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# Stoichiometry

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### Transcript

• 1. Stoichiometry
• 2. You already know... In a balanced equation the coefficients are MOLES. 2H 2 + O 2 -> 2H 2 O 2 moles Hydrogen, 1 mole Oxygen, 2 moles H 2 O How to Calculate Molar Mass: H 2 O = H 2 x 1.01 = 2.02 O 1 x 16.00 = 16.00 18.02 g/mol 1 mole of anything is 22.42 L examples: 1 mole water = 22.42 L 1 mole H 2 SO 4 = 22.42 L 1 mole acetic acid = 22.42 L
• 3. Before the Math
• Balance the equation.
• You need the coefficients.
• Look at what numbers the question provides.
• Look at what the question is asking for.
• This is where you stop.
• It is also the correct label.
• 4. The Math
• Step 1: Get to the mole.
• Step 2: Mole to mole ratio from the balanced equation.
• Step 3: Use the mole to get to what you want.
• *KEEP LIKE TERMS DIAGONAL.
• 5. Finding Moles (this is going to be the first step in all the other types of problems)
• How many moles of oxygen are formed if 1.34 moles of H 2 O 2 completely decomposes?
• 1) Write and balance:
• 2H 2 O 2 -> 2H 2 O + O 2 2:2:1
• 2) Do the math
= .67 mol O 2 1.34 mol H 2 O 2 (from the problem) 1 mol O 2 (from equation) 2 mol H 2 O 2 (from equation)
• 6. Finding Liters
• If I produce 2.4 L of oxygen in the decomposition of H 2 O 2 , how many L of H 2 O 2 did I start with?
• 1) Write and balance:
• 2H 2 O 2 -> 2H 2 O + O 2 2:2:1
• 2) Do the math:
= 4.8 L H 2 O 2 2.4 L O 2 1 mol O 2 2 mol H 2 O 2 22.42 L H 2 O 2 22.42 L O 2 1 mol O 2 1 mol H 2 O 2
• 7. Finding Grams
• In the decomposition of H 2 O 2 , how many grams of H 2 O 2 are required to produce 3.7g of water?
• 1) Write and balance: 2H 2 O 2 -> 2H 2 O + O 2 2:2:1
• 2) Because it is grams you need molar masses:
• O 2 = 32.00 g/mol, H 2 O = 18.02 g/mol, H 2 O 2 = 34.02 g/mol
• 3)Do the math.
= 7.02 g H 2 O 2 3.7 g H 2 O 1 mol H 2 O 2 mol H 2 O 2 34.02 g H 2 O 2 18.02 g H 2 O 2 mol H 2 O 1 mol H 2 O 2
• 8. Grams to Liters? The mole allows for any calculation.
• In the decomposition of H 2 O 2 , how many L of H 2 O 2 are required to produce 1.5 g of water?
• 1) Write and balance: 2H 2 O 2 -> 2H 2 O + O 2 2:2:1
• 2) Do the math:
= 1.87 L H 2 O 2 1.5 g H 2 O 1 mol H 2 O 2 mol H 2 O 2 22.42 L H 2 O 2 18.02 g H 2 O 2 mol H 2 O 1 mol H 2 O 2