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  • 1. MANAGEMENT APTITUDE TEST AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME – World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship OPEN FOR ALL FREE FOR ALL www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 2. MANAGEMENT APTITUDE TEST Dr. T.K. Jain. AFTERSCHO☺OL Centre for social entrepreneurship Bikaner M: 9414430763 tkjainbkn@yahoo.co.in www.afterschool.tk, www.afterschoool.tk www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 3. The ratio of the rate of flow of water in pipes varies inversly as the square of the radius of the pipes. What is the ratio of the rates of flow in 2 pipes of diameter 2 cm and 4 cm • Solution : ratio (1/2)^2 : (1/4)^2 = ¼: 1/16 • Thus their ratio is 4:1 answer.
  • 4. Salaries of A, B and C were in the ratio 3 : 5: 7, respectively. If their salaries were increased by 50%, 60% and 40% respectively, what will be the new ratio of their respective salaries? • Let us assume that their salaries are : 300,500, 700. New salaries are : 450,800,980. Their new ratio is 45:80:98
  • 5. Solve it … • When a bus started from the first stop, the number of male passengers to the number of female passengers was 3 : 1. At the first stop 16 passengers got down and 6 more female passengers got in. The ratio of the male to female passengers now became 2: 1. What was the total number of passengers in the bus when it started from the first stop?
  • 6. Solution • Let us assume the number of females in the beginning to be X. • So : (3X -16)/ (X +6) = 2/1 • 3X -16 = 2X +12 • X = 28 • Thus total passengers was : 28*4 = 112 answer.
  • 7. Solve it • Given that 24 carat gold is pure gold, 18 carat gold is ¾ gold and 20 carat gold is 5/6 gold, the ratio of the pure gold in 18 carat gold to the pure gold in 20 carat gold is • Soluton… • ¾ : 5/6 = 18: 20 or 9:10 answer.
  • 8. A started a business with $ 4500 and another person B joined after some period with $ 3000. Detemine this period before B joined the business if the profit at the end of the year is divided in the ratio 2 : 1 • Capital * period for A = 4500 * 12 = 54000 • For B it is half of it 27000, dividing it by 3000 gives 9 months. Thus B joined after 3 months. (answer).
  • 9. A began a business with $ 4,500 and was joined.afterwards by B with $ 5,400. If the profits at the end of the year were divided in the ratio 2 : 1, B joined the business after … months?? • Like the last question: 4500*12 = 54000 • B has ½ of it: 27000 • 27000/5400 = 5 months. Thus B joined after 7 months. Answer.
  • 10. The monthly incomes of two persons are in the ratio of 4: 5 and their monthly expenditures are in the ratio of 7: 8. If each saves Rs. 50 a month then what are their monthly incomes? • 4X – 7Y = 50 or 20 X – 35Y = 250 • 5X –8 Y = 50or 20 X -32 Y = 200 • Y = 50/3 = 16.6. Thus expenses of first person is 116 and income is 166. Similarly income of 2nd person can be identified.
  • 11. A salesman averages Rs. 240 during a normal 40 hour week. During a sale, his rates are increased by 50%. What Is his commission if he puts in 60 hours during the sale? • Commission during 40 hours 240, so it should be 60/40 *240 = 360 during 60 hours. • It is further increased by 50%, so it should be 540 instead of 360. (360 *1.5) Answer.
  • 12. A machine is sold at a profit of 10%. Had it been sold for Rs. 40 less, there would have been a loss of 10%. What was the cost price? • Let us assume that the cost of machine is 100, it is sold at 110. when it is sold in loss, it will sale at 90. The difference is Rs. 20 i.e. (110-90) • If the difference is 20, cost is 100, if the difference is 40, cost should be 200. Answer.
  • 13. If 50% of the 2 : 3 solution of milk and water is replaced with water, then the concentration of the solution is reduced by: • Let us assume that total mixture is 10 liters. Now we reduce it to 5 liters and add 5 lt. water. Total water now becomes (3+5) = 8 liters and concentration is reduced from 40% (4 liters out of 10 liters) to 20% (2liters out of 10 liters). Thus there is reduction of 50%. Answer.
  • 14. Normally, numbers are written with a base of 10. Binary number have a base of 2. In which base can 19257 be written as 110100? (1) 3 (2) 5 (3) 7 (4) 8
  • 15. Solution –dividing by 7 19257 2751 0 393 0 56 1 8 0 7 1 1
  • 16. Let A=0.a1a2… and R = 0.r1r2.. Where a1,a2,r1,r2 etc are integers between I to 9 in random order, Then which of the following is an integer? • (1) 1089 x (A + R) (2) 10989 x (A ÷ R) • (3) 100989 x (A + R) (4) None of these
  • 17. Solution … • A1,a2,a3 and r1,r2,r3 etc. are integers which are in continuous order. Thus these numbers are such that we can express them as divided by 999….. • Thus we have a number like: • (a) 1089 * (1/99… + 1/99…) • In this option, we find that 1089 is dividisble by both 11 and 9 (11*9=99), therefore this is the answer.
  • 18. I a farmer is having 5 acres of land and only 50 kg of fertilizers, how much should he use per hectare to get best yield ?
