MOLARITY

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TEMA PARA LA CLASE DE QUÍMICA...t/t

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MOLARITY

  1. 1. MolarityQBA Miguel A. Castro Ramírez LecturePLUS Timberlake1
  2. 2. Molarity (M)A concentration that expresses themoles of solute in 1 L of solution Molarity (M) = moles of solute 1 liter solution LecturePLUS Timberlake2
  3. 3. Units of Molarity2.0 M HCl = 2.0 moles HCl 1 L HCl solution6.0 M HCl = 6.0 moles HCl 1 L HCl solution LecturePLUS Timberlake3
  4. 4. Molarity CalculationNaOH is used to open stopped sinks, to treatcellulose in the making of nylon, and toremove potato peels commercially.If 4.0 g NaOH are used to make 500. mL ofNaOH solution, what is the molarity (M) of thesolution? LecturePLUS Timberlake4
  5. 5. Calculating Molarity1) 4.0 g NaOH x 1 mole NaOH = 0.10 mole NaOH 40.0 g NaOH2) 500. mL x 1L_ = 0.500 L 1000 mL3. 0.10 mole NaOH = 0.20 mole NaOH 0.500 L 1L = 0.20 M NaOH LecturePLUS Timberlake5
  6. 6. Learning Check M1A KOH solution with a volume of 400 mLcontains 2 mole KOH. What is the molarityof the solution?1) 8 M2) 5 M o an3) 2 M Dr LecturePLUS Timberlake6
  7. 7. Solution M1A KOH solution with a volume of 400 mLcontains 2 moles of KOH. What is themolarity of the solution?2) 5 MM = 2 mole KOH = 5 M o an 0.4 L Dr LecturePLUS Timberlake7
  8. 8. Learning Check M2A glucose solution with a volume of 2.0 Lcontains 72 g glucose (C6H12O6). If glucosehas a molar mass of 180. g/mole, what isthe molarity of the glucose solution?1) 0.20 M2) 5.0 M3) 36 M LecturePLUS Timberlake8
  9. 9. Solution M2A glucose solution with a volume of 2.0 Lcontains 72 g glucose (C6H12O6). If glucosehas a molar mass of 180. g/mole, what isthe molarity of the glucose solution?1) 72 g x 1 mole x 1 = 0.20 M 180. g 2.0 L LecturePLUS Timberlake9
  10. 10. Molarity Conversion FactorsA solution is a 3.0 M NaOH.. Write themolarity in the form of conversion factors. 3.0 moles NaOH and 1 L NaOH soln 1 L NaOH soln 3.0 moles NaOH LecturePLUS Timberlake10
  11. 11. Learning Check M3Stomach acid is a 0.10 M HCl solution. Howmany moles of HCl are in 1500 mL of stomachacid solution?1) 15 moles HCl2) 1.5 moles HCl3) 0.15 moles HCl LecturePLUS Timberlake11
  12. 12. Solution M33) 1500 mL x 1 L = 1.5 L 1000 mL 1.5 L x 0.10 mole HCl = 0.15 mole HCl 1L (Molarity factor) LecturePLUS Timberlake12
  13. 13. Learning Check M4How many grams of KCl are present in 2.5 Lof 0.50 M KCl?1) 1.3 g2) 5.0 g3) 93 g LecturePLUS Timberlake13
  14. 14. Solution M43)2.5 L x 0.50 mole x 74.6 g KCl = 93 g KCl 1L 1 mole KCl LecturePLUS Timberlake14
  15. 15. Learning Check M5How many milliliters of stomach acid, which is0.10 M HCl, contain 0.15 mole HCl?1) 150 mL2) 1500 mL3) 5000 mL LecturePLUS Timberlake15
  16. 16. Solution M52) 0.15 mole HCl x 1 L soln x 1000 mL 0.10 mole HCl 1L (Molarity inverted) = 1500 mL HCl LecturePLUS Timberlake16
  17. 17. Learning Check M6How many grams of NaOH are required toprepare 400. mL of 3.0 M NaOH solution?1) 12 g2) 48 g3) 300 g LecturePLUS Timberlake17
  18. 18. Solution M62) 400. mL x 1 L = 0.400 L 1000 mL0.400 L x 3.0 mole NaOH x 40.0 g NaOH 1L 1 mole NaOH (molar mass) = 48 g NaOH LecturePLUS Timberlake18

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