3.3.6 Example 2

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    3.3.6 Example 2 - Presentation Transcript

    1. Example 2: How much voltage must you apply across a 10μF capacitor to cause an AC current of 25mA at 50 Hz to flow
    2. 25mA at 50 Hz to flow XC = 1 / 2 π f C = 1 / 2 x 3.1416 x 50 x 10 x 10-6 = 318.5 Ω
    3. Now, V = I XC = 25 x 10-3 x 318.5 = 7.96 V
    4. Example 3: Using this example where the is a 10V AC supply at 60 Hz applied to a simple capacitive circuit with a 100 μF capacitor, let’s calculate the current.
    5. XC =1 / 2 π f C = / 2 x 3.1416 x 60 x (100 x 10-6) 1 = 6.52 Ω 2
    6. I = V / XC = 10 / 26.52 = 0.3770 A

    + Talia CarbisTalia Carbis, 6 months ago

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