17)

Unit 11 family letter
Unit 11 family letterUnit 11 family letter
Unit 11 family letter
 
Yayasan MENDAKI Seminar for Parents
Yayasan MENDAKI Seminar for ParentsYayasan MENDAKI Seminar for Parents
Yayasan MENDAKI Seminar for Parents
 
04a 5 mb2f_unit_2_november_2011_mark_scheme
04a 5 mb2f_unit_2_november_2011_mark_scheme04a 5 mb2f_unit_2_november_2011_mark_scheme
04a 5 mb2f_unit_2_november_2011_mark_scheme
 
Form 2441-Child and Dependent Care Expenses
Form 2441-Child and Dependent Care ExpensesForm 2441-Child and Dependent Care Expenses
Form 2441-Child and Dependent Care Expenses
 
M1ED taxes.state.mn.us
M1ED taxes.state.mn.usM1ED taxes.state.mn.us
M1ED taxes.state.mn.us
 
F4 Maths Ppsmi 2007 P2
F4 Maths Ppsmi 2007 P2F4 Maths Ppsmi 2007 P2
F4 Maths Ppsmi 2007 P2
 
08a 5 mb2h_unit_2_mark_scheme_–_march_2012
08a 5 mb2h_unit_2_mark_scheme_–_march_201208a 5 mb2h_unit_2_mark_scheme_–_march_2012
08a 5 mb2h_unit_2_mark_scheme_–_march_2012
 
Unit 2 higher_mark_scheme_march_2012
 Unit 2 higher_mark_scheme_march_2012 Unit 2 higher_mark_scheme_march_2012
Unit 2 higher_mark_scheme_march_2012
 
F4 Final Sbp 2007 Maths P2
F4 Final Sbp 2007 Maths P2F4 Final Sbp 2007 Maths P2
F4 Final Sbp 2007 Maths P2
 
Assessor course
Assessor courseAssessor course
Assessor course
 
C13s
C13sC13s
C13s
 
Millionaire game-idioms
Millionaire game-idiomsMillionaire game-idioms
Millionaire game-idioms
 
Seminar for Parents at Beacon Primary School
Seminar for Parents at Beacon Primary SchoolSeminar for Parents at Beacon Primary School
Seminar for Parents at Beacon Primary School
 
F4 Final Sbp2007 Maths P1
F4 Final Sbp2007 Maths P1F4 Final Sbp2007 Maths P1
F4 Final Sbp2007 Maths P1
 
Matrix Inverse, IMT
Matrix Inverse, IMTMatrix Inverse, IMT
Matrix Inverse, IMT
 
1. fizik k2 set b soalan
1. fizik k2 set b soalan1. fizik k2 set b soalan
1. fizik k2 set b soalan
 
F4 Final Sbp2006 Math P 2
F4 Final Sbp2006 Math P 2F4 Final Sbp2006 Math P 2
F4 Final Sbp2006 Math P 2
 

More from 1stgeneralming

More from 1stgeneralming (12)

