Chemical Equilibrium<br />Presentation Part 2<br />c!e-γ˚T 2010<br />
KP and KC equation<br />Derive Kp= Kc(RT)n<br />n = (moles of gaseous product) <br /> − (moles of gaseous reactant)<br />If n= 0 then KC= KP<br />n> 0 then KC< KP<br />n< 0 then KC> KP<br />H2(g) + Br2(g) HBr(g)<br />N2O5(g) NO2 + O2(g)<br />CaCO3 (s) CaO (s) + CO2(g)<br />AgCl (s) Ag+ (aq) + Cl- (aq)<br />(NH4)2Se (s) NH3 (g) + H2Se (g)<br />
Solving for KC and KP<br />Carbonyl chloride (COCl2), also known as phosgene was used in World War I as a poisonous gas. The equilibrium concentrations for the reaction between carbon monoxide and chlorine gas to form phosgene at 74oC are [CO] = 1.2x10-2 M, [Cl2] = 0.054 M, and [COCl2] = 0.14 M. Calculate KC and KP. (220, 7.6)<br />Consider the following equilibrium process at 700oC: 2H2 (g) + S2 (g) 2H2S (g). Analysis shows that there are 2.50 moles of H2, 1.35x10-5moles S2, and 8.70 moles of H2S present in a 12.0-L flask. Calculate KC for the reaction. (1.08 x107 )<br />The equilibrium constant KP for the reaction 2NO2 (g) 2NO (g) +O2 (g) is 158 at 1000 K. Calculate PO2 if PNO2 = 0.400 atm and PNO = 0.270 atm. (347 atm)<br />
Manipulating equilibrium constants<br />Reversing a chemical equation<br />2NO2 (g) N2O4 (g) KC = 4.63 X 10-3<br />N2O4 (g) 2NO2 (g) K’C = ?<br />
Manipulating equilibrium constants<br />Multiplying or dividing coefficients by a constant<br />2NO2 (g) N2O4 (g) KC = 4.63 X 10-3<br />6NO2 (g) 3 N2O4 (g) K”C = ?<br />NO2 (g) ½ N2O4 (g) K’”C = ?<br />
Manipulating equilibrium constants<br />Adding chemical reactions<br />
Predicting direction of a reaction to achieve equilibrium<br />K > Q, K -- > Q<br />K < Q, K < -- Q<br />K = Q, K < = > Q<br />
Example<br />The equilibrium constant for the formation of nitrosyl chloride from nitric oxide and molecular chlorine:<br /> 2NO (g) + Cl2 (g) 2 NOCl (g)<br /> is 6.5 x 104 at 35 oC. In a certain experiment, 0.02 mole of NO, 0.0083 mole of Cl2 and 6.8 mole NOCl are mixed in 2.0 L flask, in which direction will the system proceed to reach equilibrium?<br />
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