STATISTICAL ANALYSIS AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME – World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship OPEN FOR ALL FREE FOR ALL

STATISTICAL ANALYSIS Dr. T.K. Jain. AFTERSCHO☺OL Centre for social entrepreneurship Bikaner M: 9414430763 [email_address] www.afterschool.tk www.afterschoool.tk

CALCULATE MEAN DEVIATION FROM THE FOLLOWIND DATA? 49 39 35 28 24 23 X

SOLUTION . . Step 1. prepare average of the numbers Step 2: find Dx or deviation of each number from the mean. (ignore plus or minus signs) Step 3: find our average of Dx. Mean deviation is available to us Answer = 8.

Step 1. prepare average of the numbers

Step 2: find Dx or deviation of each number from the mean. (ignore plus or minus signs)

Step 3: find our average of Dx.

Mean deviation is available to us

Answer = 8.

Solution 8 33 16 49 6 39 2 35 5 28 9 24 10 23 Dx x

Find mean deviation from the following series? 1.741 3.89 212.4 474 122 5.115 5.1148 9 1 9 65.41 3.1148 147 21 7 35.67 1.1148 160 32 5 39.84 0.8852 135 45 3 66.36 2.8852 23 23 1 fdx Dx FX frequency (f) X

SOLUTION . . MEAN DEVIATION = 1.74 Steps: 1. multiply X with F and get FX X = values, F = frequency Divide sum of FX by sum of F (total frequency). You will get average = 3.89 Find DX by taking difference of X and Average. Now multiply DX by F. we get FDX. Get average of FDX by dividing it by sum of frequency. We get answer 1.74 answer.

MEAN DEVIATION = 1.74

Steps:

1. multiply X with F and get FX

X = values, F = frequency

Divide sum of FX by sum of F (total frequency). You will get average = 3.89

Find DX by taking difference of X and Average. Now multiply DX by F. we get FDX.

Get average of FDX by dividing it by sum of frequency. We get answer 1.74 answer.

Find Mean Deviation from the following data? 9 5 15 4 23 3 12 2 2 1 Frequency X

Solution . . 0.86 3.3 52.6 200 61 15.5 2 45 9 5 10.8 1 60 15 4 6.41 0 69 23 3 15.3 1 24 12 2 4.56 2 2 2 1 F X

Answer . . Mean deviation is .86 (see excel sheet for details).

Mean deviation is .86

(see excel sheet for details).

Find mean deviation from Median from the following data. . : 80, 75, 70, 52, 56, 68, 82? STEP 1: ARRANGE THE DATA IN ASCENDING ORDER. STEP 2: FIND THE MID VALUE = HERE IT IS 70. THIS IS MEDIAN. STEP 3: FIND Dx (DIFFERENCE) FROM MEDIAN. FIND AVERAGE OF Dx.

STEP 1: ARRANGE THE DATA IN ASCENDING ORDER.

STEP 2: FIND THE MID VALUE = HERE IT IS 70. THIS IS MEDIAN.

STEP 3: FIND Dx (DIFFERENCE) FROM MEDIAN.

FIND AVERAGE OF Dx.

Solution . . 8.7 61 12 82 10 80 5 75 0 70 2 68 14 56 18 52 Dx x

Solution .. Check the excel notes for this and final answer is 8.7 answer.

Check the excel notes for this and final answer is 8.7 answer.

Find MEDIAN from the following data? (see excel table). Use the following formulae to find MEDIAN: 1. SUM UP ALL THE FREQUENCY. IT IS 50. DIVIDE 50 BY 2 = 25. FIND OUT WHERE IS 25. 25 LIES IN THE GROUP 60 TO 70. NOW APPLY FORMULAE . .

Use the following formulae to find MEDIAN:

1. SUM UP ALL THE FREQUENCY. IT IS 50.

DIVIDE 50 BY 2 = 25.

FIND OUT WHERE IS 25. 25 LIES IN THE GROUP 60 TO 70.

NOW APPLY FORMULAE . .

SOLUTION . . . L + (N/2) – p1/ (t-p1) *c =L = THE LOWER LIMIT OF CLASS. N = TOTAL FREQUENCY P1 = TOTAL OF PREVIOUS FREQUENCY SET T = TOTAL OF MEDIAN CLASS C = GAP IN THE MEDIAN CLASS.

L + (N/2) – p1/ (t-p1) *c

=L = THE LOWER LIMIT OF CLASS.

N = TOTAL FREQUENCY

P1 = TOTAL OF PREVIOUS FREQUENCY SET

T = TOTAL OF MEDIAN CLASS

C = GAP IN THE MEDIAN CLASS.

SOLUTION . . . L = 60 N = 50 (TOTAL FREQUENCY) P1 = 20 (TOTAL UPTO LESS THAN 60) T = 40 (TOTAL UPTO LESS THAN 70) C = (70 – 60) = 10 (gap of median class) =60 + (25-20) / (40-20) *10 60 + 2.5 =62.5 ANSWER.

L = 60

N = 50 (TOTAL FREQUENCY)

P1 = 20 (TOTAL UPTO LESS THAN 60)

T = 40 (TOTAL UPTO LESS THAN 70)

C = (70 – 60) = 10 (gap of median class)

=60 + (25-20) / (40-20) *10

60 + 2.5

=62.5 ANSWER.

Solution table : 50 75 10 70 -80 50 less than 80 65 20 60-70 40 less than 70 55 12 50 - 60 20 less than 60 45 8 40-50 8 Less than 50 mid f range Fry X

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AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.

Case Studies We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.

We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.

Basic values at afterschoool Share to learn more Interact to develop yourself Fear is your worst enemy Make mistakes to learn Study & discuss in a group Criticism is the healthy route to mutual support and help Ask fundamental questions : why, when, how & where? Embrace change – and compete with yourself only

Share to learn more

Interact to develop yourself

Fear is your worst enemy

Make mistakes to learn

Study & discuss in a group

Criticism is the healthy route to mutual support and help

Ask fundamental questions : why, when, how & where?

Embrace change – and compete with yourself only

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