Science paper J
Science paper JScience paper J
Science paper J
 
Science paper I
Science paper IScience paper I
Science paper I
 
Science paper H
Science paper HScience paper H
Science paper H
 
Mathematics paper I
Mathematics paper IMathematics paper I
Mathematics paper I
 
Mathematics paper H
Mathematics paper HMathematics paper H
Mathematics paper H
 
Science paper F
Science paper FScience paper F
Science paper F
 
Science papere
Science papereScience papere
Science papere
 
Science paperd
Science paperdScience paperd
Science paperd
 
Science paperg
Science papergScience paperg
Science paperg
 
Mathematics paper F
Mathematics paper FMathematics paper F
Mathematics paper F
 
Mathematics paper E
Mathematics paper EMathematics paper E
Mathematics paper E
 
Mathematics paper G
Mathematics paper GMathematics paper G
Mathematics paper G
 

Mathematics paperj

  • 1. PAPER J ctice s Pra stion Que inter national DO NOT OPEN THIS BOOKLET UNTIL INSTRUCTED. competitions STUDENT’S NAME: and assessments for schools Read the instructions on the ANSWER SHEET and fill in your NAME, SCHOOL and OTHER INFORMATION. Use a 2B or B pencil. Do NOT use a pen. Rub out any mistakes completely. You MUST record your answers on the ANSWER SHEET. Mark only ONE answer for each question. MatheMatics Your score will be the number of correct answers. Marks are NOT deducted for incorrect answers. MULTIPLE-CHOICE QUESTIONS: Use the information provided to choose the BEST answer from the four possible options. On your ANSWER SHEET fill in the oval that matches your answer. FREE-RESPONSE QUESTIONS: Write your answer in the boxes provided on the ANSWER SHEET and fill in the oval that matches your answer You may use a ruler and spare paper. A CALCULATOR is required.
  • 2. 1. The diagram below represents the 3. During 2001, Australia exported goods to products of (x + 5) and (3x + 2). a total value of $123 000 million. The graph shows the percentage of these 3x + 2 goods exported to different parts of the world. 3x 2 x Key 19% Japan USA x+5 41% 10% ASEAN 5 EU 12% China 12% 6% Other What product is represented by the NOT TO SCALE shaded rectangle? What was the value, in millions of dollars, of the goods exported to China? (A) 2x (B) 6x (A) 7 380 (C) x2 (B) 12 300 (D) 3x2 (C) 14 760 (D) 23 370 2. Jules has a package gift-wrapped, as shown. 10 cm 10 cm 30 cm What is the volume, in cm3, of the package? (A) 50 (B) 300 (C) 1400 (D) 3000 ICAS Mathematics Practice Questions Paper J © EAA 2
  • 3. 4. Jane was tossing a coin, but one side of 6. the coin was weighted more heavily than X F L=M 1– the other. Y Here are the results she obtained. Y = 5 F = 10 M =100 000 L = 120 000 What is the value of X correct to two decimal places? (A) – 0.09 (B) – 0.02 (C) 0.02 (D) 0.09 7. The area of one of these isosceles triangles is 60 square units. base Based on her results, which of these is the best estimate of the probability of The length of the base of the triangle is 10 getting a head in a single toss of Jane’s units. coin? base The grid below is made up of triangles (A) 0.4 exactly the same size as the triangle (B) 0.5 above. (C) 0.6 (D) 0.7 5. This picture is based on the style of the Dutch artist Piet Mondrian (1872–1944). 6 2 2 4 What is the perimeter of the shaded shape? 6 (A) 105 units (B) 150 units 4 (C) 160 units (D) 162 units NOT TO SCALE Which expression gives the total area of the three coloured rectangles in the picture? (A) 6a2 + 48ab – 32b2 (B) 20a2 + 24b2 (C) 4a2 + 36ab – 24b2 (D) 6a2 + 16b2 3 ICAS Mathematics Practice Questions Paper J © EAA
  • 4. QUESTIONS 9 AND 10 ARE FREE RESPONSE. 8. Anna forgot the code of a 3-digit lock on her case. The code was made of 3 digits Write your answer in the boxes provided on ranging from 0 to 9. She remembered that the ANSWER SHEET and fill in the ovals that the first digit was less than 5, the second match your answer. digit was an odd number, and the third one was either 7 or 8. There were no identical digits in the code. 9. The diagram represents a regular octagon of area 500 cm2. How many different combinations could possibly open her lock? (A) 25 (B) 36 How long, to the nearest centimetre, (C) 41 is one side of the octagon? (D) 50 10. In the diagram H represents the position of a hawk hovering above the ground, and M the position of a mouse on the ground. 250 200 150 H 100 50 M 0 50 0 100 50 150 100 200 150 200 250 ALL MEASUREMENTS IN CENTIMETRES The mouse moves to a new position N, which is 50 cm from position M. What is the maximum possible distance, in cm, from H to the new position N correct to the nearest whole number? END OF PAPER ICAS Mathematics Practice Questions Paper J © EAA 4
  • 5. This page may be used for working. 5 ICAS Mathematics Practice Questions Paper J © EAA