  • 19. Solution • He should use 16 kg per acre in 2 acres. Remaining 18 kg should be used in in remaining 3 acres. The total yield will be : • 18+18+5+5+5 = 51 answer.
  • 20. A number when divided by 5 leaves the remainder 3 what is the remainder when the square of this number is divided by 5? • Let us do the square of the remainder also = we get 3*3 = 9. When we divide 9 by 5, we get 4 as remainder, thus 4 is the answer.
  • 21. The difference between a three- digit (with 3 distinct digits) number and a number obtained by reversing this number will always have its middle digit as? • The middle digit is always nine.
  • 22. A ground is in the shape of an isosceles right triangle, if length of the longest side of the ground is sqrt (2), what is perimeter of the ground? • We know that sin 45 is equal to : 1/ (sqrt(2)). Thus the other two sides are each. The perimeter is 1+1+1.4 = 3.4 approx. answer.
  • 23. Solution …. • As we can see that the triangle is an isoscales triangle.
  • 24. SOLVE IT • A salesman has a 35 hours per week normal schedule. During normal hours he gets Rs.40. per hour and for overtime he gets 1.5 times his normal charges. What is his income if he works for 60 hours in a week? • SOLUTION : • 35*40 + 25*60 =1400+1500 = 2900 ANS. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 25. What is the cube root of 571787? Options : • • 47 • 73, • 83 93 • Answer : • • 83. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 26. 3A+2B / 5A-3B =12/15 what is the ratio of A to B? • 3A + 2B = 12 5A – 3B = 15 • Multiply the first equation with 5 and 2nd equation with 3, we get : • 15A + 10 B = 60 and • 15A -9 B = 45 • 19 B = 15. thus B = 15/19 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 27. Solution … 3A + 2B = 12 • • B =15/19 • Putting this value in the first equation. • 3A + 30/19 = 12 3A = 12 -30/19 = 228 -30 / 19 • 3A = 198/19 • • A = 198/57 • A: B = 198/57 : 15/19 = 22: 5 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 28. if p/q 2/3, what is the value of p+q / p-q P=2 • • Q =3 • Answer : (2+3) / (2-3) • = - 5 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 29. Two dice are tossed simultaneously. What is the probability of getting the sum as a prime number? • Prime number : 2,3,5,7,11, • Total possibilities = 6* 6 = 36 • Answer = 16 out of 36 or 16/36. ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 30. Solution… Total of 14 5 6 78 9 10 11 2 12 1 1 2 3 4 5 6543 2 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 31. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 32. What is the value of * in the given equation…. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 33. Solution We know that (A –B)^2 = A^2 – 2AB+ B^2 • • A = 16/7 • B= 9/7, solutoin is 1. (16 -7 = 7,so 7/7) • Thus the above equation is just expansion of this equation. Thus the value of * is 2AB, out of which we already have B. thus the remaining number is 2A = 32/7, we already have 7, thus answer is 32. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 34. There is a circular park of 20 meters diameter. Inside the circular park is a path 1 meter wide. Find the area of the park. • Area of circle = pi* radius * radius • = pi * 10^2 – 9^2 { A^2 – B^2=(A+B) (A-b)} • = pi * 19*1 = 19 pi. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 35. A can do a piece of work in 8 days, B can do it in 9 days and C can do it in 6 days. On the first two days A & B work together and on the third day C joins them. What is the total number of days worked, needed to complete the work? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 36. Solution • For the first 2 days – A and B are working together… (2*1/8) + (2* 1/9) = 34/72 • Now A,B,C will work together: • 1/8 +1/9 + 1/6 = 29/72 • They will complete the work in 72/29 • Now multiply this by (1- 34/72) * 72/29 • (because 34/72 work is already complete, the remaining work is 38/72) • =38/72 *72/29 = 38/29. • Thus total time required is 2 +38/29 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 37. Surface area of a cube is 150 cm^2 . What is the length of its edge? Surface area of cube : • • Formula = 6 * Side * side • 6 * side * side = 150 • Side * side = 25 Side = 5 answer. • www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 38. A circular cord of 35 cm is drawn into a rhombus. what is the length of its edge? • Length of cord = 35 Cm • Edge = 35/4 = 8.75 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 39. The age of the father is 4 times the son’s age. 5 years ago it was 7 times the son’s age. What is his age now? • Let us assume father’s age = X , son’s age is X /4 . • (X-5) / (X/4 – 5) =7 or (X-5)/ (X – 20)/4 =7 Or 4X- 20 = 7X – 140 • - 3X = -120, or X = 40 Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 40. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 41. What is the difference between a discount of 40% on Rs. 1000 and two successive discounts of 35% and 5% on the same amount? • =1000*.35*.05 = discount of 350+32.5 • v/s discount of 400. the difference is : 17.5 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 42. A man sold a horse at a loss of 7%. Had he been able to sell it at a gain of 9%, it would have fetched Rs.64 more than it did. What is the cost price of the horse? • 64 *100/16 = 400 answer www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 43. Solve it .. • On an article marked Rs.20000, a customer has a choice between three successive discounts of 20%, 2O% and l0% and three successive discounts of 40%, 5% and 5%. By choosing the better offer, determine the amount he can save. • Solution : • 20000*.8*.8*.9 v/s 20000*.6*.95*.95 • =12000 v/s 10300. thus savings are 1700. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 44. A manufacturer sells a vehicle to a dealer at a profit of 40%, the dealer sells it to a customer at a profit of 30% and the customer sells it to a friend for Rs.7280 at a loss of 2O%. Find the cost price of the vehicle for the manufacturer? • 7280*100/80*100/130*100/140 = 5000. ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 45. What profit percent is made by selling an article at a certain price, if by selling it at two-thirds of that price, there would be a loss of 20%? • 80 *3/2 = 120 thus there will be profit of 20%. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 46. Two articles are sold at Rs.198 each such that a prof1t of 10% is made on the first while a loss of 10% is incurred on the other. What would be the net profit/loss on the two transactions combined? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 47. Solution Sold • • Profit on first 198 *10/110 =18 • Loss on 2nd = 198 * 10/90 =22 • There is net loss of Rs. 4 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 48. .A person purchases 50 dozen toys at Rs.4 per dozen. Of these, 40 toys were found broken. At what price should he sell the remaining toys in order to make a profit of 5%? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 49. Solution No. toys : 50 * 12 = 600 • • Defective = 40 • Net = 560 • Cost : 4 * 50 = 200 add profit = 5% = 10 • Selling price = 210 • • No. of dozens = 560/12 = 46.66 dozens • New sale price per dozen= 4.5 answwer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 50. .A fruit vendor sells apples at cost price but uses false weight of 960 gm instead of 1 kg. Find the gain %. • Profit = 1000 grams – 960 grams • = 40 • Cost = 960 • Profit = 40/960 *100 = 4.16% answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 51. • A engaged 40 labourers on a job. He was paid Rs.1,050 for the work. After retaining 20% of it, he distributed the remaining amount amongst the labourers. If the number of men to women labourers was as 5: 3 and their wages were as 3 : 2, then how much did a man get as wages? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 52. Solution No . Of men = 5/ (5+3) *40 = 25 • • 25 men were working • Total payments to men: • 5*3 = 15, women : 3*2 = 6 Thus payment received was 15/21 * • (1050*.8) • =total payment received = 600 • Payment per man – 600/25 = 24 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 53. arrange eight of the nine numbers 2,3,4,5, 7,10, 11,12,13 in the vacant squares of 3X4 array shown below so that the arithmetic average of the numbers in each row and column is the same integer. What is their average? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 54. Solution • Let us add these numbers: • Sum( 1,2,3,4,5, 7,9,10, 11,12,13,14,15, - X) • X = left out number • =106-X • Let us assume average = Y • The average is same, so total of columns should be 4Y. • 3*(4Y) = 106-X • 12Y = 106 – X, by hit and trial, we know that X should be 10. Thus Y = 8. • Thus average is 8 and left out number is 10. • Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 55. For how many integers N, N/(20—n) is the square of an integer? (a) 0 (b) 1 • • (c) 2 (d) 3 • (e) 4 • Solution : square cannot be negative, so 20-N must be positive. Therefore N can be upto 19 only. By trial, we can see that when N = 16, this is square, there is no other option, Thus answer is B. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 56. Puzzle • A truck tra veiled from town A to town B over several days. During the first day, it covered 1/p of the total distance, where p is a natural number. During the second day, it travelled 1/q of the remaining distance, where q is a natural number. Duthig the third day, it travelled i/p of the distance remaining after the second day, and during the fourth day, l/q of the distance remaining after third day. By the end of the fourth day the truck had travelled 3/4 of the distance between A and B. • The value of p+q is • (a) 4 0) 5 • (c) 6 (d) 7 • (e) 8 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 57. Solution • Try from options, it cannot be 5 or 6, it has to be higher value 7 or 8. Let us try for 7. • Let us assume that the number is 144 (we have assumed it because 4*3*4*3 = 144) • First day: 36 is used, left out is 108. 2nd day: 36 is used and left out is 72. 3rd day: 18 is used and left out is 54. 4th day 18 is used and left out is 36. • We know that now 1/4 th is left out, so our condition is fulfilled. Thus this is the answer. • www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 58. In a certain factoiy, each day the expected number of accidents is related to the number of overtime hour by a linear equation. Suppose that on one day there were 1000 overtime hours logged and 8 accidents reported, and on another day there were 400 overtime hours logged and 5 accidents. What are the expected numbers of accidents when no overtime hours are logged? • (a) 2 (b) 3 • (c) 4 (d) 5 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 59. Solution • Let us frame 2 equations and use them to solve this question: • 8 = 1000X +Y • 5 = 400 X +Y • Solving these we get : 3 = 600X • X = 1/200; putting this value, we get Y. • Y = 3. • Thus when there is no overtime, the number of accident is 3. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 60. In which year did the firm pay maximum tax? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 61. Solution • Since all the figures are in %, we cannot calculate the value of taxes paid as absolute value. We are not aware of change in sales also. So answer : cannot be determined. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 62. Solve it : • Seven integers A, B, C,D, E, Fand G arc to be arranged in an increasiug order such that • i. First four numbers are in arithmetic progression. • ii. Last four numbers are in geometric progression. • iii. There exists one number between E and G. • iv. There exist no numbers between A and B. • v. D is the smallest number and E is the greatest. • Vi. A / D = G /C = F / A >1 • vii. E= 960 • What is E / A? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 63. SOLUTION • F is more than A and A is more than D and G is more than C. • D is smallest :D - - - - - - E (G will come one less than E, A and B are close. C has to be near D. • DC BAGFE • The last four are in GP. • Thus E = A *r^3 (because it is GP) and A = D +3(common difference) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 64. Continued… • E = 960 • Let us find factors of 960 • 2*2*2*2*2*2*3*5 • Thus A must be 15 and ratio must be 4 • The numbers will be : 15,60,240,960. • Or A may be 120 and ratio may be 2, the numbers will be 120,240,480 and 960 • Thus F/A = 240/15 = 16 or 480/120 = 2. • The 2nd option is better. Thus A/D = 2 and D = 60 • We can write that A = D + (3*common difference) • =120=60 +(3*common difference). www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 65. Continued… 120=60 +(3*common difference). • • Common difference is 20 • Thus the numbers are : • 60,80,100,120,240,480,960 Thus we can find answer to the question: • E/A • =960/120 = 8 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 66. Goti and Nitin could do a piece of work in 12 days. Nitin and Kap together do lt In 15 days. If Goti is twice as good a workman as Kap, find in how many days Goti alone will do it? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 67. Solution G = 2K (now add the two equations) • • 2K+N+N+K = 1/12+1/15 = 27/180, • K+N = 1/15 or 2 (K+N) = 2/15 • 3K +2N = 3/20 K = 3/20 – 2/15 = 1/60 • Thus Kap can do it in 60 days. • • Goti being twice fast, can do it in 30 days alone. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 68. Goti car paint a fence 100 metres long in 6 days, then how much time will both Goti and his friend Kap take, if Kap is thrice as efficient as Goti? • Goti’s one day work = 1/6, Kap=3*1/6 • 1/6 + 3/6 = 4/6 • Thus they will take 6/4 = 1.5 days to complete theFOR PGPSE PARTICIPANTS work. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL
  • 69. Two pipes A and B can fill a cistern in 10 and 15 minutes respectively. Both pipes are opened together but at the end of 3 minutes, ‘B’ is turned off. How much time will the cistern take to fill? • 3/10 +3/15 = 75/150 thus the remaining pipe A will take 5 minutes to fill up the tank. Total time: 2+5 = 7 minutes. Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 70. Explanation • 75/150 = is half of the total pip3 thus the pipe is helf illed. Thus A can fill the remaining portion in 5 minutes (it takes 10 minutes to fill completely). www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 71. A is twice as good a workman as B; and together they finish a work in 14 days. In how many days can it be done by each separately? • Let us assume that A takes X and B takes 2X days. 1/2x + 1/x = 1/14 • Let us assume 1/x = Y • Y/2 + Y = 1/14 • 3/2Y = 1/14 or Y = 2/42 or 1/21 • Thus A can do it in 21 days and B in 42 days. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 72. If 20 men complete one-third of a piece of work in 20 days, how many more men should be employed to finish the rest of the work in 25 days? Total work left = 2*20 = 40 days. • • Total mandays required = 40*20 = 800 • Thus no. of persons required = 800/25=32 • Additional persons required = 32-20=12 persons. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 73. Goti can copy 75 pages in 25 hours Goti and Kap together can copy 135 pages in 27 hours In what time can Kap copy 42 pages? • Goti copies 3 pages in one hour. Thus he copies 27*3 = 81 pages. Kap copies (135-81) = 54 pages in 27 hours, or 2 pages in one hour. Thus 42/2 = 21 hours will be taken by Kap Sa. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 74. goti & Kap can do a piece of work in 4.8 days, Kap and Jitu together can do it in 8 days and the three together in 4 days. How long would Goti & Jitu together take to do it’ www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 75. Solution • (calculate for 1 day and add them to get the ans.) • G+K +K +J= 1 / (4.8) + 1/8 • GKKJ = 12.8 / 38.4 • GKJ = ¼ • K = 12.8 / 38.4 - ¼ • = (12.8 – 9.6) / 38.4 • = 3.2 / 38.4 = 1/12 • Thus G+J = ¼ - 1/12 = 2/12 = 1/6 • G + J will do it in 6 days. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 76. A person works twice as fast as a woman. A woman works twice as fast as a child. If 16 persons can complete a job in 12 days, then how many days would be required for 32 women and 64 children together to complete the same job? • 32 women = 16 men • 64 children = 16 men. • Thus they will together do it in 6 days. Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 77. 3 pipes A, B and C can fill a cistern in 15, 20 and 30 min. respectively. They were all turned on at the same time. After 5 minutes the first two pipes were turned off. In what time will the cistern be filled? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 78. Solution • 5/15 + 5/20 5/30 • = (20+15+10) / 60 = 45/60 or ¾ • Thus remaining ¼ of the cistern can be filled by C in 7.5 minutes only. • Thus total time taken is 5 + 7.5 =12.5 minutes www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 79. A certain number of men can finish a piece of work in 100 days. If, however, there are 10 men less, it would take 10 days more for the work to finish. How many men were there? • Let the number of men = X • Total work = 100X • (X-10) 110 = 100X or 110X -1100 = 100X • 10X = 1100 or X = 110. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 80. A, B and C can do a piece of work in 20, 20 and 40 days respectively. They began the work together but C left 2 days before the completion of work. In how many days would the work have been completed? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 81. Solution For 2 days only A and B worked • • 2/20 + 2/20 = 4/20 or 1/5 • Together (all three) : • 1/20+1/20+1/40 = (2+2+1) / 40 = 1/8 Thus they take 8 days to complete the • work, but they completed only 4/5 work together, so 8*4/5 = 6.4 days were taken by them. Thus total days : 8.4 days. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 82. ERROR SPOTTING Industrial accidents/(1)usually result into /(2) ignorance/(3)or carelessness/(4) No Error (5) • The correct sentence should be : • Industrial accidents are caused by ignorance or carelessness. • So answer is (2) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 83. Some people are like (1)to do a lot of social work/(2)even though they are poor(3)and lack resources • Correct sentence should be : • Some people want / are likely to do a lot of social work, even though they are poor and lack resources. • So answer is (1) . www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 84. ERROR SPOTTING Some men (1)have conveniently believe (2)that women are inferior to(3) men in respect of abilities.