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    H 1 H 1 Presentation Transcript

    • Ä î ð íî ã î â ü à é ìã è é í11 æ è ë è é í 1- ð ñ ó ð ã ó ó ë ü Ó ñ ò º ð º ã ч ò ¿ ¿ íè é ¿ è íæ , ò àð õ àë ò , ã àð ã àí àâ àõ Õ è ìè é í á à ã ¿ Б . Эрдэнэчимэг
    • ë íü ñ î ã îÝõíèé ¿ñãèéã õàññàí чèíü Ýâã¿é áóäëèàí òàðüчèõëàà Ýðäýì ñóðч ÿâàà õ¿íèéã Ýä ñ¿éòãýãýч ãýýä õýëчèõëýý /ñóðàãч/Õîñîîðîî áàéõäàà àìüñãàëûã òýòãýäýã Ãóðàâëààä áàéõäàà àìüäðàëûã õàìãààëäàã Àìò ¿íýð ºíãºã¿é Àòãàæ áàðèõ áèåã¿é /õ¿чèëòºðºãч/
    • Ç îð è ë mÓñòºðºãч,óñòºðºãчèéí áàéãàëü äàðõàëòûí òàëààð ìýäýýëýë áîëîâñðóóëàõ.Óñòºðºãчèéã ãàðãàí àâàõ àðãûã ñóäëàõ.Óñòºðºãчèéã èëð¿¿ëýõ,ôèçèê øèíæèéã ñóäëàõ
    • Í2-í äàðààõ øèíæ¿¿äèéã òîäîðõîéë.Õèìèéí òýìäýã HÂàëåíò чàíàð IÕàðüöàíãóé Ar 1Õàðüöàíãóé Mr 2Ìîëèéí ìàññ 2ã/ì
    • Ñóðàõ áèчãèéí 113-114ð õóóäñûãóíøèæ óñòºðºã÷èéí òàëààðõ ìýäýýëýëöóãëóóëæ, áàãààðàà õàðèëöàíÿðèëöàæ ìýäýýëëýý áóñàä áàãóóäàäòàéëàãíààðàé. /5 ìèíóò/
    • Ó ñ ò ºð ºã чÀíãëèéí õèìèч Ã.Êàâåíäèø 1766 îíä õ¿÷ëèéã ìåòàëëààð ¿éëчëýõ çàìààð ãàðãàí àâñàí áà “øàòäàã àãààð” ãýæ íýðëýñýí.Óñíû íàéðëàãàíä îðîëöäîã õèé áîëîõûã òîãòîîæ óñ òºð¿¿ëýãч ãýæ íýð ºãчýý.Óñòºðºãч àãààð ìàíäëûí äîîä äàâõàðãàä áàãà, 50 êì-í äýýð ýçýëõ¿¿íèé 3% 100êì-ä 95% àãóóëàãäàíà.Äýëõèéí ãàçðûí öàðöäàñûí ìàññûí 1%-ã ýçýëäýã.
    • ¯ ã ýë æ ë ýë ðÍàð,îääûí ¿íäñýí õýñýã íü óñòºðºãч áàéäàã./̺í ãåëè áàéäàã./Áàãàëèéí õèé øàòàìõàé õèé áîëîí áóñàä îðãàíèê íýãäëèéí íàéðëàãàä îðîëöäîã.Àãààðûí áºìáºëºã ä¿¿ðãýõýä àøèãëàíà.
    • Óñòºðºãч ãàðãàí àâàõ1.Óñûã öàõèëãààíààð çàäàëæ ãàðãàí àâíà. 2H2O = 2H2 + O22.Ìåòàëë öàéðûã õ¿чëýýð ¿éëчèëæ Zn + 2HCL = ZnCL2 + H2 öàéð äàâñíû õ¿чèë öàéðûí õëîðèä óñòºðºãч3.Èäýâõòýé ìåòàëëûã óñòàé ¿éëчë¿¿ëæ 2Na + 2HOH = 2NaOH + H2 íàòðè óñ íàòðèéí ãèäðîêñèä óñòºðºãч
    • Óñòºðºãч àãààðààñ õºíãºí óчèð ò¿¿íèéã óñ áà àãààðûã ò¿ðýõ çàìààð ãàðãàí àâíà.
    • ÎíüñîãîÄýýøýý äýýøýý õººðººõýéÄýãäýõ áºìáºã æîëîîäîîõîéÄýíä¿¿ àìàðõàí øàòààõàéÄýðýãäýõ íºõºäòýéãýý íýãäýýõýé /óñòºðºãч/
    • ¯ã ç¿éí òààâàðÀíõíû ¿ã íü ò¿ãýýìýë óóñãàãчèéí íýðÀðûí ¿ãèéã íü ãóðàâ õóâààчèõÝõíèé ãóðâàí ¿ñýã íüÓëñ ãýäãèéí õîëáîî ¿ãÄàðààãèéí õî¸ð ¿ñýã íüÀâ ãýäãèéí ýñðýã ¿ãÀðäàõ ¿ñýã íü çàðèìäàã ãèéã¿¿ëýãч /óñòºðºãч/
    • Äàñã àë......+......=……/Ëèòèéí ãèäðèä/......+......=....../õ¿õýðò óñòºðºãч/......+......=....../Áàðèéí ãèäðèä/
    • Äàñãàë/õàðèó/2Li + H2 = 2LiH /ëèòèéí ãèäðèä/S +H2 =H2S /õ¿õýðò óñòºðºãч/Ba +H2=BaH2 /áàðèéí ãèäðèä/
    • Ãýðèéí äààëãàâàðÕî¸ð áàãàíàíä áóé ºãºãäëèéã àæèãëàæ õîîðîíäîî ÿìàð õîëáîîòîé áîëîõûí òîãòîîæ õîëáîæ çóð.À.õºíãºí 1.àãààðûã ò¿ð¿¿ëýõ çàìààðÁ.óñàíä óóñàõã¿é 2.óñûã ò¿ð¿¿ëýõ çàìààðÂ.àíãèæðóóëàãч 3.àãààðûí áºìáºëºã ä¿¿ðãýõÃ.õ¿чòýé òýñðýëò 4.ïóóæèíãèéí ò¿ëø ¿¿ñãýí øàòäàã 5.Ìåòàëë ãàðãàí àâàõ