  • 6. Acknowledgment copyright in this booklet is owned by educational assessment australia, UNsW Global Pty Limited, unless otherwise indicated. every effort has been made to trace and acknowledge copyright. educational assessment australia apologises for any accidental infringement and welcomes information to redress the situation. The following year levels should sit THIS Paper: Australia Year 12 Brunei Pre-University 2 Malaysia Upper 6 New Zealand Year 13 Pacific Year 12 Singapore Junior college 1 South Africa Grade 12 PAPER J Educational © 2010 educational assessment australia. eaa is an education group of UNsW Global Pty Assessment Limited, a not-for-profit provider of education, THE UNIVERSITY OF NEW SOUTH WALES Australia training and consulting services and a wholly owned enterprise of the University of New eaa.unsw.edu.au south Wales. aBN 62 086 418 582
  • 7. PaPer J M Inter national Competitions and Assessments THE UNIVERSITY OF NEW SOUTH WALES for Schools HOW TO FILL OUT THIS SHEET: EXAMPLE 1: Debbie Bach EXAMPLE 2: Chan Ai Beng EXAMPLE 3: Jamal bin Abas FIRST NAME LAST NAME FIRST NAME LAST NAME FIRST NAME LAST NAME • Rub out all mistakes completely. • Print your details clearly A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A in the boxes provided. B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C • Make sure you fill in only D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D one oval in each column. FIRST NAME to appear on certificate LAST NAME to appear on certificate A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B S C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C C N D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D D E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E E IO F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F F G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G G T H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H S I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I E J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J J K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K K U L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L Q M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M M N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N N E O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O O P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P P I C Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q Q R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R R T S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S C T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T A U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U U V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V V R W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W W P X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Y Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ ’ – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – – / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / DATE OF BIRTH CLASS Day Month Year (optional) Are you male or female? Male Female *045912* 0 1 0 1 0 1 0 1 0 1 0 1 A B K L Does anyone in your home usually speak a language other than English? 2 2 2 2 2 C M Yes No 3 3 3 3 3 D N 4 4 4 4 E O School name: 5 5 5 5 F P 6 6 6 6 G Q Town / suburb: 7 7 7 7 H R 8 8 8 8 I S Today’s date: Postcode: 9 9 9 9 J T
  • 8. TO ANSWER THE QUESTIONS MULTIPLE CHOICE FREE RESPONSE Example: 4 + 6 = Example: 6 + 6 = (A) 2 ● The answer is 12, so WRITE your 1 2 (B) 9 answer in the boxes. 0 0 0 (C) 10 ● Write only ONE digit in each box, 1 1 1 2 2 2 (D) 24 as shown, and fill in the correct oval, 3 3 3 as shown. 4 4 4 5 5 5 The answer is 10, so fill in the oval , as shown. C 6 6 6 7 7 7 A B C D 8 8 8 9 9 9 START 1 A B C D 2 A B C D 3 A B C D 4 A B C D 5 A B C D 6 A B C D 7 A B C D 8 A B C D 9 10 0 0 0 0 0 0 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 5 5 5 5 5 5 6 6 6 6 6 6 7 7 7 7 7 7 8 8 8 8 8 8 9 9 9 9 9 9 PaPer J M Inter national Competitions Your privacy is assured as EAA fully complies and Assessments with appropriate Australian privacy legislation. for Schools Visit www.eaa.unsw.edu.au for more details.
  • 9. LEVEL OF QUESTION KEY SOLUTION STRAND DIFFICULTY The shaded rectangle has a side of 2 and a side Algebra and 1 A of x. Therefore, the product of these two sides Easy Pattern is 2x. Volume of a box = length × width × height 2 D V = 30 × 10 × 10 Measurement Easy V = 3000 cm3 6% of the total products are exported to China. Chance and 3 A 6% of 123 000 million = 0.06 × 123 000 Easy Data million = $7380 million Experimental Probability equals: Number of times an event has occurred Number of times an event has occurred Number of trials Number of trials Chance and 4 C Applying this formula: Medium Data 67 + 286 + 581 + 2989 67 + 286 + 581 + 2989 = 0.59 100 + 500 + 1000 + 5000 100 + 500 + 1000 + 5000 Therefore, the best estimate is 0.6. The green area is 2a × a = 2a2 The orange area is 4a × a = 4a2 The blue area is = length × width = (6b + 2b) × (6a − 4b) 5 A = 8b × (6a − 4b) Algebra and Medium = 48ab − 32b2 Pattern Therefore the total area that is coloured is = green + orange + blue = 2a2 + 4a2 + 48ab − 32b2 = 6a2 + 48ab − 32b2 Substitute all values in the given expression: 120000 = 100000(1− )10 X 120000 = 100000(1− X)10 X 10 5 120000 = 100000(1− get: 5) By simplifying you will 5 X 6 = 5(1− )10 X)10 5 120000 = X 10 X 6 = 5(1− 100000(1− 5 )10 by 5 to get: 6 = 5(1− 5 ) , then divide 5 120000 = X)10 6 100000(1− )10 X = (1−X 5 6= 5(1− 5 10 5 66 = (1− X)10 10 5 = (1− 5 ) 5 X 5X 10 6 Algebra and 6 A By= 5(1−X the tenth root to the two sides of 6 1− =10 5 ) Medium/Hard 6 applying5 X =10 6 10 5 Pattern = (1− 6 1− X ) the equation: 1− 5 =10 55 5 6 5 X 5 X = 5(1−10 66 ) = (1− )10 5 X 10 6 5 X = 5 = 105 65 1− 5(1−10 ) X = 5(1− 5 ) X 65 1− =10 subject of the equation: Make5X the 5 X = 5(1−10 6 ) 5 10 6 X = 5(1− ) 5 X = −0.09 ICAS Mathematics Practice Questions Paper J © EAA
