Management Aptitude Test 3 November

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  • 1. MANAGEMENT APTITUDE TEST AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME – World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship OPEN FOR ALL FREE FOR ALL
  • 2. MANAGEMENT APTITUDE TEST Dr. T.K. Jain. AFTERSCHO☺OL Centre for social entrepreneurship Bikaner M: 9414430763 [email_address] www.afterschool.tk , www.afterschoool.tk
  • 3. The area of a rectangular field is 52000 m This rectangular area has been drawn on a map to the scale 1 cm to 100 m. The length is shown as 3.25 cmon the map. The breadth of the rectangular field is (a) 300.5 m (b) 200.5 m (c) 160 m (d) 150m
    • =52000/325 = 160 METERS.
  • 4. A recIa lawn 60 metres by 40 metres has two roads each 5 metres wide running in the middle of it, one parallel to length and the other parallel to breadth The cost of gravelling the roads at 60 paise per sq. metre is: (a) Rs. 300 (b) Rs. 280 (c) Rs. 285 (d) Rs. 250
  • 5. SOLUTION
    • TOTAL AREA OF ROAD:
    • Length = 5*60 = 300
    • Width direction = 5*40 = 200
    • Total 500
    • Less common area = 5*5 = 25.
    • Thus total road is 475
    • Total cost = 475 * .6 = Rs. 285 answer.
  • 6. A sum of Rs. 18.45 is made up of 90 coins which are either. 10 paise coins or 25 paise coins. Find the number of each type of coins.
    • = 18.45/90 = .205 or 20.5 paise
    • Using the principles of mixture, we can solve it :
    • Thus ratio is 45:105
    • Or 9:21 answer.
    10 4.5 10.5 25 Mixture 20.5
  • 7. A circle is inscribed inside a square. The ratio of the area of the circle to the area of the square is pi/4 , Find the radius of the inscribed circle. 4,6,8,10,cant be determined
    • Cannot be determined – because this ratio is always Pi to 4 answer.
  • 8. A square and a rhombus share the same base, however, the rhombus is inclined by 30degree. What is the ratio of the area of the square of that of the rhombus ? 1: 1 , 3:2 2:1
  • 9. Solution
    • Area of rhombus = base * hight
    • Let us assume the base to be 4.
    • Area of square= 16
    • As the angle is 30 degree, the height is half of hypoteneuse = 2.
    • Thus area of rhomus is 4*2 = 8
    • Thus the ratio is 2:1 answer.
    • Rhombus & square
  • 10. Triangle PQR is inscribed in a semi-circle. What is the area of the shaded portion ?
  • 11. Solution
    • Length of PR = sqrt(4^2 + 6^2)
    • = sqrt(16 + 36)
    • =sqrt (52) = 7.21
    • Radius = 3.605
    • Area of semi circle:
    • =22/7 * 3.605*3.605 = 40.84/2 = 20.42
    • Area of triangle = ½(4*6) = 12
    • Area of shaded region = 8.42 answer. `
  • 12. A boat sails 18 km of a river stretch upstream in 6 hours and takes only 4½ hours to cover the same distance downstream. What is the speed of the current? 0.5 kmph 1.5 kmph 3.5 kmph
  • 13. Solution
    • 18/6 = 3 km per hour (speed upstream)
    • 18/4.5 = 4 km per hour (speed downstream)
    • Average of these two is 3.5 and the speed of water is .5 km per hour
    • Or
    • (4-3)/2 = .5 KM per hour.
  • 14.
    • Two friends ‘Bitthal’ and ‘Sunny’ start from the same point at the same time in the same direction on a circular cycle track 4 Km long. ‘Bitthal’ travels at a speed of 8 KM / Hour while ‘Sunny’ moves at 11 KM/hour When do they meet at the starting point again for the first time?
  • 15. Solution
    • Bitthal takes 30 minutes
    • Sunny takes 4/11*60 = 21.81 minutes
    • Now we shall take LCM of these:
    • 218.1 minutes or 3.63 hours
    • Or 3 hours and 38 minutes after the start of the race.
  • 16.
    • Two friends ‘Bitthal’ and ‘Sunny’ start from the same point at the same time in the same direction on a circular cycle track 4 Km long. ‘Bitthal’ travels at a speed of 8 KM / Hour while ‘Sunny’ moves at 11 KM/hour When do they meet again for the first time?
  • 17. Solution
    • Difference of their speed is 11-8 = 3
    • They will meet again at 4/3*60 = 80 minutes
    • Answer.
  • 18.
    • Two friends ‘Hulash and ‘Rajesh’ start from the same point at the same time on a circular track, with ‘Hulash’ moving in the clockwise direction and ‘Rajesh’ in the anti-clockwise direction. The circumference of the track is 336 m. ‘Hulash’ moves at 6 m/s and ‘Rajesh’ moves at 8 m/s. When do they meet again for the first time?
  • 19. Solution
    • 336 / (8+6)
    • =24 seconds
  • 20.
