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# Watertaxi-3rd project presentation-BUET

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### Transcript

• 1. BANGLADESH UNIVERSITY OF ENGINEERING & TECHNOLOGY
NAME 338
SHIP DESIGN PROJECT & PRESENTATION-3
DATE-18 ,April,2011
• 2. DESIGN OF A WATER TAXI FOR 100 PASSENGERS in SADARGHAT-ASHULIA ROUTE
Project Supervisor
KhabirulHaqueChowdhury
Professor
Department of Naval Architecture & Marine Engineering,BUET
Presented By-
Hasib-Ul-Haque (0712014)
• 3. OBJECTIVES
To use the circular water ways around Dhaka city
To ease the water way communication with comfortable service
To reduce the pressure on land transport.
To safe people from horrible traffic jam.
• 4. PRINCIPAL PARTICULARS
LENGTH:
OVERALL : 24.90 meter
Load water line : 24.122 meter
L.B.P : 22.95 meter
MAXIMUM : 6.5 meter
MOULDED : 6.3 meter
DEPTH(MLD) : 2.0 meter
DRAFT(MLD) : 1.1 meter
• 5. PRESENTATION TOPICS
1.Rudder design.
2.Engine selection and foundation.
3.GA and Lines plan update
4.Weight calculation update
5.Hydrostatic calculation update
6. Trim and Stability update
• 6. Rudder Design-Calculation from GL
• 8. Steering Arrangement
• 9. Resistance & Power CalculationHoltrop Mennen Method
RT = RF(1+K1) + RAPP + RW + RB + RTR + RA
Where,
• RF = Frictional resistance according to ITTC 1957 friction formula
• 10. (1+K1) = Form factor describing the viscous resistance of the hull form in relation to RF
• 11. RAPP = Appendage resistance
• 12. RW = Wave making and wave breaking resistance
• 13. RB = Additional pressure resistance due to bulbous bow near the water surface
• 14. RTR = Additional pressure resistance of immersed transom stern
• 15. RA = Model ship correlation resistance

• 16. Resistance & Power Calculation
For our ship we get,
RF= 4.6430 KN
(1+K1) = 1.22
RAPP = 0.1417 KN
RW= 9.0478 KN
RB = 0
RTR = 0
RA = 1.7609 KN
So, RT = 16.6149 KN
Effective power,PE = RT × V
= 16.6149 × 12 ×0.5149
= 102.65 KW = 137.68 HP
• 17. Resistance & Power Calculation
Shaft Power,Ps= PE/[ ηR η0ηs(1-t)/(1-w)] = 188.19 HP
Delivered Power,PD= ηs× Ps= 0.99 × 188.19 = 186.31 HP
Break horse power = PS/ ηG = 194.01 HP
Where,
ηG= gear efficiency = 97%
• 18. Engine Selection
Yanmar type 4JH4-HTE
• 19. Engine Selection
Steyr Motor Engines-M0114K33
• 20. Why we select Yanmar type 4JH4-HTE??
The Yanmar type 4JH4-HTE Engine is designed for high performance.
The innovative fuel injection technology enables an excellent torque and speed range.
Service Life-this engine is manufactured using high alloy materials to provide enduring longevity for all running components.
Comfort-The patented 2-stage UNIT Injector fuel injection technology provides for a worldwide approped and smooth operation noise
Exhaust Emissions-The trend-setting UNIT INJECTOR system enables us already today to conform with the valid emission regulations.
Transmission-this engine allow the installation with different driving system in our boat.
• 21. Power
Yanmar type 4JH4-HTE
Steyr Motor Engines-M0114K33
• 22. Fuel Consumption
Yanmar type 4JH4-HTE
Steyr Motor Engines-M0114K33
• 23. Torque
Yanmar type 4JH4-HTE
Steyr Motor Engines-M0114K33
• 24. Engine Dimension
Aft view
Right View
• 25. Engine Specification
• 26. Engine Foundation
• 30. Equipments
• 31. VARIANCE IN DATA
• 32. GA Update
• 33. MODIFICATION OF GENERAL ARRANGEMENT
1.Canteen facility has been cancelled
4.Seating arrangement has been renovated and updated
5.Change in Cabin type,size and position
• 34. Comparison between GA plans
GA-Updated
GA-Previous
• 35. Lines Plan Update
No of person on board:
No of passenger = 100
No of crew = 6
Total = 106
Weight allowance per person:
Weight per person = 75 kg
Luggage per person = 5 kg
Total = 80 kg
Total weight for persons = 80× 106
= 8.48 tons
• 38. Capacity calculation
• 39. Summery from Capacity Calculation
• 41. Lightweight calculation
• 42. SHELL EXPANSION
• 43. Longitudinal
• 44. CALCULATION OF WEIGHT OF PLATES
• 45. weight of other items
• 46. WEIGHT OF OTHER ITEMS
• 47. MISCELLANEOUS : 2 TONNE
• 48. So,the total lightweight of the vessel is = (9.47+47.93) tons
= 57.4 tons
Therefore,
the displacement of the vessel= Lightweight+Deadweight
= 57.4 + 17.48
= 74.88 tons
Which was previously 123.48 tons
• 49. HYDROSTATIC UPDATE
• 50.
• 51. Hydrostatic Parameters
• 52. Form coefficient
• 53. Longitudinal centre of buoyancy
Updated
Previous
• 54. Longitudinal metacentre
Updated
Previous
• 55. Transverse metacentre
Updated
Previous
• 56. Displacement
Updated
Previous
• 57. Water plane coefficient
Updated
Previous
• 58. Prismatic coefficient
Updated
Previous
• 59. Vertical centre of buoyancy
Updated
Previous
• 60. Block coefficient
Updated
Previous
• 61. Midship section coefficient
Updated
Previous
• 62. Longitudinal centre of flotation
Previous
Updated
• 63. MCT 1m
Previous
• 64. MCT 1m
Updated
• 65. STABILITY CALCULATION
• 66. GZ SAMPLE CALCULATION AT 30°INCLINATION
• 67. GZ SAMPLE CALCULATION AT 30° INCLINATION
V.C.G from keel= 1.31 m
KB = 0.69 m
• 68. GZ CURVE
• 69. TRIM UPDATE
• LCB At LWL = 0.72 m aft of amidship
• 70. LCG of total ship = 0.93 m aft of amidship
• 71. Displacement of the Ship = 74.68 tonne
At LWL,
• MCT1m = 141.16 tonne-m
• 72. C.F. = 1.08 m aft of amidship
• 73. Draft = 1.1 m
[The value of LCB,MCT1m,C.F. are taken from the Hydrostatic Calculations earlier in the design procedure]
• 74. TRIM UPDATE
Now,
Amount of Trim={(0.93-0.72)*74.68}/141.16
= 0.1111 m by stern
So,
Change in Trim aft= 0.05 m
Change in Trim Forward= 0.061 m
Therefore, resulting
Draft Forward= 1.1-0.061 = 1.039 m
Draft Aft= 1.1+0.05 = 1.15 m