  • 10. The perimeter of the shaded shape is made of 11 bases of the given triangle + 2 heights + 2 sides. You need to calculate the height and the side of the triangle first. Calculating the height: the area is given (60 square units), therefore you can find the height using the formula: Area = ½ × height h × 10 × base, 60 = 2 which gives h = 12 units Space and 7 C Calculating the side by cutting the triangle Hard s middle, a right-angled triangle is Geometry down the = 12 + 5 2 2 formed with base = 5 cm and height = 12 cm. The unknown side is called s. Using Pythagoras’ h × 10 60 = 2 Theorem, h2 + 52 =s2. Substitute h = 12 and find s: s = 122 + 52 . Therefore, s = 13 units. Now add all the values in the original calculation: 11 bases of the given triangle + 2 heights + 2 sides. 11 × 10 + 2 × 12 + 2 × 13 = 160 units. The first two digits filled 5 × 5 ways, the last digit 2 ways BUT must delete Chance and 8 C Hard 117, 118, 337,338, 077,177,277,377 and 477. Data 5 × 5 × 2 – 9 = 41. This item requires a lot of work and some knowledge of Pythagoras’ Theorem and the internal angles of an octagon. There are several approaches, but they all work by finding the area of triangles, rectangles or trapeziums. From there, an equation that relates the area of the octagon to the length of the side can be written. One method is to think of the octagon as a rectangle between two trapeziums. A different way is to think of it as a square with triangles cut off. Space and 9 10 Hard Geometry x  2x 2 45° x 2 x y y ICAS Mathematics Practice Questions Paper J © EAA
  • 11. x y y x x y x Either method results in the same answer. Let’s approach it using x second way: 500 = 2(1+ 2) the 2 We need to calculate y first. using Phythagoras’ Theorem: y 2 + y 2 = x2 x y= 2 The side of the square equals x + 2y 2x that is x + 2 2  2x  The area of the square is  x + 2   The area of each of the four triangles on the 1 1 x x x2 corners is × y × y = × × = 2 2 2 2 4 Therefore, area of square – area of 4 triangles = 500 2  2x  x  − x = 500 2  2 2x × 2x x2  2 x2  − x2 = 500 2  4  x2  2   = 500  2 Solving for x gives an answer of 10.176, cm. Which is 10 to the nearest centimetre. ICAS Mathematics Practice Questions Paper J © EAA
  • 12. Apart from reading 3D coordinates the main mathematics in this question is Pythagoras’ Theorem. If we look at the mouse and the hawk from above we would see this: M M H H M H The line shows the hawk’s path. The distance along the ground of this path (the horizontal component)2is 1002 + 502 . This is about M 111.8 cm.50 mouse runs 50 cm away from 1002 + The H the hawk M a new position ‘N’. The mouse can to H run in any direction but wants to maximise the 1002 +from the hawk. This means he should distance 502 N N run in the same direction as the line NH in the H diagram below. H N 1002 + 502 H 1002 + 502 N H 10 190 H Measurement Hard Along the ground H this gives a distance of N 111.8+50=161.8 cm 100 cm H 100 cm H This is just the horizontal distance. Fortunately for the mouse, the hawk is further away than N N 161.8 cmcm that because it is hovering above 100 ground at the 161.8 cm a height of 100 cm. We can show this on a new diagram from a H N different point of view. 161.8 cm H 161.82 + 1002 100 cm 161.82 + 1002 100 cm N 161.8 cm 161.82 + 1002 N 161.8 cm We can now use Pythagoras’ Theorem again to find the distance from the hawk to the mouse. 161.82 + 1002 This gives an answer of 190.2 cm. To the 161.82 + 1002 nearest whole number this is 190. Comment The underlying mathematics in this problem is not very difficult and boils down to two instances of Pythagoras’ Theorem. As a problem, though, the question is more difficult. Students have to realise that Pythagoras’ Theorem is the appropriate piece of mathematics to use and have to extract information presented in an unusual way. Also some insight is required to understand in what direction the mouse should run. ICAS Mathematics Practice Questions Paper J © EAA
  • 13. Level of difficulty refers to the expected level of difficulty for the question. Easy more than 70% of candidates will choose the correct option Medium about 50–70% of candidates will choose the correct option Medium/Hard about 30–50% of candidates will choose the correct option Hard less than 30% of candidates will choose the correct option ICAS Mathematics Practice Questions Paper J © EAA