Simulate all Page Replacement Algorithms    a) FIFO Page Replacement Algorithm#include<stdio.h>#include<conio.h>int str[30...
return 0; }OUTPUT:1) Enter the No.of frames:3 Enter string (-1 to stop):2 3 2 1 5 2 4 5 3 2 5 2 -1    Pages Frames      <2...
b) LRU Page Replacement Algorithm#include<stdio.h>#include<conio.h>int str[30],count,fs,p[100],pf;main(){ int i,j,k,z,temp...
}lru(int pos){int i,j=0,r=0;for(i=0;i<fs;i++){if(p[i]==-1)return i;if(rec(i,pos)>=r){ j=i; r=rec(i,pos);} }return j;}rec(i...
c) LFU page replacement Algorithm#include<stdio.h>int i,j=1,s,k,l,re[30],p[10],ch,no,nr,c,a1=0,a,line=6,nk;struct{        ...
}                                       if(a>1)                                       {                                   ...
printf("%d",p[k]);              else              printf(" ");              printf("_");       }      printf("|"); }OUTPUT...
3.Simulate all File Allocation Strategiesa) Sequential file allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>...
{            printf("%5dt",i);            for(j=1;j<=p[i];j++)                 printf("%5d",k[i][j]);            printf("n...
b) Indexed File allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>struct block{  int bno,flag;};struct block b...
k=rand()%100;     if(b[k].flag!=-1)       break;  }return k;}OUTPUT:Enter the no of files: 3Enter the memory requirements:...
c) Linked File Allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>typedef struct{        int bno,flag,bn[20];}b...
c=1;       for(i=1;i<=n;i++)       {         printf("n allocated for file%d",i);         for(j=1;j<=p[i];j++)         {   ...
4. Simulate all File Organization Techniquesa) Single level directory#include<stdio.h>#include<conio.h>#include<stdlib.h>#...
OUTPUT:
b) Two level Directory//two level directory structure#include<stdio.h>#include<conio.h>#include<graphics.h>#define SX 250#...
setfillstyle(1,cols[i]);  x1=SX+(i%10)*50;  y1=SY+(i/10)*40;  bar(x1,y1,x1+BL+20,y1+BW);  outtextxy(x1+BL/4,y1+BW/4,f[i].n...
5.Interprocess Communication   a) Pipes#include<stdio.h> #include<string.h> #include<stdlib.h> #include<error.h> #define M...
if(write(writefd,buff,n)!=n) printf("client filename error"); while((n=read(readfd,buff,MAXBUFF))>0) if(write(1,buff,n)!=n...
b) FIFO#include<stdlib.h> #include<sys/types.h> #include<stdio.h> #include<sys/stat.h> #include<string.h> #include<sys/wai...
c) Semaphores#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <errno.h>#include <sys/types.h>#include <sys...
int ready = 0;       semid = semget(key, nsems, 0);       if (semid < 0) return semid;        arg.buf = &buf;       for(i ...
printf("Press return to lock: ");getchar();printf("Trying to lock...n");if (semop(semid, &sb, 1) == -1){   perror("semop")...
d) Message Queues/*server*/  #include<sys/types.h>  #include<sys/ipc.h>  #include<sys/msg.h>  #include<stdio.h>  #include<...
#define MAX 5700  typedef struct msgbuf{ long mtype; char mtext[MAX]; }my_msgbuff; main(){ my_msgbuff buffer; int msgID,my...
e) Shared Memory/*server*/  #include<sys/types.h>  #include<sys/ipc.h>  #include<sys/shm.h>  #include<stdio.h>  #include<s...
#include<sys/ipc.h> #include<sys/shm.h> #include<stdio.h> #include<stdlib.h> #define SHMSZ 27 main() { int shmid; key_t ke...
Banker’s Algorithm for Deadlock avoidance and Prevention#include<stdio.h>#include<conio.h>int C[4][3],A[4][3],RQ[4][3],V[3...
continue; for(j=0;j<nr;j++) { if(V[j] >= RQ[i][j]) count++;   }  if(count == nr) {  K[i] = i+1;  for(j=0;j<nr;j++)        ...
4Enter the total number of resources in R25Enter the total number of processes to be executed4Enter the claim matrix2462En...