    • Two friends ‘Hulash and ‘Rajesh’ start from the same point at the same time on a circular track, with ‘Hulash’ moving in the clockwise direction and ‘Rajesh’ in the anti-clockwise direction. The circumference of the track is 336 m. ‘Hulash’ moves at 6 m/s and ‘Rajesh’ moves at 8 m/s. When do they meet again at the starting point for the first time?
  • 21. Solution
    • Hulash 336/6 = 56 seconds per round
    • Rajesh 336/8 = 42 seconds per round
    • LCM of 56 and 42 is 168 seconds
    • So they will meet at the starting point again after 168 or 2 minutes and 48 seconds. Answer.
  • 22. Time and work
    • Two taps ‘A’ and ‘B’ can individually fill a tank in 12 and 18 hours respectively. The tan is already one third full. Both taps are opened and after 3 hours, tap ‘B’ is shut. How much more time will it take us to fill the the tank?
  • 23. Solution …
    • 1/12 + 1/18
    • =5/36 in one hour or 36/5 hours to fill the complete tank. But we have to fill only 2/3 so it will take 24/5 hours to fill it. Both the pipes are kept open for 3 hours. 3*5/36 = 15/36 is again filled.
    • =1 – (15/36 + 12/36) =9/36;
    • So only 9/36 is left out.
    • A can fill it in : 12*9/36 = 3 hour only
  • 24.
    • ‘A’ is 20% more efficient than ‘B’. If they complete a piece of work in 30 days; in how many days would ‘A’ working alone complete the same work?
    • 1] 55 2] 66 3] 60
  • 25. Solution
    • Let us assume that A takes X days. B will take 1.2 X days.
    • Let us assume that 1/x = Y
    • Y + Y /1.2 = 1/30
    • 2.2Y = 1.2 /30
    • Y = 1/55
    • That means A can do the work in 55 days alone. Answer.
  • 26.
    • Two taps ‘A’ and ‘B’ individually fill a tank in 8 and 12 hours respectively. There is a tap ‘C’ which can empty the entire tank in 24 hours. If the tank is empty, and all 3 taps are opened simultaneously, in how much time will it be full?
    • 1] 6 2] 7 3] 5 4] It will never fill up
  • 27. Solution
    • 1/8 + 1/12 – 1/24
    • = (3+2 – 1)/24
    • =4/24 = 1/6 or in 6 hours the tank will be filled up.
  • 28.
    • Two taps ‘A’ and ‘B’ can individually fill a tank in 16 and 24 hours respectively. A leak in the tank can empty the entire tank in 9 hours. If the tank is empty and both the taps are opened, how much time does it take the tank to be full?
    • 8 10 12 Cannot be filled
  • 29. Solution
    • 1/16 + 1/24 – 1/9
    • (9+6 – 16) / 144
    • Here we can see that the answer is coming in negative. Thus the tank can never be filled up (unless the leak is removed). Answer.
  • 30. 78.8% of a common medicine for stomach-upsets is absolute alcohol; 3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177% chloroform. How much of each of these compounds is there in a pack of 30 ml? solution alchol = 23.6 ml, 1 ml of menthol oil and so. On.
  • 31. Seven digits from the numbers 1,2,3,4,5,6,7,8 and 9 are written in random order. the probability that this seven-digit number is divisible by 9 is
    • You need a total which is multiple of 9
    • 1/9 answer. .
  • 32. IF D IS OF 80 DEGREE, WHAT IS THE MEASURE OF C?
  • 33. SOLUTION
    • Both the angles are on AB. Angles on one segments are always equal, therefore D and C are equal = both with 80 angle.
  • 34. What is the sum of cubes of the first 5 natural numbers?
    • Formula
    • = [N (N+1)/2 ]^2
    • = [5*6 / 2 ]^2
    • =225 answer.
  • 35. What is the sum of squares of the first 13 natural numbers?
    • Formula
    • =[n(n+1)(2n+1) ] /6
    • =(13*14*27)/6
    • =819 answer.
  • 36. In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls in the class.
    • Let the number of girls be X
    • X + 3/5X = 80
    • 8/5 X = 80
    • X = 80 *5/8
    • X = 50 (the number of girls is 50, boys are 30) answer.
  • 37. The difference between two numbers is 30. On dividing the greater by the smller the quotient is 3. Find the numbers.
    • Let the smaller number be X.
    • 3X – X = 30
    • 2X =30; X = 15,
    • Thus 2 numbers are 15 and 45 answer.
  • 38. Gunpowder contains 75% nitre and 10% sulphur. The rest of it is charcoal. What is the amount of charcoal in 9 kg of gunpowder.
    • Charcoal is (100 – 75 – 10) = 15%
    • 9 KG = 9000 Grams
    • 9000*15/100
    • =1350 grams answer.
  • 39. Question on profit
    • At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%?
    • (a) 48% (b) 43%
    • (c) 40% (d) 38%
    • (e) None of the above
  • 40. Solution …
    • Let the cost be 100
    • Final price being realised 133
    • It is after discount, so price before discount (marked price) is :
    • 133*100/95 =140 , so 40 is the answer.
