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Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
Atomic Mass Presentation
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Atomic Mass Presentation

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  • 1. Ch. 3 - Atomic Structure II. Masses of Atoms ♦ Mass Number ♦ Isotopes ♦ Relative Atomic Mass ♦ Average Atomic Mass
  • 2. A. Mass Number ♦mass # = protons + neutrons ♦always a whole number ♦NOT on the Periodic Table! © Addison-Wesley Publishing Company, Inc.
  • 3. B. Isotopes ♦Atoms of the same element with different mass numbers. C12 6 Mass # Atomic # ♦Nuclear symbol: ♦Hyphen notation: carbon-12
  • 4. B. Isotopes © Addison-Wesley Publishing Company, Inc.
  • 5. B. Isotopes ♦Chlorine-37 • atomic #: • mass #: • # of protons: • # of electrons: • # of neutrons: 17 37 17 17 20 Cl37 17
  • 6. IONS ♦Sometimes an atom can lose or gain electrons. If this happens it becomes charged. ♦If it loses (an) electron(s), it becomes positive. ♦If it gains (an) electron(s), it becomes negative.
  • 7. IONS ♦ If lithium loses one electron, its symbol is: ♦ If oxygen gains two electrons, its symbol is: + iL7 3 −2 O16 8
  • 8. C. Relative Atomic Mass ♦12 C atom = 1.992 × 10-23 g ♦1 p = 1.007276 amu 1 n = 1.008665 amu 1 e- = 0.0005486 amu ♦atomic mass unit (amu) ♦1 amu = 1 /12 the mass of a 12 C atom
  • 9. D. Average Atomic Mass ♦weighted average of all isotopes ♦on the Periodic Table ♦round to 2 decimal places 100 (%)(mass(mass)(%) )+ = Avg. Atomic Mass
  • 10. Avg. Atomic Mass D. Average Atomic Mass ♦EX: Calculate the avg. atomic mass of oxygen if its abundance in nature is 99.76% 16 O, 0.04% 17 O, and 0.20% 18 O. = ++ = 100 (18)(0.20)(17)(0.04))(16)(99.76 16.00 amu
  • 11. Avg. Atomic Mass D. Average Atomic Mass ♦EX: Find chlorine’s average atomic mass if approximately 8 of every 10 atoms are chlorine-35 and 2 are chlorine-37. = + = 10 (37)(2)(35)(8) 35.40 amu

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