05/20/14 Lecture PLUS Timberlake 1
Chapter 9
Acids and Bases
Acid-Base Neutralization
Buffers
Acid-Base Titration
05/20/14 Lecture PLUS Timberlake 2
Neutralization Reactions
When acid and bases with equal amounts of
hydrogen ion H+
and ...
05/20/14 Lecture PLUS Timberlake 3
Neutralization
H3O+
and OH-
combine to produce water
H3O+
+ OH-
→ 2 H2O
from acid from...
05/20/14 Lecture PLUS Timberlake 4
Ionic Equations for Neutralization
Write strong acids, bases, and salt as ions
H+
+ Cl-...
05/20/14 Lecture PLUS Timberlake 5
Balancing Neutralization
Equations
Write the equation for the neutralization
between ma...
05/20/14 Lecture PLUS Timberlake 6
3. Write the products:
Mg(OH)2 + 2HNO3 Mg(NO3)2 + H2O
salt water
(metal and nonmetal)
4...
05/20/14 Lecture PLUS Timberlake 7
Learning Check N2
Select the correct group of coefficients for the
following neutraliza...
05/20/14 Lecture PLUS Timberlake 8
Solution N2
A. 3HCl + 1Al(OH)3 1AlCl3 + 3H2O
B. 3Ba(OH)2 + 2H3PO4 1Ba3(PO4)2 + 6H2O
05/20/14 Lecture PLUS Timberlake 9
Learning Check N3
Write a balanced equation and calculate
the mL of 2.00 M H2SO4 requir...
05/20/14 Lecture PLUS Timberlake 10
Solution N3
How many mL of 2.00 M H2SO4 are required to
neutralize 50.0 mL of 1.00 M K...
05/20/14 Lecture PLUS Timberlake 11
Learning Check N4
A 25 mL sample of phosphoric acid is
neutralized by 40. mL of 1.5 M ...
05/20/14 Lecture PLUS Timberlake 12
Solution S4
0.040 L x 1.5 mole NaOH x 1 mole H3PO4
1 L 3 mole NaOH
x 1 = 0.80 mol/L = ...
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Acids, bases + neutralization 1

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Acids, bases + neutralization 1

  1. 1. 05/20/14 Lecture PLUS Timberlake 1 Chapter 9 Acids and Bases Acid-Base Neutralization Buffers Acid-Base Titration
  2. 2. 05/20/14 Lecture PLUS Timberlake 2 Neutralization Reactions When acid and bases with equal amounts of hydrogen ion H+ and hydroxide ions OH- are mixed, the resulting solution is neutral. NaOH (aq) + HCl(aq) NaCl + H2O base acid salt water Ca(OH)2 + 2 HCl CaCl2 + 2H2O base acid salt water
  3. 3. 05/20/14 Lecture PLUS Timberlake 3 Neutralization H3O+ and OH- combine to produce water H3O+ + OH- → 2 H2O from acid from base neutral Net ionic equation: H+ + OH- → H2O
  4. 4. 05/20/14 Lecture PLUS Timberlake 4 Ionic Equations for Neutralization Write strong acids, bases, and salt as ions H+ + Cl- + Na+ + OH- Na+ + Cl- + H2O Cross out matched ions H+ + Cl- + Na+ + OH- Na+ + Cl- + H2O Write a net ionic reaction H+ + OH- H2O
  5. 5. 05/20/14 Lecture PLUS Timberlake 5 Balancing Neutralization Equations Write the equation for the neutralization between magnesium hydroxide and nitric acid. 1. Write the formulas of the acid and base Mg(OH)2 + HNO3 2. Balance to give equal OH- and H+ Mg(OH)2 + 2 HNO3
  6. 6. 05/20/14 Lecture PLUS Timberlake 6 3. Write the products: Mg(OH)2 + 2HNO3 Mg(NO3)2 + H2O salt water (metal and nonmetal) 4. Balance products Mg(OH)2 + 2 HNO3 Mg(NO3)2 + 2 H2O
  7. 7. 05/20/14 Lecture PLUS Timberlake 7 Learning Check N2 Select the correct group of coefficients for the following neutralization equations A. __ HCl + __ Al(OH)3 __AlCl3 + __ H2O 1) 1, 3, 3, 1 2) 3, 1, 1, 1 3) 3, 1, 1 3 B.__ Ba(OH)2 + __H3PO4 __Ba3(PO4)2 + __ H2O 1) 3, 2, 2, 2 2) 3, 3, 1, 6 3) 2, 3, 1, 6
  8. 8. 05/20/14 Lecture PLUS Timberlake 8 Solution N2 A. 3HCl + 1Al(OH)3 1AlCl3 + 3H2O B. 3Ba(OH)2 + 2H3PO4 1Ba3(PO4)2 + 6H2O
  9. 9. 05/20/14 Lecture PLUS Timberlake 9 Learning Check N3 Write a balanced equation and calculate the mL of 2.00 M H2SO4 required to neutralize 50.0 mL of 1.00 M KOH? ___H2SO4 + ___KOH ___K2SO4 + H2O 1) 12.5 mL 2) 50.0 mL 3) 200. mL
  10. 10. 05/20/14 Lecture PLUS Timberlake 10 Solution N3 How many mL of 2.00 M H2SO4 are required to neutralize 50.0 mL of 1.00 M KOH? H2SO4 + 2KOH K2SO4 + 2H2O 0.0500 L x 1.00 mole KOH x 1 mole H2SO4 x 1 L 2 mole KOH 1 L x 1000 mL = 12.5 mL 2 mole KOH 1 L
  11. 11. 05/20/14 Lecture PLUS Timberlake 11 Learning Check N4 A 25 mL sample of phosphoric acid is neutralized by 40. mL of 1.5 M NaOH. What is the molarity of the phosphoric acid solution? 3NaOH + H3PO4 Na3PO4 + 3H2O 1) 0.45 M 2) 0.80 M 3) 7.2 M
  12. 12. 05/20/14 Lecture PLUS Timberlake 12 Solution S4 0.040 L x 1.5 mole NaOH x 1 mole H3PO4 1 L 3 mole NaOH x 1 = 0.80 mol/L = 0.80 M 0.025 L
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