  • 41. A vertical pole PO is standing at the centre 0 of a square ABCD. If AC subtends an angle 90° at point P of the pole then the angle subtended by a side of the square at P is (a) 35° (b) 45° (c) 30° (d) 60° (e) None of the above
  • 42. Solution
    • When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule).
    • So answer is 60 degrees.
  • 43. Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent per cent pure gold.
    • 22/24 *100
    • =91.67 % answer.
  • 44. In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is the perimeter of the region marked B?
  • 45. Solution
    • Permieter of one circle is 2/3 now because, it is being cut by other circle.
    • Thus 2/3 + 2/3 of perimeters added :
    • 2 * 2/3 * (formula of perimeter = 2pi *r)
    • =(8 * pi * r) /3 answer.
  • 46. What is angle C?
  • 47. Solution
    • Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer.
  • 48. What is angle a?
  • 49. Solution
    • Angles from D and C are equal .
    • 180 – 60 – 37 – x
    • =83 – x
    • Let us sum up for two angles:
    • (180+180 ) = 360
    • 83-x + 83 – x + 180+2X = 360
    • 2Y +2X = 180 let us assume Y = 53
    • 2X = 72 or X = 36 answer (solve by options, so angle A = 53 ) answer.
  • 50. ABOUT AFTERSCHO☺OL
    • Afterschoool conducts three year integrated PGPSE (after class 12 th along with IAS / CA / CS ) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM . This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society.
  • 51. Why such a programme?
    • To promote people to take up entrepreneurship and help develop the society
    • To enable people to take up franchising and other such options to start a business / social development project
    • To enable people to take up social development as their mission
    • To enable people to promote spirituality and positive thinking in the world
  • 52. Who are our supporters?
    • Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us.
    • You can also support us – not necessarily by money – but by being promotor of our concept and our ideas.
  • 53. About AFTERSCHO☺OL PGPSE – the best programme for developing great entrepreneurs
    • Most flexible, adaptive but rigorous programme
    • Available in distance learning mode
    • Case study focused- latest cases
    • Industry oriented practical curriculum
    • Designed to make you entrepreneurs – not just an employee
    • Option to take up part time job – so earn while you learn
    • The only absolutely free course on internet
  • 54. Workshops from AFTERSCHO☺OL
    • IIF, Delhi
    • CIPS, Jaipur
    • ICSI Hyderabad Branch
    • Gyan Vihar, Jaipur
    • Apex Institute of Management, Jaipur
    • Aravali Institute of Management, Jodhpur
    • Xavier Institute of Management, Bhubaneshwar
    • Pacific Institute, Udaipur
    • Engineering College, Hyderabad
  • 55. Flexible Specialisations:
    • Spiritualising business and society
    • Rural development and transformation
    • HRD and Education, Social Development
    • NGO and voluntary work
    • Investment analysis,microfinance and inclusion
    • Retail sector, BPO, KPO
    • Accounting & Information system (with CA / CS /CMA)
    • Hospital management and Health care
    • Hospitality sector and culture and heritage
    • Other sectors of high growth, high technology and social relevance
  • 56. Salient features:
    • The only programme of its kind (in the whole world)
    • No publicity and low profile course
    • For those who want to achieve success in life – not just a degree
    • Flexible – you may stay for a month and continue the rest of the education by distance mode. / you may attend weekend classes
    • Scholarships for those from poor economic background
    • Latest and constantly changing curriculum – keeping pace with the time
    • Placement for those who are interested
    • Admissions open throughout the year
    • Latest and most advanced technologies, books and study material
  • 57. Components
    • Pedagogy curriculum and approach based on IIM Ahmedabad and ISB Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)
    • Meditation, spiritualisation, and self development
    • EsGotitial softwares for business
    • Business plan, Research projects
    • Participation in conferences / seminars
    • Workshops on leadership, team building etc.
    • Written submissions of research projects/articles / papers
    • Interview of entrepreneurs, writing biographies of entrepreneurs
    • Editing of journals / newsletters
    • Consultancy / research projects
    • Assignments, communication skill workshops
    • Participation in conferences and seminars
    • Group discussions, mock interviews, self development diaryng
    • Mind Power Training & writing workshop (by Dr. T.K.Jain)
  • 58. Pedagogy
    • Case analysis,
    • Articles from Harvard Business Review
    • Quiz, seminars, workshops, games,
    • Visits to entrepreneurs and industrial visits
    • PreGotitations, Latest audio-visuals
    • Group discussions and group projects
    • Periodic self assessment
    • Mentoring and counselling
    • Study exchange programme (with institutions out of India)
    • Rural development / Social welfare projects
  • 59. Branches
    • AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.
  • 60. Case Studies
    • We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.
  • 61. Basic values at AFTERSCHO☺OL
    • Share to learn more
    • Interact to develop yourself
    • Fear is your worst enemy
    • Make mistakes to learn
    • Study & discuss in a group
    • Criticism is the healthy route to mutual support and help
    • Ask fundamental questions : why, when, how & where?
    • Embrace change – and compete with yourself only
  • 62. www.afterschoool.tk social entrepreneurship for better society