Let ’s Review VELOCITY is the SLOPE of a distance, position, or displacement vs. time graph.
Let ’s Review What is the slope doing? CHANGING, INCREASING What is the velocity doing? CHANGING, INCREASING
Now for Velocity vs. Time Graphs In a velocity vs. time graph, acceleration is the slope
Velocity vs. Time Graphs Describe the acceleration during interval A. The acceleration or SLOPE is constant and positive. Describe the acceleration during interval B. The acceleration or SLOPE is ZERO. Describe the acceleration during interval C. The acceleration or SLOPE is constant and negative.
The same thing can be done to find velocity, if given an acceleration vs. time graph
Find the area under the curve.
The Area Model v What is the change in Velocity during the t=2 to t=4 interval?
You can also calculate the change in velocity by calculating the area under the curve of an acceleration vs. time graph.
In summary t (s) t (s) t (s) x (m) v (m/s) a (m/s/s) slope = v slope = a area = x area = v Graph Slope Area x vs. t Velocity N/A v vs. t Acceleration Displacement a vs. t N/A Velocity Slope Graph Area x vs. t v vs. t a vs. t
Comparing and Sketching graphs One of the more difficult applications of graphs in physics is when given a certain type of graph and asked to draw a different type of graph t (s) x (m) slope = v t (s) v (m/s)
List 2 adjectives to describe the SLOPE or VELOCITY
The slope is CONSTANT The slope is POSITIVE How could you translate what the SLOPE is doing on the graph ABOVE to the Y axis on the graph to the right?
Example: A boat moves slowly out of a marina (so as to not leave a wake) with a speed of 1.50 m/s. As soon as it passes the breakwater, leaving the marina, it throttles up and accelerates at 2.40 m/s/s .
a) How fast is the boat moving after accelerating for 5 seconds? 13. 5 m/s What do I know? What do I want? v o = 1.50 m/s v = ? a = 2.40 m/s/s t = 5 s
Kinematic #2 b) How far did the boat travel during that time? 37.5 m
Does all this make sense? 1.5 m/s 13.5 m/s Total displacement = 7.50 + 30 = 37.5 m = Total AREA under the line.
Kinematic #3 Example: You are driving through town at 12 m/s when suddenly a ball rolls out in front of your car. You apply the brakes and begin decelerating at 3.5 m/s/s. How far do you travel before coming to a complete stop? 20.57 m What do I know? What do I want? v o = 12 m/s x = ? a = -3.5 m/s/s V = 0 m/s