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The Mole



      Formula
    Calculations


            I   II   III
A. Percentage Composition
     s the
         percentage by mass of each
      element in a compound

                 mass of element
% compositio n =                 × 100
                   total mass
A. Percentage Composition
s Find   the % composition of Cu2S.

          127.10 g Cu
%Cu =                  × 100 =
         159.17 g Cu2S
                         79.852% Cu
          32.07 g S
%S =                    × 100 =
        159.17 g Cu2S
                          20.15% S
A. Percentage Composition
s Find the percentage composition
 of a sample that is 28 g Fe and
 8.0 g O.
         28 g
%Fe =           × 100 = 78% Fe
         36 g
         8.0 g
%O =             × 100 = 22% O
         36 g
A. Percentage Composition
s How  many grams of copper are in
  a 38.0-gram sample of Cu2S?

Cu2S is 79.852% Cu

(38.0 g Cu2S)(0.79852) = 30.3 g Cu
A. Percentage Composition
s Findthe mass percentage of
 water in calcium chloride
 dihydrate, CaCl2•2H2O?


%H2O =   36.04 g    × 100 = 24.51%
         147.02 g            H2O
B. Empirical Formula
s Smallestwhole number ratio of
 atoms in a compound

             C2H6
                 reduce subscripts


             CH3
B. Empirical Formula
1. Find mass (or %) of each element.
2. Find moles of each element.
3. Divide moles by the smallest # to
   find subscripts.
4. When necessary, multiply
   subscripts by 2, 3, or 4 to get
   whole #’s.
B. Empirical Formula
s Find
     the empirical formula for a
 sample of 25.9% N and 74.1% O.

25.9 g 1 mol     = 1.85 mol N
                              =1N
         14.01 g    1.85 mol

74.1 g 1 mol     = 4.63 mol O
                              = 2.5 O
         16.00 g    1.85 mol
B. Empirical Formula

          N1O2.5
Need to make the subscripts whole
 numbers ⇒ multiply by 2



          N2O5
C. Molecular Formula
s “True Formula” - the actual number
  of atoms in a compound

                   CH3
 empirical
 formula

                         ?



                  C2H6
 molecular
 formula
C. Molecular Formula
1. Find the empirical formula.
2. Find the empirical formula mass.
3. Divide the molecular mass by the
   empirical mass.
4. Multiply each subscript by the
   answer from step 3.
 MF mass
 EF mass
         =n         ( EF ) n
C. Molecular Formula
s The  empirical formula for ethylene
 is CH2. Find the molecular formula
 if the molecular mass is
 28.1 g/mol?
    empirical mass = 14.03 g/mol
         28.1 g/mol
                       = 2.00
         14.03 g/mol
        (CH2)2 ⇒ C2H4

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Formula ppt

  • 1. The Mole Formula Calculations I II III
  • 2. A. Percentage Composition s the percentage by mass of each element in a compound mass of element % compositio n = × 100 total mass
  • 3. A. Percentage Composition s Find the % composition of Cu2S. 127.10 g Cu %Cu = × 100 = 159.17 g Cu2S 79.852% Cu 32.07 g S %S = × 100 = 159.17 g Cu2S 20.15% S
  • 4. A. Percentage Composition s Find the percentage composition of a sample that is 28 g Fe and 8.0 g O. 28 g %Fe = × 100 = 78% Fe 36 g 8.0 g %O = × 100 = 22% O 36 g
  • 5. A. Percentage Composition s How many grams of copper are in a 38.0-gram sample of Cu2S? Cu2S is 79.852% Cu (38.0 g Cu2S)(0.79852) = 30.3 g Cu
  • 6. A. Percentage Composition s Findthe mass percentage of water in calcium chloride dihydrate, CaCl2•2H2O? %H2O = 36.04 g × 100 = 24.51% 147.02 g H2O
  • 7. B. Empirical Formula s Smallestwhole number ratio of atoms in a compound C2H6 reduce subscripts CH3
  • 8. B. Empirical Formula 1. Find mass (or %) of each element. 2. Find moles of each element. 3. Divide moles by the smallest # to find subscripts. 4. When necessary, multiply subscripts by 2, 3, or 4 to get whole #’s.
  • 9. B. Empirical Formula s Find the empirical formula for a sample of 25.9% N and 74.1% O. 25.9 g 1 mol = 1.85 mol N =1N 14.01 g 1.85 mol 74.1 g 1 mol = 4.63 mol O = 2.5 O 16.00 g 1.85 mol
  • 10. B. Empirical Formula N1O2.5 Need to make the subscripts whole numbers ⇒ multiply by 2 N2O5
  • 11. C. Molecular Formula s “True Formula” - the actual number of atoms in a compound CH3 empirical formula ? C2H6 molecular formula
  • 12. C. Molecular Formula 1. Find the empirical formula. 2. Find the empirical formula mass. 3. Divide the molecular mass by the empirical mass. 4. Multiply each subscript by the answer from step 3. MF mass EF mass =n ( EF ) n
  • 13. C. Molecular Formula s The empirical formula for ethylene is CH2. Find the molecular formula if the molecular mass is 28.1 g/mol? empirical mass = 14.03 g/mol 28.1 g/mol = 2.00 14.03 g/mol (CH2)2 ⇒ C2H4