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Os 2 cycle

  1. 1. Simulate all Page Replacement Algorithms a) FIFO Page Replacement Algorithm#include<stdio.h>#include<conio.h>int str[30],z,count,fs,p[100],pf=0;main(){ int i,j,k,temp; printf("n Enter the No.of frames:"); scanf("%d",&fs); printf("n Enter string (-1 to stop):"); i=0; while(1) { scanf("%d",&temp); if(temp==-1) break; str[i++]=temp; } count=i; for(i=0;i<fs;i++) p[i]=-1; printf("nt Pages t Frames"); i=j=0; while(i<count) { if(!check(str[i])) { pf++; p[j]=str[i]; j=(j+1)%fs; } printf("nt <%d> t",str[i]); for(k=0;k<fs;k++) if(p[k]!=-1) printf("%3d",p[k]); i++; } z=pf-fs; printf("nt Page Faults:%d",z); } check(int key) { int i; for(i=0;i<fs;i++) if(key==p[i]) return 1;
  2. 2. return 0; }OUTPUT:1) Enter the No.of frames:3 Enter string (-1 to stop):2 3 2 1 5 2 4 5 3 2 5 2 -1 Pages Frames <2> 2 <3> 2 3 <2> 2 3 <1> 2 3 1 <5> 5 3 1 <2> 5 2 1 <4> 5 2 4 <5> 5 2 4 <3> 3 2 4 <2> 3 2 4 <5> 3 5 4 <2> 3 5 2 Page Faults:6
  3. 3. b) LRU Page Replacement Algorithm#include<stdio.h>#include<conio.h>int str[30],count,fs,p[100],pf;main(){ int i,j,k,z,temp; printf("n Enter the No.of frames:"); scanf("%d",&fs); printf("n Enter string (-1 to stop):"); i=0; while(1) { scanf("%d",&temp); if(temp==-1) break; str[i++]=temp; } count=i; for(i=0;i<fs;i++) p[i]=-1; printf("n Pages tt Frames"); i=0; while(i<count) { if(!check(str[i])) { pf++; j=lru(i); p[j]=str[i]; } printf("n %3d tt",str[i]); for(k=0;k<fs;k++) if(p[k]!=-1)printf("%3d",p[k]); i++; } z=pf-fs; printf("nn Page Faults:%d",z); } check(int key) { int i; for(i=0;i<fs;i++) if(key==p[i]) return 1; return 0;
  4. 4. }lru(int pos){int i,j=0,r=0;for(i=0;i<fs;i++){if(p[i]==-1)return i;if(rec(i,pos)>=r){ j=i; r=rec(i,pos);} }return j;}rec(int fn,int pn){int i,c=0;for(i=pn-1;i>=0;i--){ c++; if(p[fn]==str[i]) return c; } }OUTPUT1) Enter the No. of frames: 3Enter string (-1 to stop):2 3 2 1 5 2 4 5 3 2 5 2 -1Pages Frames 2 2 3 2 3 2 2 3 1 2 3 1 5 2 5 1 2 2 5 1 4 2 5 4 5 2 5 4 3 3 5 4 2 3 5 2 5 3 5 2 2 3 5 2Page Faults:4
  5. 5. c) LFU page replacement Algorithm#include<stdio.h>int i,j=1,s,k,l,re[30],p[10],ch,no,nr,c,a1=0,a,line=6,nk;struct{ int st,l,ps,pos;}opr;main(){ clrscr(); printf("Enter length of reference string:"); scanf("%d",&nr); printf(" Enter reference string:"); for(i=1;i<=nr;i++) scanf("%d",&re[i]); printf("n Enter number of frames:"); scanf("%d",&no); clrscr(); for(i=1;i<=no;i++) p[i]=-1; opr.st=100; for(i=1;i<=nr;i++) { a1=0; opr.st=100; opr.pos=100; for(c=1;c<=no;c++) if(re[i]==p[c]) a1++; if(a1==0) { if(j<=no) { p[j]=re[i]; j++; } else { for(k=1;k<=no;k++) { a=0; for(ch=i-1;ch>0;ch--) { if(p[k]==re[ch]) { a++; nk=ch; }
  6. 6. } if(a>1) { if(opr.st>a) { opr.st=a; opr.ps=k; } else if(opr.st==a) { if(opr.pos>ch) opr.ps=k; } } else if(a==1) { if(opr.pos>nk) { opr.pos=nk; opr.ps=k; opr.st=a; } } } p[(opr.ps)]=re[i]; } } display(no,p,i); } printf("n"); getch();}display(int no,int p[],int i){ int k; if(i==1) { printf("ttt"); for(k=1;k<=no;k++) printf("_ _"); } printf("n%d",re[i]); gotoxy(25,line++); for(k=1;k<=no;k++) { printf("|"); printf("_"); if(p[k]!=-1)
  7. 7. printf("%d",p[k]); else printf(" "); printf("_"); } printf("|"); }OUTPUT:Least frequently usedEnter no of frame 3Enter no of pages 4Enter page sequence 4 5 8400F450F458FNo of page faults 3
  8. 8. 3.Simulate all File Allocation Strategiesa) Sequential file allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>typedef struct{ int bno,flag;}block; block b[200];void main(){ int rnum(); int n,p[30],i,j,r,k[20][20],s,s1; printf("n input"); printf("n enter no of files"); scanf("%d",&n); printf("n-------------------------------"); printf("n enter memory requirements"); printf("n------------------------------"); for(i=1;i<=n;i++) { printf("n enter %d file requirements:",i); scanf("%d",&p[i]); } for(i=1;i<=n;i++) { s1=rnum(); j=0; for(s=s1;s<(s1+p[i]);s++) { j=j+1; b[s].bno=s; b[s].flag=1; k[i][j]=s; } } printf("n output"); printf("n ---------------------------------"); printf("n program blocka allocated"); printf("n----------------------------------"); for(i=1;i<=n;i++)
  9. 9. { printf("%5dt",i); for(j=1;j<=p[i];j++) printf("%5d",k[i][j]); printf("n"); } printf("n------------------------------------");printf("n allocated blocks:"); printf("n-----------------------------------"); for(i=1;i<=200;i++) if(b[i].flag==1) printf("%5dt",b[i].bno);}int rnum(){ int i,k=0; for(i=1;i<=200;i++) { k=rand()%200; if(k%2==0) k=k+10; if(b[k].flag!=1) break; return k; }}OUTPUT:Enter the no of input files : 3Input the requirements:Enter the no of blocks needed in file 1: 2Enter the no of blocks needed in file2 :4Enter the no of blocks needed in file3: 3AllocationAllocate for file1: 8386Allocate for file2: 77159335Allocate for file3:924921
  10. 10. b) Indexed File allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>struct block{ int bno,flag;};struct block b[100];int rnum();void main(){ int p[10],r[10][10],ab[10],i,j,n,s; printf("n INPUT"); printf("enter no of files:"); scanf("%d",&n); for(i=1;i<=n;i++) { printf("n enter the size of block %d:",i); scanf("%d",&p[i]); } for(i=1;i<=n;i++) { s=rnum(); ab[i]=s; for(j=0;j<p[i];j++) { s=rnum(); r[i][j]=s; }}printf("n output:"); for(i=1;i<=n;i++){ printf("n file %d n block %d contains:",i,ab[i]); for(j=0;j<p[i];j++) { printf("%6d",r[i][j]); }}}int rnum(){int k=0,i; for(i=1;i<=100;i++) {
  11. 11. k=rand()%100; if(b[k].flag!=-1) break; }return k;}OUTPUT:Enter the no of files: 3Enter the memory requirements:Enter the 1 file requirement: 3Enter the 2 file requirement: 2Enter the 3 file requirement: 4Program blocks allocated1 70 71 722 115 1163 212 213 214 215Allocated blocks70 71 72 115 116 212 213 214 215
  12. 12. c) Linked File Allocation#include<stdio.h>#include<conio.h>#include<stdlib.h>typedef struct{ int bno,flag,bn[20];}block; block b[100],b1;void main(){ int rnum(); int p[30],kk[20],i,n,t,s1,s,r,j,c=1; printf("n enter no of i/p files"); scanf("%d",&n); printf("n input the requirements"); for(i=1;i<=n;i++) { printf("n enter the no of blocks needed for file%d",i); scanf("%d",&p[i]); } t=1; for(i=1;i<=n;i++) { for(j=1;j<=p[i];j++) { s=rnum(); b[s].flag=1; b[c].bno=s; r=p[i]-1; kk[i]=s; t=1; c++; } } while(r!=0) { s1=rnum(); b[s].bn[t]=s1; b[s1].flag=1; b[c].bno=s1; r=r-1; t=t+1; c++; } printf("n allocation:n");
  13. 13. c=1; for(i=1;i<=n;i++) { printf("n allocated for file%d",i); for(j=1;j<=p[i];j++) { if(j==1) { printf("%3d",b[c].bno); c++; } else { printf("---->%3d",b[c].bno); c++; } } printf("n"); }}int rnum(){ int k=0,i; for(i=1;i<=100;i++) { k=rand()%100; if(b[k].flag!=1) break; } return k;}OUTPUT:Enter the no of files 3Enter the size of block 1 2 34 3 2File 1 Block 83 contains 86 77 15 93File 2 Block 85 contains 86 92 49File 3 Block 21 contains 62 27
  14. 14. 4. Simulate all File Organization Techniquesa) Single level directory#include<stdio.h>#include<conio.h>#include<stdlib.h>#include<graphics.h>void main(){ int gd,gm,count,i,j,mid,cir_x; char fname[10][20]; gd=DETECT; clrscr(); initgraph(&gd,&gm,"c:/turboc"); cleardevice(); setbkcolor(GREEN); puts("n Enterno.of files do u have?"); scanf("%d",&count); for(i=0;i<count;i++) { cleardevice(); setbkcolor(GREEN); printf("Enter file %d name ",i+1); scanf("%s",fname[i]); setfillstyle(1,MAGENTA); mid=640/count; cir_x=mid/3; bar3d(270,100,370,150,0,0); settextstyle(2,0,4); settextjustify(1,1); outtextxy(320,125,"Root Directory"); setcolor(BLUE); for(j=0;j<=i;j++,cir_x+=mid) { line(320,150,cir_x,250); fillellipse(cir_x,250,30,30); outtextxy(cir_x,250,fname[i]); } getch(); }}
  15. 15. OUTPUT:
  16. 16. b) Two level Directory//two level directory structure#include<stdio.h>#include<conio.h>#include<graphics.h>#define SX 250#define SY 200#define BL 30#define BW 15#define SY1 250int SX1=100;int n,m[10];char a[10][10];int cols[]={2,5,1,3,4,6,8,7,9};typedef struct{ char name[10]; struct { char file[10]; }k[10];}file_info;file_info f[10];void readfiles(){ int i,j; printf("nEnter no. of directories:"); scanf("%d",&n); for(i=0;i<n;i++) { printf("Enter %d directory:",i+1); scanf("%s",&f[i].name); printf("enter no.of files:"); scanf("%d",&m[i]); for(j=0;j<m[i];j++) { printf("enter %d file name:",j+1); scanf("%s",&f[i].k[j].file); } }}void fillspace(){ int x1,y1,i,j; outtextxy(70,205,"Directory"); outtextxy(100,255,"Files"); for(i=0;i<n;i++) {
  17. 17. setfillstyle(1,cols[i]); x1=SX+(i%10)*50; y1=SY+(i/10)*40; bar(x1,y1,x1+BL+20,y1+BW); outtextxy(x1+BL/4,y1+BW/4,f[i].name); line(x1+BL/2,y1+BW,SX1+50,SY1); SX1=SX1+50; for(j=0;j<m[i];j++) { setfillstyle(1,cols[i]); x1=SX1+(j%10)*40; y1=SY1+(j/10)*40; bar(x1,y1,x1+BL+10,y1+BW); outtextxy(x1+BL/4,y1+BW/4,f[i].k[j].file); line(x1+BL/2,y1+BW,x1+BL/2,y1+50); circle(x1+BL/2,y1+60,7); } SX1=SX1+100; }}void main(){ int gm,gd=DETECT; initgraph(&gd,&gm,"c:tcbgi"); readfiles(); cleardevice(); getch(); fillspace(); getch(); closegraph();}
  18. 18. 5.Interprocess Communication a) Pipes#include<stdio.h> #include<string.h> #include<stdlib.h> #include<error.h> #define MAXBUFF 1024 main() { int childpid,pipe1[2],pipe2[2]; if(pipe(pipe1)<0||pipe(pipe2)<0) printf("error"); if((childpid=fork())<0) { printf("error"); } else if(childpid>0) { close(pipe1[0]); close(pipe2[1]); client(pipe2[0],pipe1[1]); while(wait((int *)0)!=childpid) close(pipe1[1]); close(pipe2[0]); exit(1); } else { close(pipe1[1]); close(pipe2[0]); server(pipe1[0],pipe2[1]); close(pipe1[0]); close(pipe2[1]); } } client(readfd,writefd) int readfd,writefd; { char buff[MAXBUFF]; int n; if(fgets(buff,MAXBUFF,stdin)==NULL) printf("client filename read error"); n=strlen(buff); if(buff[n-1]==n) n--;
  19. 19. if(write(writefd,buff,n)!=n) printf("client filename error"); while((n=read(readfd,buff,MAXBUFF))>0) if(write(1,buff,n)!=n) printf("client data write error"); if(n>0) printf("client: data read errror"); } server(readfd,writefd) int readfd,writefd; { char buff[MAXBUFF]; int n,fd; if((n=read(readfd,buff,MAXBUFF))<0) printf("srever filename read error"); buff[n]=0; if((fd=open(buff,0))<0) { n=strlen(buff); if(write(writefd,buff,n)!=n) printf("server :error msg"); } else { while((n=read(fd,buff,MAXBUFF))>0) if(write(writefd,buff,n)!=n) printf("server data write error"); if(n>0) printf("server read error"); } }OUTPUT:vi a.txt welcome to NP ]$ ./a.out a.txt welcome to NP
  20. 20. b) FIFO#include<stdlib.h> #include<sys/types.h> #include<stdio.h> #include<sys/stat.h> #include<string.h> #include<sys/wait.h> #define FIFO1 "tmp/fifo1.c" #define FIFO2 "tmp/fifo2.c" #define PERM 0666 main() { int chpid,rfd,wfd; mknod(FIFO1,S_IFIFO|PERM,0); mknod(FIFO2,S_IFIFO|PERM,0); if(chpid=fork()>0) { wfd=open(FIFO1,1); rfd=open(FIFO2,0); client(rfd,wfd); while(wait((int *)0)!=chpid) close(rfd); close(wfd); exit(1); } }OUTPUT: hello HELLO :from server
  21. 21. c) Semaphores#include <stdio.h>#include <stdlib.h>#include <unistd.h>#include <errno.h>#include <sys/types.h>#include <sys/ipc.h>#include <sys/sem.h>#define MAX_RETRIES 10union semun { int val; struct semid_ds *buf; ushort *array;};int initsem(key_t key, int nsems){ int i; union semun arg; struct semid_ds buf; struct sembuf sb; int semid; semid = semget(key, nsems, IPC_CREAT | IPC_EXCL | 0666); if (semid >= 0) { sb.sem_op = 1; sb.sem_flg = 0; arg.val = 1; printf("press returnn"); getchar(); for(sb.sem_num = 0; sb.sem_num < nsems; sb.sem_num++) { if (semop(semid, &sb, 1) == -1) { int e = errno; semctl(semid, 0, IPC_RMID); errno = e; return -1; } } }else if (errno == EEXIST){
  22. 22. int ready = 0; semid = semget(key, nsems, 0); if (semid < 0) return semid; arg.buf = &buf; for(i = 0; i < MAX_RETRIES && !ready; i++) { semctl(semid, nsems-1, IPC_STAT, arg); if (arg.buf->sem_otime != 0) { ready = 1; } else { sleep(1); } } if (!ready) { errno = ETIME; return -1; } } else { return semid; } return semid;}int main(void){ key_t key; int semid; struct sembuf sb; sb.sem_num = 0; sb.sem_op = -1; sb.sem_flg = SEM_UNDO; if ((key = ftok("semdemo.c", J)) == -1) { perror("ftok"); exit(1); } if ((semid = initsem(key, 1)) == -1) { perror("initsem"); exit(1); }
  23. 23. printf("Press return to lock: ");getchar();printf("Trying to lock...n");if (semop(semid, &sb, 1) == -1){ perror("semop"); exit(1);}printf("Locked.n");printf("Press return to unlock: ");getchar();sb.sem_op = 1; /if (semop(semid, &sb, 1) == -1){ perror("semop"); exit(1); } printf("Unlockedn"); return 0;} OUTPUT:
  24. 24. d) Message Queues/*server*/ #include<sys/types.h> #include<sys/ipc.h> #include<sys/msg.h> #include<stdio.h> #include<stdlib.h> #include<string.h> #define BUFSZ 4096 struct msg { 10 long int type; char text[BUFSZ]; }; int main() { struct msg data; int msgid; char buff[BUFSZ]; msgid=msgget((key_t)4321,0666|IPC_CREAT); while(1) { 21 printf("n enter some data:nn"); fgets(buff,BUFSZ,stdin); data.type=1; strcpy(data.text,buff); msgsnd(msgid,(void *)&data,BUFSZ,0); exit(1); } 28 }OUTPUT: enter some data hai/*client*/ #include<sys/types.h> #include<sys/ipc.h> #include<sys/msg.h> #include<stdio.h> #include<stdlib.h> #include<string.h> #define MSGKEY1 4321L
  25. 25. #define MAX 5700 typedef struct msgbuf{ long mtype; char mtext[MAX]; }my_msgbuff; main(){ my_msgbuff buffer; int msgID,myID; int temp; if((msgID=msgget(MSGKEY1,0666|IPC_CREAT))<0) {perror("error getting msg queue"); exit(1);} if(msgrcv(msgID,&buffer,sizeof(buffer),0L,0)<0) { perror("error receiving msg from queue"); exit(1); } printf("n msg read from queue:nn");printf("MESSAGE:%sn",buffer.mtext);while(msgsnd(msgID,&buffer,sizeof(buffer.mtext),0)>0); if(msgctl(msgID,IPC_RMID,0)<0){ perror("error detecting msg queue");exit(1); } msgctl(myID,IPC_RMID,0); exit(0); }OUTPUT:msg read from queue: MESSAGE:hai
  26. 26. e) Shared Memory/*server*/ #include<sys/types.h> #include<sys/ipc.h> #include<sys/shm.h> #include<stdio.h> #include<stdlib.h> #define SHMSZ 27 main() { char c; int shmid; key_t key; char *shm,*s; key=1202; if((shmid=shmget(key,SHMSZ,IPC_CREAT|0666))<0) { perror("shmat"); exit(1); } if((shm=shmat(shmid,NULL,0))==(char *)-1) { perror("shmat"); exit(1); } s=shm; for(c=a;c<=z;c++) *s++=c; *s=NULL; while(*shm!=*) sleep(1); exit(0); }/*client*/ #include<sys/types.h>
  27. 27. #include<sys/ipc.h> #include<sys/shm.h> #include<stdio.h> #include<stdlib.h> #define SHMSZ 27 main() { int shmid; key_t key; key=1202; char *s,*shm; if((shmid=shmget(key,SHMSZ,0666))<0) { perror("shmget"); exit(1); } if((shm=shmat(shmid,NULL,0))==(char *)-1) { perror("shmat"); exit(1); } for(s=shm;*s!=NULL;s++) putchar(*s); putchar(n); *shm=*; exit(0); }OUTPUT:abcdefghijklmnopqrstuvwxyz
  28. 28. Banker’s Algorithm for Deadlock avoidance and Prevention#include<stdio.h>#include<conio.h>int C[4][3],A[4][3],RQ[4][3],V[3],R[3],K[4],sum=0,np,nr;main(){void fun();int i,j,count=0,pcount=0;clrscr();printf("nEnter the total number of resources : ");scanf("n%d",&nr);for(i=0;i<nr;i++) { printf("nEnter the no of resources int R%d : ",i+1); scanf("%d",&R[i]); }printf("nEnter the no of processes to be executed : ");scanf("%d",&np);printf("nEnter the claim matrix:n");for(i=0;i<np;i++)for(j=0;j<nr;j++)scanf("%d",&C[i][j]);printf("nEnter the allocation matrix:n");for(i=0;i<np;i++)for(j=0;j<nr;j++)scanf("%d",&A[i][j]);for(i=0;i<np;i++)for(j=0;j<nr;j++)RQ[i][j] = C[i][j] - A[i][j];fun();for(i=0;i<np;i++){count=0;f(K[i] == i+1)
  29. 29. continue; for(j=0;j<nr;j++) { if(V[j] >= RQ[i][j]) count++; } if(count == nr) { K[i] = i+1; for(j=0;j<nr;j++) C[i][j] = A[i][j] = RQ[i][j] = 0; pcount++; count = 0; i=-1; fun(); } } if(pcount == np) printf("nThere is no chance of deadlock.nIt is a safe state."); else printf("nThere is a chance of deadlock.nIt isnt a safe state."); getch(); } void fun() { int i1,j1; for(i1=0;i1<nr;i1++) { for(j1=0;j1<np;j1++) { sum = sum + A[j1][i1]; } V[i1] = R[i1] - sum; sum = 0; } }OUTPUT Enter the total number of resources 2 Enter the total number of resources in R1
  30. 30. 4Enter the total number of resources in R25Enter the total number of processes to be executed4Enter the claim matrix2462Enter the allocation matrix1011There is a chance of deadlockIt is not a safe state

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