OOPs difference faqs- 4
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OOPs difference faqs- 4



This provides a list of OOPs FAQs-4 which are of "Difference between" kind

This provides a list of OOPs FAQs-4 which are of "Difference between" kind



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OOPs difference faqs- 4 OOPs difference faqs- 4 Document Transcript

  • 1.Difference between String and StringBuilder S.No String StringBuilder 1 String class belongs to the StringBuilder class belongs to the namespace System. namespace System.Text. 2 String class is immutable. StringBuilder class is mutable. Immutable means that the string Consider the following example: cannot be changed. Consider the class sampleClass { following example: public static void Main() { class sampleClass { StringBuilder sampleSB = new public static void Main() { StringBuilder("Hai",10); string sampleStr = "Hai"; sampleSB = new sampleStr = "Hello"; StringBuilder("Hello"); Console.WriteLine(sampleStr); Console.WriteLine(sampleSB); } } } } Output of this code will be: Output of this code will be: Hello Hello In this example, you have created In this example, you are doing the a string called sampleStr. You same thing. But the string "Hai" will have initially assigned the value be overwritten as "Hello" and no new "Hai". And then you try to strings will be created in the memory. overwrite its value with "Hello". You get the overwritten value as output. But the problem lies in the number of strings that get created in memory. When you create the string as "Hai", this string gets created in the memory. When you try to change the value to "Hello", instead of overwriting the existing "Hai" string it will create a new string in the memory and assign this new string "Hello" to sampleStr. 3 You can directly assign a string to You cannot directly assign a string to string class instance. For example, StringBuilder instance. For example, String sampleStr = "Hai" is valid. StringBuilder sampleSB = "Hai" will lead to the following error: "cannot implicitly convert type string to System.Text.StringBuilder " You can assign a string to StringBuilder using the following statement: StringBuilder sampleSB = new StringBuilder("Hai"); 4 String concatenation is done using String concatenation is done using
  • + operator. Here is an example: Append method. Here is an example: class sampleClass { class sampleClass { public static void Main() { public static void Main() { string sampleStr = "Hello!"; StringBuilder sampleSB = new sampleStr += " Good Day!"; StringBuilder("Hello!"); Console.WriteLine(sampleStr); sampleSB.Append("Good } Day!"); } Console.WriteLine(sampleSB); Output of this code will be: } Hello! Good Day! } Here you have used += operator Output of this code will be: to perform both concatenation and Hello! Good Day! assignment using single operator. You can also use + and = separately as shown below: sampleStr = sampleStr + " Good Day!";5 During string concatenation, During string concatenation, additional additional memory will be memory will be allocated if and only if allocated. the string buffers capacity is reached.6 During string concatenation, If the number of concatenations to be additional memory will be done is random or not known, then it is allocated if and only if the string recommended to use stringBuilder buffers capacity is reached.7 You cannot set a limit (specifying You can set a limit to StringBuilder how many strings can be using the member called capacity concatenated) to a string object which will by default have the value using string class. 16. You can override it to any number. The maximum value acceptable is equivalent to MaxValue of Int32. If you feel that you do not want to reserve 16 as the capacity then you can very well redefine it. However the capacity will dynamically grow based on the number of strings that you append. Here is an example demonstrating the usage of capacity: class sampleClass { public static void Main() { StringBuilder sampleSB = new StringBuilder(); Console.WriteLine( sampleSB.Capacity); sampleSB.Capacity = 1; Console.WriteLine( sampleSB.Capacity);
  • sampleSB.Append("str1"); sampleSB.Append("str2"); Console.WriteLine( sampleSB.Capacity); } } Output of this code will be: 16 1 82.Difference between Delegate and Interface S.No Delegate Interface 1 Delegates can only be methods. Interface can include both properties Here is an example: and methods. delegate void sampleDelegate(); Here is an example for an interface: interface ItestInterface { int paraml { get; set; } void sampleMethod(); } 2 Delegate can be applied to only When a class implements an interface, one method at a time it can implement all the methods associated with it 3 You can use a delegate that is You can use an interface only when visible in your scope your class or struct implements it 4 Within a class, you can implement Within a class, you can implement an the same delegate any number of interface method only once. In times. Assume that either Example2, interface ITestInterface has sampleClass1 or sampleClass2 of a method called sampleMethod(). Examplel includes a method When sampleClass1 implements called sampleMethod2( ) with the ITestInterface it implements same signature as that of delegate, sampleMethod() only once. If not, then then the same delegate can be it will end up in error. used to access both sampleMethod() as well as sampleMethod2( ) 5 Delegate can implement any When an interface method is method that shares the same implemented, same method name and signature as that of the delegate signature has to be overridden 6 Delegate is mainly used for Interfaces are not used for handling handling events events