(4) No Error (5) • (2) = it should be : have conveniently believed. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 85. ERROR SPOTTING His qualities include(1)the ability to take/(2)right and/(3)quickly decisions.(4)/ No Error(5) • ANSWER : (4) • It should be quick decisions. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 86. ERROR SPOTTING If you want to (1)ensure prompt service (2)please be contacted to us (3) at your earlier convenience. (4) No Error (5) • Answer : (3) please contact us OR please be in contact with us www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 87. They founded (1)this institution for/ (2)the welfare of the poor (3) and the disable people.(4) No Error (5) • Answer (4) it should be : • For the disable (there is no need to put people with disable). www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 88. He asked me/U) what had my total investrnents(2)during the (3) last five years.(4) No Error. (5) • Answer : (2) it should be : • What had my total investments been www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 89. He takes the(1) prescribed medicine regularly(2) and that is how(3) he has succeed to control his ailment.(4) No Error (5) • Answer : (3) • It should be : this is how www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 90. We should take(1) regular exercises to keep ourself (2) fit and active.(3) No Error (4) • (2) it should be : regular exercises to keep • (there is no need of ourself). www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 91. Each time (1) you reached this spot (2) go back and(3) start your next (4) round again.(4) No Error (5) • (2) it should be – you reach this spot. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 92. SENTENCE IMPROVEMENT • The honourable court had taken a leniency view because the accused had no previous criminal record. • (1) had viewed leniency (2) had taken a leniency viewing • (3) had taken a lenient view(4) Noae of these • (5) No correction required • Solution: • (3) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 93. Sentence improvement • Maintaining global peace is our self-made commitment to the word. • (1) self-making commitment • (2) self-made committee • (3) made of self-connnitment • (4) None of these • (5) No correction required • Solution (5) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 94. The dinner party hosted by the President at the club was shifted to an undisclosed location. (1) a locality undisciosing • • (2) a undisc location • (3) an undisc location • (4) None of these (5) No correction required • Solution • • (5) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 95. Sentence improvement • The government should launch such projects which should reversible the destructive cycle of flood and drought. • (1) should have reversible (2) should be reverse (3) should have been reverse • (4) None of these • (5) No correction required • Solution : • (4) correct answer: should reverse www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 96. A comnilttee comprising eminent experts from various fields were setting up. (1) was setup (2) was setting up (3) were being set up (4) None of these (5) No correction required • Solution : (1) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 97. Our foreign exchange reserves have been increased substantial. (1) have been increased substantially (2) have increased substantially (3) have substantially increasing (4) None of these (5) No correction required • Solution : (2) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 98. The key to a competitive economy is its investment regime. • (1) competition economy is • (2) competing economist lays • (3) economy competition was • (4) None of these (5) No correction required • Solution • • (5) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 99. Driving a car in jammed traffic require extraordinary patience - especially when other drivers are not disciplined. (1) required extraordinary patient (2) requires extraordinary patience (3) requiring extraordinary patience (4) None of these (5) No correction required • Solution (2) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 100. Chinese army possesses highly sophisticated simulotors on which their soldiers are training. • (1) which their soldiers training on • (2) on which their soldiers have trains • (3) which their soldiers do train • (4) None of these • (5) No correction required • Solution : last part : soldiers are getting training. (so answer is (4)) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 101. Every novel activity will be likely to face resistance from vested interests. • (1) is likely to face • (2) would be like facing • (3) No correction required • (4) will be likely facing (5) None of these • Solution : (1) • www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 102. We observed that traders were not primarily dedicated with art of selling. (1) dedicated to the art of(2) None • • (3) dedicated in the art by • (4) dedicated by the art of • (5) No correction required Solution (1) preposition error . • www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 103. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 104. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 105. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 106. If expenses per participant during the meeting is Rs.200 in 1995, which keeps on increasing at the rate of 10% per year, then what are the total expenses (in Rs.thousand) in 1996. The graph below shows the number of participants coming from different regions? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 107. Solution • 200*1.1*360 = 79200 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 108. The following graph shows profits of 5 companies. What was the average profit in 1979? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 109. Solution : A =130 • • B = 40 • C = 110 • D = 60 E = 90 • Let us add them and divide by 5: • • =430/5 = 86 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 110. Solve it • A cube with edges equal to 8cm is painted on all the six faces and is subsequently cut into 64 identical cubes. The number ct smaller cubes painted on atleast two faces is • (1) 24 (2) 16 • (3) 36 • (4) 32 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 111. Solution • There are four on the top right side. There are 4 on the opposite side also (4*4*4 = 64). • Thus we have 4+4+2+2 cubes in front, same 12 in the back side also. We have 8 in sides also. Thus we have 32 cubes. • Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 112. Solve it • The perimeter of a regular hexagon is 36cm. The area of the hexagon is • (1) 54*sqrt(3) sq cm (2) 108*3 sq cm • (3) 27*3 sq cm (4) 18*3 sq cm • Solution: • One side of hexagon = 6 • One triagle = ((sqrt(3)/4 * side )^2 =1.7/4* 36 • Hexagon = 6* equilateral triangle = 6*sqrt(3)/4*36 • =54* sqrt(3) ans www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 113. Solve it … • How many patient does the doctor examine in a day, if he treats 5 patients in 3 hours with breaks of 10 minutes between two consecutive patients and works for 10 hours per day? • (1) 16 (2) 15 • (3) 12 (4) 20 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 114. Solution 3 hours = 180 minutes • • Break = 4*10 = 40 • Time per patient = 140 / 5 = 28 minutes • Total time : 10 hours *60 = 600 minutes 600 – 28 = 572 • Now dividing 572 / (28+10) = 15 • • Thus the doctor checks 15+1 = 16 patients. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 115. If the interior angle of a regular polygon is twice its exterior angle then the polygon is a (1) rhombus (2) pentagon (3) hexagon (4) heptagon Interior angle = 2X and exterior angle = X 3X = 180 or X = 60 Thus one exterior angle is 60 Thus 360/60 = 6 Thus the shape is hexagon. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 116. DATA SUFFICIENCY QUESTION. 40 pens were distributed equally amon all the participants, then how many participants were there? (A) The number of participants was a prime number greater than 10. (B) The leftover pen was kept by the Chairman. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 117. Solution • If we combine both the statements, we can get the answer. One pen was left (given to the chairman), so 39 pen were distributed. • 39 = 3*13 • Thus the number of participants must be either 3 or 13. since it had to be above 10, therefore the answer is 13. (so answer can be drawn with the help of both the students together). Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 118. WHAT IS THE VALUE OF X www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 119. WHAT IS THE VALUE OF X www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 120. Data sufficiency question. Is the series a GP? • • (A)If the third term is twice the second. • (B)The fourth term is eight times the first. • Solution Let us start from 1 • 1,2,4,8 = yes it is GP • • Thus the answer can be drawn with the help of both the statements. Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 121. The number of common terms in the two-seç 17, 21, 25,.. ., 417 and 16, 21, 26,. . ., 466 • Let us start from 21. In the first term the gap is of 4 and in second series the gap is of 5. their LCM is 20 so we have to find the gaps of 20 each. • Last term is 417. let us deduct 21 from 417, we get 396. now let us divide it by 20. We get : 19. Thus we have 19+1 = 20 common terms. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 122. Solution continued. .. . • The final series is : • 21,41,61,81,101,121,141,161,181,201,22 1,241,261,281,301,321,341,361,381,401, www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 123. What is the total production of machine no. 3? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 124. Solution • Production accepted : 100 – 27 = 73%. • Thus total production • 100/73 * 438 = 600 units answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 125. • The integers 1, 2,..., 40 are written on a blackboard. The following operation is then repeated 39 times: In each repetition, any two numbers, say a and b, currently on the blackboard are erased and a new number a + b —1 is written. What will be the number left on the board at the end? • Options: (1) 820 (2) 821 (3) 781 (4) 819 (5) 780 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 126. Solution …. • In the first round, we add up 1 and 2 and get 2. now we take up 2 and 3, we get 4, now we take up 4 and 4 and get 7. now we take up 7 and 5 and get 11. Now we take up 11 and 6 and get 16. We can find that we have an increasing series : • 2,4,7,11,16 …. … • Let us add 1 to 39. =39*40/2 = 780 • Let us add 780 + 1= 781 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 127. What is the total sale (in no. of units) in the year 1991? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 128. • = 82016 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 129. What is the % increase in the sale of VCR in 1993 against 1992? Sale in 1993 =6151 • • Sale in 1992 = 3006 • Difference = 3145 • Increase in % = 3145/3006 *100 = 105% answer. • www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 130. This graph shows price of 4 shares, what is the average price of these 4 shares? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 131. Solution • Let us add them: • (150+40+120+90)/4 = 100 answer www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 132. what is the production of food grains in 1991, expressed as a percentage of its production in 1989? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 133. Solution • 15/20 *100 = 75 % answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 134. Which is the most logical idea? • If an ant were as big as a horse, could it move mountains? • No. A giant ant . . . . . (select from a,b,c,d) • (a) Would be a structural failure. • (b) Would never be able to move mountains. • (c) Would be a mere curiosity. • (d) Would never be able to hunt for food. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 135. Solution • A giant Ant would not be able to move mountains because it is just a curoisity (we are not sure about what could it do). Other options are not logical – as logically we cannot say that it is structural failure or it cannot hunt for food or it cannot move mountains. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 136. Puzzle test… • Nine cricket fans are watching a match in a stadium. Seated in one row, they are J, K, L, M, N, 0, P, Q and R. L is at the right of M and at third place at the right of N. K is at one end of the row. Q is immediately next to 0 and P. 0 is at the third place at the left of K. J is right next to left of 0. • Who is sitting in the centre of the row? • (a)L (b)O • (c)J (d)Q www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 137. Solution … • NRMLJOPQK • J IS IN THE CENTRE www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 138. A and B start walking in opposite directions. A covers 3 km and B covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from the starting point? • A is 3 KM in one direction and 4 KM in right. Applying pythogorus, we find that A is 5 KM from the starting point. Similarly B is also 5 KM from the starting point. Ans. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 139. Ram walks 10 m south from his house, turns left and walks 25 m, again turns left and walks 40 m, then turns right and. walks 5 m to reach to school. In which direction the school is from his house? • Draw a map and get the answer = north- east. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 140. In a class of 35 students Kiran is placed 7th from the bottom whereas Sohan is placed 9th from the top. Mohan is placed exactly in between the two. What is Kiran’s position from Mohan? • 10th • From 9th to the top and 7th to the bottom, we have 21 candidates (35-(6+8) ). Mohan is just in the centre. So from Mohan, Kiran is at 10th place. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 141. A watch reads 4 If the minute hand points towards the East, in which direction does the hour hand point? • The hour hand is towards South West. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 142. Puzzle • Goti and I started walking towards each other from two places lOO m apart. After walking 30m, Goti turns left and goes lO m, then he turns right and goes 20m then turns right again and comes back to the road and starts walking. If we walk with the same speed, what is the distance between us at this point of time www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 143. Solution • (Goti walks 70 meters in all), so I walk 70 meters towards Goti’s starting point and now I am 30 meters from that. Goti takes only 30+20 meters on the road. Thus Goti is 50 meters from my starting point. Thus there is a gap of 20 meters between me and Goti. Answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 144. Sum of 1st to 30th terms of a series in arithmetic progèssion is 150. if the first term is A, what is 30th term of the series? • Sum = 30/2 (2a + (29)D) = 150 • 2a + 29d =150*2/30 = or 29 D = 10 – 2A • 30th term = A + 29D • 29 D = 10 – 2A, putting the value, we get the answer = 10 – A answer www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 145. Question on number system • Convert 252 into binary system • 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 = 7/2 = 3/2 =1 (starting from last remainder to the first) • 11111100 answer. • Convert it again to decimal system: • 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+ 0*2^1+0*2^0 = 128+64+32+16+8+4 = 252 www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 146. Multiply 12 to 13 ( note - both are octal numbers, your outcomes must also be in octal numbers)? • Let us first convert them into decimal numbers: 12= 1*8^1 + 2*8^0 =10 • 13 = 1*8^1 + 3*8^0 =11 • Now multiply 10 to 11 = 110 • Now convert it into octal number: • 110/8 = 13 / 8 • =156 • Test = now convert 156 to decimal number www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 147. Convert 156 (octal) to decimal number ….. • 1*8^2 + 5*8^1 + 6*8^0 • =64+40+6 • =110 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 148. Multiply 5 (base 16) to 12 (base 7) and get the outcome in binary? • (5*16^0 ) * (1*7^1 +2*7^0) • 5 *9 = 45 • 45/2 = 22/2 = 11/2 = 5/2 =2/2 1 • =101101 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 149. 78.8% of a common medicine for stomach-upsets is absolute alcohol; 3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177% chloroform. How much of each of these compounds is there in a pack of 30 ml? solution alchol = 23.6 ml, 1 ml of menthol oil and so. On. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 150. What is the sum of cubes of the first 5 natural numbers? Formula • • = [N (N+1)/2 ]^2 • = [5*6 / 2 ]^2 • =225 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 151. What is the sum of squares of the first 13 natural numbers? Formula • • =[n(n+1)(2n+1) ] /6 • =(13*14*27)/6 • =819 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 152. In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls in the class. Let the number of girls be X • • X + 3/5X = 80 • 8/5 X = 80 • X = 80 *5/8 • X = 50 (the number of girls is 50, boys are 30) answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 153. The difference between two numbers is 30. On dividing the greater by the smller the quotient is 3. Find the numbers. Let the smaller number be X. • • 3X – X = 30 • 2X =30; X = 15, • Thus 2 numbers are 15 and 45 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 154. Gunpowder contains 75% nitre and 10% sulphur. The rest of it is charcoal. What is the amount of charcoal in 9 kg of gunpowder. • Charcoal is (100 – 75 – 10) = 15% • 9 KG = 9000 Grams • 9000*15/100 • =1350 grams answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 155. Question on profit • At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%? • (a) 48% (b) 43% • (c) 40% (d) 38% • (e) None of the above www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 156. Solution … • Let the cost be 100 • Final price being realised 133 • It is after discount, so price before discount (marked price) is : • 133*100/95 =140 , so 40 is the answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 157. A vertical pole PO is standing at the centre 0 of a square ABCD. If AC subtends an angle 90° at point P of the pole then the angle subtended by a side of the square at Pis (a) 35° (b) 45° (c) 30° (d) 60° (e) None of the above www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 158. Solution • When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule). • So answer is 60 degrees. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 159. Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent per cent pure gold. • 22/24 *100 • =91.67 % answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 160. In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is the perimeter of the region marked B? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 161. Solution • Permieter of one circle is 2/3 now because, it is being cut by other circle. • Thus 2/3 + 2/3 of perimeters added : • 2 * 2/3 * (formula of perimeter = 2pi *r) • =(8 * pi * r) /3 answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 162. What is angle C? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 163. Solution • Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 164. What is angle a? www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 165. Solution • Angles from D and C are equal . • 180 – 60 – 37 – x • =83 – x • Let us sum up for two angles: • (180+180 ) = 360 • 83-x + 83 – x + 180+2X = 360 • 2Y +2X = 180 let us assume Y = 53 • 2X = 72 or X = 36 answer (solve by options, so angle A = 53 ) answer. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 166. ABOUT AFTERSCHO☺OL Afterschoool conducts three year integrated PGPSE (after class 12th along with IAS / CA / CS) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM. This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 167. Why such a programme? • To promote people to take up entrepreneurship and help develop the society • To enable people to take up franchising and other such options to start a business / social development project • To enable people to take up social development as their mission • To enable people to promote spirituality and positive thinking in the world www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 168. Who are our supporters? • Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us. • You can also support us – not necessarily by money – but by being promotor of our concept and our ideas. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 169. About AFTERSCHO☺OL PGPSE – the best programme for developing great entrepreneurs • Most flexible, adaptive but rigorous programme • Available in distance learning mode • Case study focused- latest cases • Industry oriented practical curriculum • Designed to make you entrepreneurs – not just an employee • Option to take up part time job – so earn while you learn • The only absolutely free course on internet www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 170. Workshops from AFTERSCHO☺OL • IIF, Delhi • CIPS, Jaipur • ICSI Hyderabad Branch • Gyan Vihar, Jaipur • Apex Institute of Management, Jaipur • Aravali Institute of Management, Jodhpur • Xavier Institute of Management, Bhubaneshwar • Pacific Institute, Udaipur • Engineering College, Hyderabad www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 171. Flexible Specialisations: • Spiritualising business and society • Rural development and transformation • HRD and Education, Social Development • NGO and voluntary work • Investment analysis,microfinance and inclusion • Retail sector, BPO, KPO • Accounting & Information system (with CA / CS /CMA) • Hospital management and Health care • Hospitality sector and culture and heritage • Other sectors of high growth, high technology and social relevance www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 172. Salient features: • The only programme of its kind (in the whole world) • No publicity and low profile course • For those who want to achieve success in life – not just a degree • Flexible – you may stay for a month and continue the rest of the education by distance mode. / you may attend weekend classes • Scholarships for those from poor economic background • Latest and constantly changing curriculum – keeping pace with the time • Placement for those who are interested • Admissions open throughout the year • Latest and most advanced technologies, books and study material www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 173. Components • Pedagogy curriculum and approach based on IIM Ahmedabad and ISB Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad) • Meditation, spiritualisation, and self development • EsGotitial softwares for business • Business plan, Research projects • Participation in conferences / seminars • Workshops on leadership, team building etc. • Written submissions of research projects/articles / papers • Interview of entrepreneurs, writing biographies of entrepreneurs • Editing of journals / newsletters • Consultancy / research projects • Assignments, communication skill workshops • Participation in conferences and seminars • Group discussions, mock interviews, self development diaryng • Mind Power Training & writing workshop (by Dr. T.K.Jain) www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 174. Pedagogy • Case analysis, • Articles from Harvard Business Review • Quiz, seminars, workshops, games, • Visits to entrepreneurs and industrial visits • PreGotitations, Latest audio-visuals • Group discussions and group projects • Periodic self assessment • Mentoring and counselling • Study exchange programme (with institutions out of India) • Rural development / Social welfare projects www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 175. Branches • AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 176. Case Studies • We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs. www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 177. Basic values at AFTERSCHO☺OL • Share to learn more • Interact to develop yourself • Fear is your worst enemy • Make mistakes to learn • Study & discuss in a group • Criticism is the healthy route to mutual support and help • Ask fundamental questions : why, when, how & where? • Embrace change – and compete with yourself only www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS
  • 178. www.afterschoool.tk social entrepreneurship for better society www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS