Upcoming SlideShare
×

# Hprec10 2

134 views
103 views

Published on

Published in: Education, Technology
0 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
• Be the first to comment

• Be the first to like this

Views
Total views
134
On SlideShare
0
From Embeds
0
Number of Embeds
0
Actions
Shares
0
3
0
Likes
0
Embeds 0
No embeds

No notes for slide

### Hprec10 2

1. 1. 10-2: The Law of Sines ©2008 Roy L. Gover (www.mrgover.com) Learning Goals •Derive the Law of Sines •Solve triangles using the law of sines
2. 2. Important Idea •The Law of Cosines can be used to solve oblique triangles when SAS or SSS information is given. •The Law of Sines provides a way to solve triangles when the Law of Cosines does not work.
3. 3. Analysis A B C D a c b 2r Observations BCD is a rt. triangle 1. 3. 2 = a sinD r 4. = a sin A 2r ∠ ≅ ∠2. A D Case I
4. 4. Analysis A B C D a c b 2r Observations 3. = b sinD 2r 4. = b sinB 2r CAD is a rt. triangle 1. ∠ ≅ ∠2. B D Case II
5. 5. Analysis A B C D a c b 2r Observations 2.∠ D C∠≅ 3. = c sinD 2r 4. = c sin C 2r ABD is a rt. triangle 1. Case III
6. 6. Analysis = ⇒ = a a sin A 2r 2r sin A = ⇒ = b b sinB 2r 2r sinB = ⇒ = c c sin C 2r 2r sin C
7. 7. therefore: = = a b c sin A sinB sin C is the Law of Sines It’s a beautiful thing!!!
8. 8. Example 82° 200 ft Find the distance across the lake. 44° = ° ° d 200 sin 82 sin54 54° d
9. 9. Important Idea The Greek astronomer, Hipparchus of Nicaea, used the idea in the last example called triangulation to estimate the distance from the earth to the moon in 150 B.C.
10. 10. Try This Solve ABC if A=32.2°, B=57.7° and c=14.3 A B C C=90.1°,a=7.6 & b=12.1
11. 11. Try This Solve ABC if A=29.2° B=62.3° and c=11.5 A B C C=88.5°,a=5.6 & b=10.2
12. 12. Important Idea To use the law of sines, you must know at least one angle and the measure of the side opposite that angle. A a
13. 13. Try This Solve ABC if A=30° b=5.6 and c=11.5 A B C Can’t Solve
14. 14. Summary The following is true about the law of sines problems we have worked: •two angles are given •the side opposite one of these angles is given
15. 15. Important Idea When one angle and two sides (with one side across from the angle) are given, the following may be true: •No triangle exists •one triangle exists •two triangles exist
16. 16. Example 1 Solve ABC if A=60° b=50 and a=33 A B C 60° 50 33 a<bsinA⇒no solution 50sin60°
17. 17. Solve ABC if A=60° b=50 and a=45 A B C 60° 50 45 Solution #1 Example 2
18. 18. Solve ABC if A=60° b=50 and a=45 A B C 60° 50 45 Solution #2 Example 2 (cont.)
19. 19. Solve ABC if A=60° b=50 and a=45 A B C 60° 50 45 bsina bsina<a<b⇒2 solutions Example 2 (cont.)
20. 20. Example 3 Solve ABC if A=60° b=50 and a=65 A B C 60° 50 bsin a 65 Solution#1
21. 21. Solve ABC if A=60° b=50 and a=65 A C 60° 50 bsin a 65 No solution#2 Example 3 (cont.)
22. 22. Solve ABC if A=60° b=50 and a=65 A B C 60° 50 bsin a 65 a>bsina & a>b⇒1 solution Example 3 (cont.)
23. 23. Deep Thoughts Life and mathematics are sometimes complicated
24. 24. Lesson Close What is the purpose of the law of sines?