  • 7 You need not bother about the When a class implements an interface, other methods available in the though the class requires only one class.You are concerned about method it has to implement all the only the method that matches methods of the interface delegate signature.8 To access a method using To access the method, you need an delegate, you need not require any instance of the class which implements access to the instance of the class the interface or you need an interface where the method is defined reference pointing to the method implemented by the class9 You can access anonymous You cannot access anonymous methods using delegates methods.Only named methods declared in interface can be accessed by the implementing class.10 When you call a method using a When you are calling a method using delegate, all the method pointers interface reference, you are directly associated with the delegate will accessing the method of the class that be scanned through before the implements the interface. This is a method execution. This is not a direct method call and it doesnt have direct method call as you assume. any overhead. It has a considerable performance overhead.11 Delegates can wrap methods of Accessing sealed types is not sealed classes.Sealed classes are permissible in interface. those which cannot be inherited.12 Delegates can wrap any method Class can implement any number of matching its signature irrespective interfaces and it should override only of which ever class the method the methods belonging to those belongs to interfaces13 Delegates can wrap static This provision is not available with methods. Examplel discussed interfaces . above has used the delegate to wrap a static method called sampleMethod()14 Delegate cannot involve in Interface can inherit other interfaces. inheritance. When a class implements that interface, it has to implement all the methods belonging to the interface and its inherited interfaces as well. Here is an example of an interface inheriting from other interfaces: interface IInterface: IInterface,1 IInterface2 { void sampleMethod1(); void sampleMethod2();
  • s}Example1: Using Delegatedelegate void sampleDelegate( );class sampleClass1{static void sampleMethod( ) {Console.WriteLine(“Executing sampleMethod of sampleClass1”);}}class sampleClass2 {static void Main( ) {sampleDelegate dele1 = new sampleDelegate(sampleClass1.sampleMethod);dele1();}}Example2: Using Interfaceinterface ITestInterface{void sampleMethod( );}class sampleClass1 : ITestInterface {void sampleMethod( ) {Console.WriteLine(“Executing sampleMethod of sampleClass1”);}}class sampleClass2 {static void Main( ) {sampleClass1 obj1 = new sampleClass1( );obj1.sampleMethod( );}}3.Difference between Virtual and Abstract keywords in .NET S.No Virtual Abstract 1 If you feel that the derived class But if you want to enforce that derived may or may not override the base class must override the base class class method, then you will define method then you will define the base the base class method as virtual. class method as abstract. Consider the following example: namespace Application1 { namespace Application1 { public abstract class abstractClass { public class virtualClass { public abstract void abstractMethod(); public virtual void } virtualMethod(){ public class Console.WriteLine("Virtual derivedClass:abstractClass{ Method.."); public override void abstractMethod(){ } Console.WriteLine("Overridden..");
  • } } public class } derivedClass:virtualClass{ public class testClass { public override void public static void Main() { virtualMethod(){ derivedClass obj = new Console.WriteLine("Overridden.." derivedClass(); ); obj.abstractMethod(); } } } } public class testClass { } public static void Main() { Output of this code will be: virtualClass obj = new Overridden.. virtualClass(); obj.virtualMethod(); derivedClass dObj = new derivedClass(); dObj.virtualMethod(); } } } Output of this code will be: Virtual Method.. Overridden..2 Virtual methods need not be Abstract methods should compulsorily compulsorily overridden. In the be overridden by the derived class. In above example if the derived class the above example, if the derivedClass does not override the method does not override abstractMethod, then virtualMethod, then again the during compilation you will get the code will work. following error: Application1.derivedClass does not implement inherited abstract member Application1.abstractClass.abstractMe thod()3 To define a base class method to If you want to define a method as be virtual, you need not include abstract in the base class then the base any new definition for the base class should also be marked as class. In the earlier example, you abstract. Consider the following can see that the class virtualClass example: just includes an access modifier namespace Application1 { followed by the class name. No public class abstractClass { other additional modifiers are public abstract void abstractMethod(); required. } } In this example, abstractClass has an abstract method. Hence the class in itself has to be marked abstract. But it is not done in the above example. Therefore during compilation, you will end up in the following error: Application1.abstractClass.abstractMe
  • thod() is abstract but it is contained in nonabstract class Application1.abstractClass4 Virtual method can have a method Abstract methods have only the body. In the earlier example, signature. It cannot have method body. virtualMethod of virtualClass has However the abstract class can include method definition like any of the non-abstract methods and these other methods that you define and methods can have method body it is perfectly legal. defined. Consider the following example: namespace Application1 { public abstract class abstractClass { public abstract void abstractMethod(){ Console.WriteLine("Abstract method.."); } } } Here you are trying to include method body for an abstract method. This is not permissible. Hence during compilation you will end up in the following error: "Application1.abstractClass.abstractM ethod() cannot declare a body because it is marked abstract"5 Class containing virtual method Class containing abstract method can be instantiated. Here is an cannot be instantiated. It can only be example: inherited. Consider the following namespace Application1 { example: public class virtualClass { namespace Application1 { public virtual void public abstract class abstractClass { virtualMethod(){ public abstract void abstractMethod(); Console.WriteLine("Virtual } Method.."); public class testClass { } public static void Main() { } abstractClass obj = new Public class testClass { abstractClass(); public static void Main() { } virtualClass obj = new } virtualClass(); } obj.virtualMethod(); Here you are trying to create an } instance of abstract class. This is not } possible. Hence during compilation } you will end up in the following error: Output of this code will be: "cannot create an instance of the Virtual Method… abstract class or interface Application1.abstractClass"6 Not just methods, virtual modifier Apart from class and method, the
  • can also be used with properties. modifer abstract can be associated with properties, events and indexers. 7 There is a restriction when using Abstract modifiers also have a virtual modifer. You cannot use restriction. They cannot be used along this modifer along with static or with static or virtual or override abstract or override modifiers. modifiers.And, further updates on difference between questions and answers, please visit my blog @http://onlydifferencefaqs.blogspot.in/