Applied Electricity Two
12Ω at 20ºC. What’s the resistance at 90ºC?
12 (234.5+ 90)
R2=
(234.5+ 20)

Applied Electricity Two
12 (234.5+ 90)
11.48Ω=
(234.5+ 20)

Applied Electricity Two
R2=R1[1+α1(t2-t1)]

Applied Electricity Two
R2= Resistance that needs to be calculated
R1= reference resistance (what you start with)
α= temperature coefficient of resistance for the
conductor.
T2= Where you want to get too
T1= Where you start

Applied Electricity Two
Resistance of 24Ω at 20ºC. What’s the resistance at
120ˆC?
R2=R1[1+α1(t2-t1)]

Applied Electricity Two
R2=24[1+0.00393(120-20)]

Applied Electricity Two
33.43Ω=24[1+0.00393
(120-20)]