Apparent power (S)                   Reactive power (Q)
2.308 kVA




            49.46°

             True power (P) 1.5 ...
S2   =   P2   +   Q2


Q2   =   S2   -   P2


Q=       √(S2     -   P2)
Reactive Power (Q) = √ (S² - P²)

Q = √ (2308² - 1500²)
  = √(5326864 -2250000)
  = √3076864 =1754 VAR

Reactive Power (Q)...
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14.5.5 Example 1 Part 2

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14.5.5 Example 1 Part 2

  1. 1. Apparent power (S) Reactive power (Q) 2.308 kVA 49.46° True power (P) 1.5 kW
  2. 2. S2 = P2 + Q2 Q2 = S2 - P2 Q= √(S2 - P2)
  3. 3. Reactive Power (Q) = √ (S² - P²) Q = √ (2308² - 1500²) = √(5326864 -2250000) = √3076864 =1754 VAR Reactive Power (Q) = 1.754 kVAR

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